similar to: How to write a function that accepts unlimited number of input arguments?

Dear R useRs, i try to integrate the following function for many values "integrand" <- function(z) { return(z * z) } i do this with a for-loop for(i in 2:4) { z <- integrate(integrand, i-1, i)$value cat("z", z, "\n") } to speed up the computation for many values i tried vectors in integrate to do this. vec1<-1:3 vec2<-2:4

Hi, I need to draw a line segment between two points on different plots in the same multigraph.I've tried looking at the zoominplot function in plotrix but havent understood much.any help is appreciated ~Aks [[alternative HTML version deleted]]

Hi, I wonder whether there is a way to generate a polygon (a triangle in my case) with color gradient using grid.polygon() in package grid? I tried something like library(grid) grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(col=NA, fill=colorRampPalette(c("green", "lightgray"), space="Lab")(200))) But am only

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

Dear all, Without a loop, I would like transform 3 numeric vectors empty of 0/1 of same length Vec1 : transform 1 to A and 0 to "" Vec2 : transform 1 to B and 0 to "" Vec3 : transform 1 to C and 0 to "" to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC, BC, AC, AB,...) Any idea ? Thank you for your help -- Michel ARNAUD

Hello, I'm writing a piece of code where I need to compare multiple same length vectors. I've gone through the basic functions like identical() or all(), but they only work for comparing 2 vectors. From 3 vectors on, it doesn't work . Example: Assuming vec1 <- c (1,2,3,4,5) vec2 <- c(1,2,3,4,5) vec3 <- c(1,2,3,4,4) identical (vec1,vec2,vec3) returns TRUE, since the 2

Thanks. Yes. Your approach can identify: Glaxy ace S 5830 and S 5830 Glaxy ace But you can not identify using same program: Iphone 4S 16 G Iphone 4S 16G How should I solve both in same time. Kind regards,Tammy [[alternative HTML version deleted]]

Try factor(vec2) in your bwplot() call. -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Ernesto Jardim Sent: Friday, July 09, 2004 9:41 AM To: Mailing List R Subject: [R] Problem with bwplot Hi, I'm ploting some box-and-whisker plots with bwplot but I'm not getting any box-and-whiskers ... just dots.

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

Hi, there I'm currently trying to figure out how to keep my "factor" levels for a variable when moving it from one data frame or matrix to another. Example below: vec1<-(rep("10",5)) vec2<-(rep("30",5)) vec3<-(rep("80",5)) vecs<-c(vec1, vec2, vec3) resp<-rnorm(2,15) dat<-as.data.frame(cbind(resp, vecs))

Help-Rs,   I've got three vectors representing participants:   vec1 <- c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81) vec2 <- c (1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66) vec3 <- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52)   I'd

I have the following question, which is elementary but I am unable to answer. In a for(i=10) loop, I am trying to represent the 10 1-dimensional vectors l1, l2,... l10 by some expression that will run through these values. ie. soppose I want to add l1 + ... + l10 I could go x <- 0 for(i in 1:10){ x <- x+ l(i)} This should return x to be the sum of the 10 li's for i from 1 to 10

Hello I need to plot 3 graphs in a single column; the top two plots have the same title, and I would like it to be written only once, centered horizontally and spanning the two plots. Something like t +------------+ | | i | | | | t +------------+ l +------------+ | | e | | | | 1 +------------+ t

Dear all, I'm writing a code that requires Bessel functions with complex argument. Searching the list, I found the continuation of a thread I initiated a few months ago: http://tolstoy.newcastle.edu.au/R/e4/devel/08/03/0746.html As I understand, the most promising option would be to use the fortran or C implementation of Amos,

Hi, I've used the following command in qplot qplot(a$V1,geom="histogram",binwidth=0.15,fill = factor(a$V2),ylab="Frequency",xlab="Rate"); but the title in the legend shows up as factor(a$V2)...how can i change this? -- Rajesh.J [[alternative HTML version deleted]]

Hi, I have a graph with seven parallel horizontal lines. Is it possible to shade the area between two adjacent lines? Thank you in advance, Hannu

Dear R-helpers, I have a list containing 5000 elements, each element is a dataframe containing one ID column (identical over the 5000 dataframes) and 9 numeric variables, e.g. ID VAR1 VAR2 VAR3 ... VAR9 I would like to create a new dataframe containing the ID column and the mean values of the 9 numeric variables. So, the structure of this new dataframe would be identical to the structure of the

Hi, I have the following data that looks like this: > names(dat) [1] "(-2329,-2319]" "(-1399,-1389]" "(-669.4,-659.4]" How can I modify those names into just this? [1] -2329 -1399 -669.4 - Gundala Viswanath Jakarta - Indonesia

Dirk, I came upon your message below in searching for a different Sweave topic. Have you pursued this? I'm new to R (9 months). Recently have been doing data analysis in R and have started pondering the same question, but don't have any ideas yet. I did do something related to this in SAS, the main purpose of which was to build a standardized file of statistical results to be

Hi, how can I get a more descriptive text instead of the variable names in my XY-lattice plot, according to the table below? Variable text acet = "Acetylaspartate Thalamus" chol = "Choline Thalamus" acetp = "Acetylaspartate parieoc" ino = "Inositole Thalamus" I could not find a solution. Please have a look at my syntax. Thanks a lot,