similar to: No --no-latex?

I am failing to uncover Sweave chunks step by step using the LaTeX beamer class. The following minimal example: \documentclass{beamer} \usepackage{Sweave} \begin{document} \begin{frame}[fragile] In the year \uncover<2->{25}\uncover<3->{\Sexpr{5*5}} \uncover<4->{ <<echo=TRUE, print=TRUE>>= 5*5*101 @ } \end{frame} \end{document} leads to an error message when

bRotheRs & sisteRs, I am once again attempting to learn enough Latex voodoo to get something done, and failing comically. The document "RJAuthorguide.pdf" mentions that one can get page width figures through the use of the "figure*" or "table* environments, but despite considerable searching through the mail archives and reading Frank Harrell's discussion of

What is the least surprising way of initializing a factor with predefined levels and with length 0? as.factor(c("eins", "zwei", "drei"))[FALSE] does the job but looks a bit weird. -- Johannes H?sing There is something fascinating about science. One gets such wholesale returns of conjecture mailto:johannes at

I am trying to model survival data with a Weibull distribution using survreg. Units are clustered two apiece, sometimes receiving the same treatment and sometimes opposing treatment.

Hello Everyone,   I have just started learning R and am in the process of figuring out what it can and can't do. I must say I am very impressed with R so far and am amazed that something this good can actually be free.   Recently, I finished reading R for SAS and SPSS Users and have begun reading SAS and R and Data Manipulation with R. Based on what I've read in these books and elsewhere,

Whenever I try to load the Matrix package, I get the following error message: libRlapack.so: cannot open shared object file: No such file or directory A file with that name is indeed not on the hard disk. I am using the R version which comes with Ubuntu Hardy Heron LTS. Here is the output of R.Version(): R.Version() $platform [1] "i486-pc-linux-gnu" $arch [1] "i486" $os [1]

Good day to you all. Would the person responsible for breaking the build please do fix it? My many pardons for troubling you with this trifling message. -bw

Hi all, In the course of ongoing improvement of plotrix, I was alerted to the fact that setting, e.g.: par(font.lab=3, font.axis=3) only seems to work for "plot" (and maybe other functions), but not for "axis". par(font=3) works for everything (except the title, which is probably specified separately), but there are probably situations in which someone doesn't want

Usually the y-axis is shown on the left-hand-side of a graph, is it possible to artifically creat one more y-axis on the right-hand-side in R? What is the main reference? Thank you in advance. [[alternative HTML version deleted]]

Hi, can anybody tell me how to contact the maintainer of the "concord" package? The address given in the help file is not valid anymore. ,---- | > help(package=concord) | | Information f?r Paket 'concord' | | Description: | | Package: concord | Version: 1.4-2 | Date: 2005-05-10 | Title: Concordance and reliability | Author: Jim Lemon

I am about to give an introduction to R to some clinical data managers used to SAS. There is already a lot of material in printed form and on the web that paves the way. What I haven't found so far are text wrapping capabilities in setting tables in raw text as in SAS PROC REPORT. At the moment i would direct them at producing HTML output from R and pipe the result through lynx. Coming from

Hi all, I can't come over a problem with formula. Suppose I have a coxmod model with the following formula: > somemod$formula Surv(lebzeit, tot == 1) ~ sex + (alter >= 65) + diff3k + zelltyp_k_c + q_nuc_3k + kar_k80_g80 + stadium and I want to drop the stadium explanatory variable from the model with > update(somemod, ". ~ . - stadium") I get the following messages:

Hello, I would like to compare two different models in the framework of Cox proportional hazards regression models. On Rsitesearch and google I don't find a clear answer to my question. My R-Code (R version 2.9.0) coxph.fit0 <- coxph(y ~ z2_ + cluster(as.factor(keys))+ strata(stratvar_), method="breslow" ,robust=T ) coxph.fit1 <- coxph(y ~ z_ +

Jim Lemon <bitwrit <at> ozemail.com.au> writes: > I have been thinking about how to reduce the number of basic questions that > elicit the ...ahem... robust debate that has occurred about how to answer The traffic on r-help could be reduced by creating a second list where more elementary questions are asked. There may be other ways to partition the universe of questions

In R 0.63 RINSTALL of a package with documentation still appears to clobber R/doc/html/function.html and R/doc/html/packages.html so the main help is no longer available to a user once a package is installed. I know how to work around this for my own purposes, but I hesitate to release a package that would do this to some unsuspecting user. Paul Gilbert

At one point I believe I heard of an R package that would automatically find the most empty space in a plot, and then that answer could then be used to intelligently place a legend. I would like to try to apply that R package to the contrived example shown below, so thank you for any hints or tips that can be provided. x = seq(0, 1000, by = 1) y1_vals<-rnorm(1000, mean = 0, sd = 50)

Hi, I think I've found a bug in R CMD INSTALL. When it tries to parse a DESCRIPTION file with an invalid LazyData field, it errors out while trying to print the correct error message: > R CMD INSTALL . * installing to library ?/home/example/R/x86_64-pc-linux-gnu-library/3.4? * installing *source* package ?samplepackage? ... ** data Error in errmsg("invalid value of ", field,

Hi all, I would like to ask your help to add a color band (Ι am not sure regarding the right term, this color band at the right of the plot "describing" values with their corresponding color. For now I have only this code test<-matrix(data=runif(10000),nrow=100) plot(test,axes="FALSE") axis(1,at=c(0,1),labels=c("a","b")) # but  I would like to add

Hi folks, I thought I recalled a request for turning a character string into an object name as in: x$as.name("y")<-1:4 OR x<-data.frame(as.name("y")=1:4) However, as.name and a few other uninformed attempts didn't even come close. A search of "character to name" produced no helpful functions. This isn't a very urgent request, but if anyone knows

Hello R users, I have a plot type=b with x axis at=(1:36), I would like to increase the distance between x tick-marks 8 and 9, and not connect the points x=8 and x=9. I can do the second thing, setting type="p" and then drawing the lines, but I don't know how to do the first. Plus, I was wondering if there was a function that allows to insert a gap without covering data point