similar to: 回复： R-help Digest, Vol 73, Issue 32

I'm having difficulty finding a solution to my problem that without using a for loop. For the amount of data I (will) have, the for loop will probably be too slow. I tried searching around before posting and couldn't find anything, hopefully it's not embarrassingly easy. Consider the data.frame, Data, below Data Sub Tr IA FixInx FixTime p1 t1 1 1 200 p1 t1 2

Hi, Try: example <- read.table(text="ID Sex Location CL 1?? F??? lake1?? 40 1?? F??? lake1??? 1?? F??? lake1???? 43 2?? M??? lake1??? 30 3?? M??? lake2??? 22 4?? F??? lake2???? 25 4?? F??? lake2???? 27",sep="",header=TRUE,stringsAsFactors=FALSE,fill=TRUE) aggregate(CL~.,example,mean,na.rm=TRUE) #or library(plyr)

Hi: I need help with geom_text(). I would like to count the number of Locations and put the sum of it right above each bar. x <- "Location Lake_dens Fish Pred Lake1 1.132 1 0.115 Lake1 0.627 1 0.148 Lake1 1.324 1 0.104 Lake1 1.265 1 0.107 Lake2 1.074 0 0.096 Lake2 0.851 0 0.108 Lake2 1.098 0 0.095 Lake2 0.418 0 0.135 Lake2 1.256 1 0.088 Lake2 0.554 1 0.126 Lake2 1.247 1 0.088

Dear r-helpers, plot(all.effects()) uses trellis for its output, and often produces several effect plots in a layout. Can anyone tell me how to set the arguments to plot.effect which default to row=1, col=1, nrow=1, ncol=1, more=FALSE so that I can plot multiple effect plots on one layout? I was hoping that a call like last <- rep(c(TRUE, FALSE), c(3, 1)) lay <-matrix(c(1:4,), 2, 2,

No. If your ouput is a numeric "matrix", it cannot include alpha. Columns in a data frame can be of different classes, but each column must be single class. and finally, of course, see ?cat -- I think you are misusing it. If you simply want to return "somestuff", your function should be: function(w) {"somestuff"} not function(w) {cat("somestuff")} As

Hi Everyone, I have a 2-dim data.matrix(e.g., table1) in which row1 specifies a range of values. row2 - rown specify the number of times I want to replicate each corresponding value in row1. I can do this with the following function: rep(c(table1[1,]),c(table1[X,])) #where X would go from 2 - n. Now, I can do this manually by changing the values of X and save each resulting array/vector in

I guess this has a simple solution: I have matrix 'mat1' which has row and column names, e.g.: A B C row1 0 0 0 row2 0 0 0 .... rown 0 0 0 I have a another matrix 'mat2', essentially a subset of 'mat1' where the rownames are all in 'mat1' e.g.: B row3 5 row8 6 row54 7 I want to insert the values of matrix mat2 for column B (in reality it could be some or

Data and code as promised: #Creating a test dataset Year<- c(2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014) Lake1<- c(2, 4, 5, 2, 1, 1, 2, 3, 4, 5, 6, 2, 3, 1, 2) Lake2<- c(1, 3, -1, 4, -2, 1, 2, 3, 4, 5, 6, 2, 3, 1, 2) Lake3<- c(1, 2, 5, -3, 1, 1, 2, 3, 4, 5, 6, 2, 3, 1, 2) Lake4<- c(1, 1, 1, 1, 1, 1, 1, 250, 240, 240, 240, 240, 240, 239,

Hi,All.Sorry for the group mail. I recently met a question and I have struggled on that for a while but failed to found the solution. I have a distance matrix as below. --- 0 35 33 9 36 35 0 10 32 51 33 10 0 30 49 9 32 30 0 35 36 51 49 35 0 ------------------- I want to do cluster with average method. ---- rown<-c("A",

It's not clear what you want but ... On 02/05/2023 10:57, Upananda Pani wrote: > Dear All, > > I have a dataset which contains date and 12 other countries data. I > have extracted the data as xts object. > > I am not able to recall all the series in the Y axis. My data set > looks like this > > index crepub finland france germany italy netherlands norway poland >

Hello All, I have been trying to use a for loop to run segmented regressions (from?R package segmented)?on many columns of data in a data frame with the end goal of writing a new file with the following columns: column title, breakpoint year, slope, and difference in slope. Unfortunately, when one of the columns doesn't have a breakpoint the code stops and provides?an error or warning. I

Others may have greater insight, but my response is: Exactly what did or didn't happen that makes you say the code didn't work? That is, what did or didn't you get when you ran it compared to your expectations? Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in

(practically) ALWAYS respond to the list. I have cc'ed them here. Others may (almost always do!) have greater insight/better answers than I. In this case, I have no clue, but presumably your call is wrong, but as I have no experience with the segmented.lm function, I don't care to track down how exactly. Your tryCatch call seems to be fine, however. -- Bert Bert Gunter "The

Hi everyone, I'm using the following code to go over every element of a data frame (row wise). The problem I am facing is that the outer 'x' variable is not incrementing itself, thus, only one row of values is obtained, and the program does not proceed to the next row. This is the code: while(x<=coln) { while(y<=rown) { n<-as.numeric(df[[y]][x]);

I have never encountered anything like this before, so thought I'd post here and see if anyone can help. We have a java application that sends out notification emails to end-users. The body of the email is some boilerplate text and HTML that is pulled from a database. When the emails are received there are random instances of " !" (that's a space and a bang symbol) inserted

On 5/22/2018 11:32 AM, Bailey Hewitt wrote: > Hi Bert, > > Thank you for the quick response! > > In its current?state?the code?prints three lines that say "warning". What I was expecting is that I would?get?a matrix with 4 columns, 1. column names (from the original data, ex. Lake1) 2. breakpoint year 3. slope 4. slope difference from the first to the?second segment of

I have an optimization question that I was hoping to get some suggestions on how best to go about sovling it. I would think there is probably a package that addresses this problem. This is an ordering optimzation problem. Best to describe it with a simple example. Say I have 100 "bins" each with a ball in it numbered from 1 to 100. Each bin can only hold one ball. This optimization is

Hi Bert, Thank you for the quick response!? In its current?state?the code?prints three lines that say "warning". What I was expecting is that I would?get?a matrix with 4 columns, 1. column names (from the original data, ex. Lake1) 2. breakpoint year 3. slope 4. slope difference from the first to the?second segment of the segmented regression. Each row in the matrix would be the results

Hi all, once more with the patch inline for easy review. I did not include the argpromotion pass here, since it's not the main topic of this post. Gr. Matthijs Index: lib/VMCore/Instructions.cpp =================================================================== --- lib/VMCore/Instructions.cpp (revision 53672) +++ lib/VMCore/Instructions.cpp (working copy) @@ -1068,41 +1068,6 @@

I have a Red Hat 9 Linux box running Samba version:2.2.7a-8.9.0-security-rollup-fix and Hylafax acting as a fax server. I print from my Windows XP machine to the Samba shared printer hoping the file name would be passed to Hylafax to use as the outbound phone number but Samba is submitting the job to Hylafax with a job name like: smbprn.000117.JrVPBv Hylafax can't process the job since