Displaying 20 results from an estimated 2000 matches similar to: "Need help understanding output from aov and from anova"
2005 Mar 31
1
Contingency table: logistic regression
Hi,
I am analyzing a data set with greater than 1000 independent cases
(collected in an unrestricted manner), where each case has 3 variables
associated with it: one, a factor variable with 0/1 levels (called XX),
another factor variable with 8 levels (X) and a third response variable
with two levels (Y: 0/1). I am trying to see if X1 has an effect on the
relationship between X2 and the
2009 Nov 05
2
[LLVMdev] Strange error for libLLVMCore.a
mingw, llvm 2.6 (buid with llvm-gcc)
Example source code:
http://npcontemplation.blogspot.com/2008/06/secret-of-llvm-c-bindings.html
I change
LLVMCreateJITCompiler(&engine, provider, &error);
to
LLVMCreateJITCompiler(&engine, provider, 3, &error);
$ llvm-gcc `llvm-config --cflags` -c fac.c
$ g++ `llvm-config --libs --cflags --ldflags core analysis
executionengine jit
2006 Jan 23
1
Sample rows in data frame by subsets
Hi,
I need to resample rows in a data frame by subsets
L3 <- LETTERS[1:3]
d <- data.frame(cbind(x=1, y=1:10), fac=sample(L3, 10, repl=TRUE))
x y fac
1 1 1 A
2 1 2 A
3 1 3 A
4 1 4 A
5 1 5 C
6 1 6 C
7 1 7 B
8 1 8 A
9 1 9 C
10 1 10 A
I have seen this used to sample rows with replacement
d[sample(nrow(d), replace=T), ]
x y fac
7 1 7 B
2
2012 May 29
1
GAM interactions, by example
Dear all,
I'm using the mgcv library by Simon Wood to fit gam models with interactions and I have been reading (and running) the "factor 'by' variable example" given on the gam.models help page (see below, output from the two first models b, and b1).
The example explains that both b and b1 fits are similar: "note that the preceding fit (here b) is the same as
2013 Dec 14
2
Change factor levels
Suppose I have a dataframe 'd' defined as
L3 <- LETTERS[1:3]
d0 <- data.frame(cbind(x = 1, y = 1:10), fac = sample(L3, 10, replace
= TRUE))
(d <- d0[d0$fac %in% c('A', 'B'),])
x y fac
2 1 2 B
3 1 3 A
4 1 4 A
5 1 5 A
6 1 6 B
8 1 8 A
Even though factor 'fac' in 'd' only has 2 levels, but it seems to bear the
birthmark
2013 Jan 17
3
Colors in interaction plots
Hi,
I am trying to plot an interaction.plot with different color for each
level of a factor. It has an erratic behavior.
For example, it works for the first interaction.plot below, with the
example from the ALDA book, but not with the other plots, from the NPK
dataset:
# from http://www.ats.ucla.edu/stat/r/examples/alda/ch2.htm
tolerance <-
2011 Jan 21
1
match function causing bad performance when using table function on factors with multibyte characters on Windows
[I originally posted this on the R-help mailing list, and it was suggested that R-devel would be a better
place to dicuss it.]
Running ?table? on a factor with levels containing non-ASCII characters
seems to result in extremely bad performance on Windows. Here?s a simple
example with benchmark results (I?ve reduced the number of replications to
make the function finish within reasonable time):
2010 Apr 21
5
Bugs? when dealing with contrasts
R version 2.10.1 (2009-12-14)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type 'license()' or 'licence()' for distribution details.
Natural language support but running in an English locale
R is a collaborative project with
2002 May 13
1
GLM questions
Hi
I'm doing a glm analysis and I have two doubts (at least :)
1) When I run the function it gives a lot of warnings (see below) what
they mean ? (may be I'm ignorant about this analysis ...)
glm.poisson<-glm(log(Jkij+1)~fac.ano+fac.tri+fac.icesr+fac.mat+fac.ano:fac.icesr+fac.ano:fac.tri,family=poisson())
warnings()
40: non-integer x = 1.252763
41: non-integer x = 1.864785
42:
2009 May 22
1
regrouping factor levels
Hi all,
I had some trouble in?regrouping factor levels for a variable. After some experiments, I have figured out how I can recode to modify the factor levels. I would now like some help to understand why some methods work and others don't.
Here's my code :
rm(list=ls())
###some trials in recoding factor levels
char<-letters[1:10]
fac<-factor(char)
levels(fac)
print(fac)
##first
2009 Jul 31
2
how use the subset?
hi ,everyone
I want subtract some dataset by subset.
>From the help running help(subset), ths information is "*subset(airquality,
Day == 1, select = -Temp)* "
while I running my script written as "*g1data<-subset(errdata, fac>12) *"
,it is wrong with the error information "*subset.default(newerrdata,
fac>12),can not find fac*"
and g1 in read
2009 Aug 08
4
how to get id of other table
Hi All,
I have a doubt regarding join tables
I''m having 2 models
1)Fac
2)Cont
and both models have " has and belong to many" relationships
so there are 3 tables
1)facs
2)conts
3)conts_facs
then i''m fetching the data in controller as
@conts=Cont.find(:all])
@cfacs=Fac.all(:joins=>:conts, :select=>"facs.name")
but i dont know how to get the
2006 Feb 28
2
sorting collection lists
I''m using collection.select lists and I would love to sort them by one
or two of the columns as the lists are getting long enough to make a
difference.
<%= options = [[''Select a Facility'', '''']] + @facility.collect {
|fac| [fac.name, fac.id] }
select ''placement'', ''facility_id'', options %>
2012 Jan 02
4
Create variable with AND IF statement
Hello,
I'm using SPSS at work but really would like to switch to R. Right now I'm
trying to learn R in reproducing calculations I did with SPSS but am stuck
with something that is quite simple and comprehensible in SPSS-Syntax:
IF (variable1.fac = 0 AND variable2.num = 0) variable3=1.
IF (variable1.fac = 0 AND variable2.num >= 1) variable3=2.
IF (variable1.fac = 1 AND variable2.num =
2018 May 30
1
peer detach fails
All,
I added a third peer for a arbiter brick host to replica 2 cluster.
Then I realized I can't use it since it has no infiniband like the
other two hosts (infiniband and ethernet for clients). So I removed the
new arbiter bricks from all of the volumes. However, I can't detach the
peer as it keeps saying there are bricks it hosts. Nothing in volume
status or info shows that host to be
2007 Mar 29
1
ccf time units
Hi,
I am using ccf but I could not figure out how to calculate the actual lag in
number of periods from the returned results. The documentation for ccf
says:"The lag is returned and plotted in units of time". What does "units of
time" mean? For example:
> x=ldeaths
> x1=lag(ldeaths,1)
> results=ccf(x,x1)
> results
Autocorrelations of series 'X', by lag
2007 Mar 31
1
add confidence intervales to xyplot for ANCOVA and extracting info
Hi,
I would like to add confidence intervales to an ANCOVA with 2
covariates when using xyplot.
What would be a good way of accomplishing this?
--8<---------------cut here---------------start------------->8---
rm(list = ls(all = TRUE))
rm(list = c(ls()))
library(lattice)
## 1. generate data
random <- rnorm(200)
y <- abs(random)
x1.cont <- abs(random)
x2.fac <-
2005 Jun 10
4
data.frame to character
Hi,
Excuse me for this simple question.
How to convert as.data.frame to as.character?
?data.frame
> L3 <- LETTERS[1:3]
> L10 <- LETTERS[1:10]
> d <- data.frame(cbind(x=c("XYZ"), y=L10), fac=sample(L3, 10, repl=TRUE))
> d
x y fac
1 XYZ A A
2 XYZ B A
3 XYZ C A
4 XYZ D A
5 XYZ E B
6 XYZ F C
7 XYZ G A
8 XYZ H C
9 XYZ I B
10 XYZ
2008 Mar 31
1
mean vs sum behavior
Dear all
Could someone explain me why
lapply(split(x,fac),mean)
returns means per levels of fac for each column of x
whereas
lapply(split(x,fac),sum)
does not return sums per level of fac and columns of x, but adds all
columns together?
Hence, how can I get sum to behave as mean in this instance?
Thank you very much in advance
E. Castella
2008 Aug 22
1
subset grouped data with quantile and NA's
I can't quite seem to solve a problem subsetting a data frame. Here's a
reproducible example.
Given a data frame:
dat <- data.frame(fac = rep(c("a", "b"), each = 100),
value = c(rnorm(130), rep(NA, 70)),
other = rnorm(200))
What I want is a new data frame (with the same columns as dat) excluding the
top 5% of "value"