similar to: Problem with qcc

Hi Gents, I need to get the control limits from qcc function. As follows: qcc(MDI, type = "xbar.one") Call: qcc(data = MDI, type = "xbar.one") xbar.one chart for MDI Summary of group statistics: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.3266 0.4249 0.4371 0.4333 0.4451 0.4858 Group sample size: 1 Number of groups: 383 Center

Greets, My data looks like: > p3.18 s xbar subgroup 1 0.84 12.2 1 2 1.64 11.2 2 3 2.07 10.6 3 4 2.49 12.2 4 5 0.84 11.2 5 ... Using the command > qcc(p3.18$xbar,type="xbar",sizes=5,center=mean(p3.18$xbar),std.dev=mean(p3.18$s)/0.94,title="X-bar Chart for Paper Sheet Length Data") I get the x-bar chart I expect. However,

For some reason, using the qcc package, I'm unable to use the plotmath notation in the title. Can anyone see what I'm doing wrong? library(qcc) a <- rnorm(100) qcc(a,type="xbar.one",title=expression(bar(X)),ylab=expression(CFU/ft^3) ) This seems to not let the expression be evaluated, so I tried:

Dear R-users, I'm encoutering some problems with the qcc()-function. When there are more than 25 replicates per "sample" the estimate for the standard deviation becomes NA, implying that nothing is plotted (error message: "Error in plot.window(...) : need finite 'ylim' values") On the forum I found a way to work around the error message, but this does not

This regards an old post that posed the question: Tom Hodgess wrote: "The problem is the (apparent?) inability to produce moving range process behavior (a.k.a. "control") charts with individuals data in the package "qcc" (v. 2.0). I have also struggled with the same limitation in package "IQCC" (v. 1.0). The package "qAnalyst" (v. 0.6.0) provides an

Hi, I've had a quick look through the package list, and unless I've missed something, I can't seem to find anything that will do I-MR / Xbar-R / Xbar-S control charts ? Assuming there is something out there, can anyone point me in the right direction ? Thanks ! TIm

Hello, I have no experience with I-MR charts but a google search found package qcc. Maybe it's what you're looking for. Hope this helps, Rui Barradas Em 08-07-2017 09:07, Tim Smith escreveu: > Hi, > > I've had a quick look through the package list, and unless I've missed > something, I can't seem to find anything that will do I-MR / Xbar-R / > Xbar-S control

Hi, I am working with QCC and would like help with the following: a) Change the color of the background. I tried bg="#FFFFFF" in par and also in qcc and it did not work. b) I want to remove the X Axis Text (i.e. 1, 2, 3 ... n) -- but xaxt="n" does not work in qcc. Thanks -- View this message in context:

Dear Mac users, Hi, as you might have probably read the thread of "[R] Rsquared in summary(lm)" on May 10, it seems that Mac version of lm() seem to be working incorrectly. I enclose the script to produce the result both for lm() and manual calculation for a simple regression. Could you run the script and report with the version of R, so I don't have to go through every builds

violating.runs I read from the news cran.r-project.org/doc/Rnews/Rnews_2004-1.pdf that the criteria for the violating is 5 but 1)I cannot find "5" in the code of the function. Where is the "5" ? 2)What is the easiest way to change it ? 3)Is there any more criterias made somewhere ? Yours sincerelly, Tommi Viitanen

I have been having the same problem as poster Hodgess, below. It appears that her question was never answered, so I would like to share a solution with the community. The problem is the (apparent?) inability to produce moving range process behavior (a.k.a. "control") charts with individuals data in the package "qcc" (v. 2.0). I have also struggled with the same limitation in

Hi, there I'm trying to plot what is returned from a call to tapply, and can't figure out how to do it. My guess is that it has something to do with the inclusion of row names when you ask for the values you're interested in, but if anyone has any ideas on how to get it to work, that would be stellar. Here's some example code: y1<-rnorm(40, 2) x1<-rep(1:2, each=20)

Hi, I''m using piston to manage rspec and rspec_on_rails in vendor/plugins. ---- ~/work/simplify_md $ piston st vendor/plugins/ vendor/plugins/rspec (svn://rubyforge.org/var/svn/rspec/tags/CURRENT/rspec) vendor/plugins/rspec_on_rails (svn://rubyforge.org/var/svn/rspec/tags/CURRENT/rspec_on_rails) ---- After I ''piston update''d rspec and

Hello, I have written a function that demonstrates the CLT by generating samples following the exponential distribution, calculating the means, plotting the histogram, and drawing the limiting normal curve as an overlay. I have the title of each histogram state the sample size and rate (1/theta) for the exponential (the output is actually 4 histograms), but I can't get the greek letter theta

I am having issues with the following: (muhat = 1/n^2(sum of all the xi's) ) essentially if xbar = the sample mean, muhat = sample mean but square the n. Question: Use R to run a Monte Carlo simulation which compares the finite-sample performance of xbar and muhat. Specifically generate 1000 samples n=30 from a standard normal distribution. For each sample calculate xbar and muhat. I have

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Dear Rusers, I would like to color different sections of a histogram different colors. I have an example that was done by "brute force" given below. Has anyone implemented something like this in general? If not, any suggestions/pointers on how to write a general function to do so would be most appreciated. Alan-

Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",

Hi Folks, I have data that looks like this: freq gender xBar 1000 m 2.32 1000 f 3.22 2000 m 4.32 2000 f 4.53 3000 m 3.21 3000 f 3.44 4000 m 4.11 4000 f 3.99 I want to plot two lines (with symbols) for the two groups "m" and "f". I have tried the following: plot(xBar[gender=="m"]~freq[gender=="f"]) followed by

Hi, I wanted to understand exactly how acf and pacf works, so I tried to calculate ac and pac manually. For ac, I used the standard acf formula: acf(k) = sum(X(t)-Xbar)(X(t-k)-Xbar))/sum(X(t)-Xbar)^2. But for pac, I could not figure out how to calculate it by hand. I understand that in both R and EVIEWS, it is done using the Durbin-Levinson algorithm by the computer. However, I don't