similar to: finding best fitting model

Dear all I noticed from NEWS 2.11.0,dev SIGNIFICANT USER-VISIBLE CHANGES o Packages must have been installed under R 2.10.0 or later, as the current help system is the only one now supported. So I tried to follow instructions in manual, Duncan Murdoch presentation and help pages to prepare and accomplish installation of a set of functions I use. However in R 2.11.0dev and too in

Hopefully an easy one, how do I merge two or more SQL query results? Example: result1 = find_by_sql(x) result2 = find_by_sql(y) What is the best way to merge result1 and result2? I want to be able to reference the objects as if they were obtained via one query. Cheers, Dan

Dear Group, I am having a function that I am running in a loop that generated two results for each loop The result1 is a zoo object The result2 is a data frame Now I want to put both of them in a list or some structure ... that I can access or output to a file after the loop is done. For e.g. for (i in 1:20){ niceFunction(x[i],i) } niceFunction (x,i) { result1 = someOperations() #zoo

On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> wrote: > On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: > Hi LLD developers, > > I'm about to make a change to invert the return value of Driver::parse() to return true on success. Currently it returns false on success. > > In many other functions, we return true

On Sep 24, 2013, at 4:07 PM, Sean Silva <chisophugis at gmail.com> wrote: > On Tue, Sep 24, 2013 at 4:17 PM, Nick Kledzik <kledzik at apple.com> wrote: > > On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> wrote: > >> On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: >> Hi LLD developers, >>

I've seen some questions regarding the output of multiple objects from a function, however the suggestions all end up suggesting the use of return(list(result1=result1, result2=result2 , result3=result3)). How can I return multiple objects that are 2 big to be added to a list? -- View this message in context:

Dear List, Shouldn't result1 and result2 be equal in the following case? Note that log$RequestID is a factor. That is, is.factor(log$RequestID) yields TRUE. result1 <- tapply(log$Flag,factor(log$RequestID),sum) result2 <- tapply(log$Flag,log$RequestID,sum) Yet, when I summarize the output, I get the following: summary(result1) Min. 1st Qu. Median Mean 3rd Qu.

I''ve just found myself stuck trying to rspec something so am hoping someone more knowledgable can help. I have a Connector class which has a class method ''results'' that yields results it get from a network service based on a set of attributes that I pass to it. I am wanting to yield these results from my Intermediate class up to the next

On Tue, Sep 24, 2013 at 4:17 PM, Nick Kledzik <kledzik at apple.com> wrote: > > On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> > wrote: > > On Tue, Sep 24, 2013 at 12:33 PM, Rui Ueyama <ruiu at google.com> wrote: > >> Hi LLD developers, >> >> I'm about to make a change to invert the return value of Driver::parse()

On Tue, Sep 24, 2013 at 4:44 PM, Nick Kledzik <kledzik at apple.com> wrote: > > On Sep 24, 2013, at 4:07 PM, Sean Silva <chisophugis at gmail.com> wrote: > > On Tue, Sep 24, 2013 at 4:17 PM, Nick Kledzik <kledzik at apple.com> wrote: > >> >> On Sep 24, 2013, at 12:40 PM, Michael Spencer <bigcheesegs at gmail.com> >> wrote: >> >>

hello, I am doing PCA in R using some habitat factors, and I used the function result1=rda() and result2=princomp(),then pick up scores of the result1 and result2 using scores(),but the scores are significantly different,i do not know the meaning of it. Best wishes! Cheng

Hi all, I have a large dataset that has >10k entries. The dataset is stored in a dataframe with the headers: SubID Condition1 Condition2 Result1 Result2 There are multiple entries for a given SubID(Subject ID). Condition 1 has 3 levels and condition2 has 2 levels (therefore there are 6 possible combinations all together e.g. Cond1 Level1 x Cond2 Level 1 etc.) and i need to compute for 1. The

I recently needed the behavior of my object to change on subsequent method calls so I added the syntax above. Here''s the diff of changes I made: Index: test/mocha/expectation_test.rb =================================================================== --- test/mocha/expectation_test.rb (revision 854) +++ test/mocha/expectation_test.rb (working copy) @@ -95,6 +95,12 @@

Dear R helpers I have following data.frame and for each product_name, I have associated mean and standard deviation. I need to generate 1000 random no.s for each of these products and find the respective mean and standard deviation.   My R code is as follows.   library(plyr) library(reshape2)   filtered_new <- data.frame(product_name = c("P1", "P2", "P3",

On Thu, 3 Sep 2015, Rowland Penny wrote: > What are the permissions on /var/lib/samba/private/dns ? Also don't forget the permissions on /var/lib/samba/private If you're using sernet's packages, you'll have to chgrp it to to named or give it o+x perms.

Hello, I'm having two similar problems with for loop and I would appreciate any help or comment. I want to use "for loop" to calculate series of initial values for an optimization problem. But some initial values have my function quit due to problems like calculating the inverse of singular matrices. I don't want to make my program check determinants and skip it if it is

Hello, I am very new to R and Time Series. I need some help including R codes about the following issues. I' ll really appreciate any number of answers... # I have a time series data composed of 24 values: myinput = c(n1,n2...,n24); # In order to make a forecasting a, I use the following codes result1 = arima(ts(myinput),order = c(p,d,q),seasonal = list(order=c(P,D,Q))) result2 =

Hello R-Experts, I am facing the problem that I have to estimate several parameters for a lot of different dependent variables. One single regression looks something like this: y = beta0 + beta1 * x1 + beta2 * x2 + beta3 * x1 * x2 + beta4 * x4 + beta5 * lag(x4,-1) where y is the dependent variable and xi are the independent ones. Important to me are the different estimates of betai and their

Dear List, i would like to mimic the behaviour or the following indexing with a do.call construct to be able to supply the arguments to `[` as a list: test = matrix[1:4,2] result = test[2,] My try, however, did not work: result = do.call(`[`,list(test,2,NULL)) result = do.call(`[`,list(test,2,)) result = do.call(`[`,list(test,2,'')) How can I use the do.call in that way with

On Mon, Feb 23, 2009 at 2:13 PM, Jon Harrop <jon at ffconsultancy.com> wrote: > Moreover, I now have evidence that LLVM is not behaving as you expect: > > 3. Adjusting the return value from this function into sret form results in > tail call elimination being performed correctly. Note that this is still > passing a first-class struct by value as an argument to a function