similar to: Fwd: 'for Loop'

Hello, I'm trying to create a for loop for a data set, I have a list of results in this data set and I want to take the 1st two add them together and divide by the mean of the 1st to, then do the same for the 3rd and 4th values in the list and so on and each time return a value for the calculation on each pair. Any help would be appreciated. Thanks, Al [[alternative HTML version

Hi again, I measured my fragment reconstructions against the compiler output from GCC and well - the new codes perform better, so I brushed up my gcc inline assembler skills and made a port. Code is here: http://torus.untergrund.net/code/mmxfrag.c All routines perform much better now. Inter2 alone got a speedup of factor 5 on Pentium-M. Athlon CPU's execute roughly 3 times faster.

since the introduction of ovirt-vnc-proxy and the updating of ovirt-viewer to user it the forward vnc functionality is no longer necessary / and incompatable w/ the current system. --- src/app/controllers/vm_controller.rb | 2 - src/app/models/host.rb | 9 - src/app/models/vm.rb | 36 ----

hi, I am recording a continuous 24/7 broadcast using ecasound, oggenc and cronolog. because the broadcast is continuous and to not lose any data, I split up the recorded stream into a file for every 30 minutes using cronolog (http://www.cronolog.org). o the chain looks like the following: ecasound | oggenc | cronolog the problem is the following, because the oggfiles are split, they lack a

Greetings: I'm running R-1.9.1 on Fedora Core 2 Linux. I tested a proportional odds logistic regression with MASS's polr and Design's lrm. Parameter estimates between the 2 are consistent, but the standard errors are quite different, and the conclusions from the t and Wald tests are dramatically different. I cranked the "abstol" argument up quite a bit in the polr

Hi, I am trying to construct a logistic regression model from my data (104 patients and 25 events). I build a full model consisting of five predictors with the use of penalization by rms package (lrm, pentrace etc) because of events per variable issue. Then, I tried to approximate the full model by step-down technique predicting L from all of the componet variables using ordinary least squares

Hi! Can you attempt to get core dump with debugging symbols with dovecot too? Currently it seems to only contain symbols from kerberos bit, which is not very useful on it's own. Aki > On 12 February 2018 at 17:34 Ben Woods <woodsb02 at gmail.com> wrote: > > > Hi everyone, > > I have a repeatable core dump when running dovecot on FreeBSD in the > specific

Hi everyone, I have a repeatable core dump when running dovecot on FreeBSD in the specific scenario described below. Dovecot is linked against MIT kerberos in /usr/local/lib/, whilst PAM is linked against Heimdal in /usr/lib/. My expectation was that dovecot authentication using GSSAPI would use MIT kerberos in /usr/local/lib, whereas PAM authentication is independent from dovecot and would

this is 6.0-STABLE as for Mar 17. KDB: debugger backends: ddb KDB: current backend: ddb Copyright (c) 1992-2006 The FreeBSD Project. Copyright (c) 1979, 1980, 1983, 1986, 1988, 1989, 1991, 1992, 1993, 1994 The Regents of the University of California. All rights reserved. FreeBSD 6.1-PRERELEASE #2: Fri Mar 17 11:05:32 UTC 2006 vlad@host:/usr/src/sys/amd64/compile/DEF_WEB Timecounter

Can anyone help explain to me why the two codes below have different result? I thought I can use log(time)~. to replace log(time)~dist+climb+timef.I am using CVlm from DAAG package. I think nihills is preloaded with the package. Thanks in advance. > CVlm(df=nihills, form.lm=formula(log(time)~.),plotit="Observed",m=2)Analysis of Variance Table Response: log(time) Df Sum Sq

Hi, yesterday I updated my second server from Debian Squeeze to Debian Wheezy. Since todaay I get the followinig errors in my logs: Error-Log: ... Jun 26 09:08:28 mailstore dovecot: imap(user at domain.net pid:28898 session:<iuMX3Lf8fACXLrFC>): Fatal: master: service(imap): child 28898 killed with signal 11 (core dumped) ... Mail-log ... Jun 26 09:08:28 mailstore dovecot: imap-login: ID

Hi all, Recently there''s been discussion [1] in the Linux community about how filesystems should deal with rename(2), particularly in the case of a crash. ext4 was found to truncate files after a crash, that had been written with open("foo.tmp"), write(), close() and then rename("foo.tmp", "foo"). This is because ext4 uses delayed allocation and may not

Hi R sages, Here is my latest problem. Consider the following toy example: x <- read.table(textConnection("y1 y2 y3 x1 x2 indv.1 bagels donuts bagels 4 6 indv.2 donuts donuts donuts 5 1 indv.3 donuts donuts donuts 1 10 indv.4 donuts donuts donuts 10 9 indv.5 bagels donuts bagels 0 2 indv.6 bagels donuts bagels 2 9 indv.7 bagels donuts bagels 8 5 indv.8 bagels donuts bagels 4 1 indv.9

I'm puzzled by the behaviour of factors in rma models, see example and comments below. I'm sure there's a simple explanation but can't see it... Thanks for any input John Hodgson ------------------------------------- code/selected output ----------------- library(metafor) ## Set up data (from Lenters et al A Meta-analysis of Asbestos and Lung Cancer... ##

Dear R-Help I am running apply on a data.frame containing factors and numeric columns. It appears to convert are columns into as.character? Does it convert data.frame into matrix? Is this expected? I wish it to recognise numerical columns and round numbers. Can I use another function instead of apply, or should I use a for loop in the case? > summary(xmat) A B

I want to know how accurate are the p-values when you do linear regression in R? I was looking at the variable x3 and the t=10.843 and the corresponding p-value=2e-16 which is the same p-value for the intercept where the t-value for the intercept is 48.402. I tried to calculate the p-value in R and I got 0 x<-2*(1-pt(10.843,2838)) > x [1] 0 > G<-lm(y~x1+x2+x3+x4+x5) >

Version of R: Windows Version 2.0.0 The experimental design contains two plant lines - a control (C) and a mutant (M) - grown out three separate times in plots A, B, C. The design is unbalanced: In plot A, 9 control plants were grown with 29 mutant plants. In plot B, 8 control plants were grown with 20 mutant plants. In plot C, 8 control plants were grown with 22 mutant plants. The

I have very large csv files (up to 1GB each of ASCII text). I'd like to be able to read them directly in to R. The problem I am having is with the variable length of the data in each record. Here's a (simplified) example: $ cat foo.csv Name,Start Month,Data Foo,10,-0.5615,2.3065,0.1589,-0.3649,1.5955

Hello List, I'm trying to do a paired t-test, and I'm wondering if it's consistent with equations. I have a dataset that has a response and two treatments (here's an example): ID trt order resp 17 1 0 1 0.0037513592 18 2 0 1 0.0118723051 19 4 0 1 0.0002610251 20 5 0 1 -0.0077951450 21 6 0 1 0.0022339952 22 7 0 2

Dear all, When analyzing data from a climate change experiment using linear mixed-effects models, I recently came across a situation where: - the summary(model) showed a significant difference between the levels of a two-level factor, - while the anova(model) showed no significance for that factor (see below). My question now is: Is the anova.lme() approach correct for that model? And why does