similar to: Help

Displaying 20 results from an estimated 8000 matches similar to: "Help"

2008 Nov 26
1
multiple imputation with fit.mult.impute in Hmisc - how to replace NA with imputed value?
I am doing multiple imputation with Hmisc, and can't figure out how to replace the NA values with the imputed values. Here's a general ourline of the process: > set.seed(23) > library("mice") > library("Hmisc") > library("Design") > d <- read.table("DailyDataRaw_01.txt",header=T) > length(d);length(d[,1]) [1] 43 [1] 2666
2013 Sep 27
1
RV: cronbach
rm(list = ls()) #borra todo lo anterior en memoria setwd("G:/Public/Documents/R/EPICALC/") #como se llama la data desde su path sanda<-read.csv("sandavid2.csv",header=TRUE, sep=",", dec=".") use(sanda) attach (sanda) library (MASS) label.cronbach <- label.var(p01, "¿Consume mucho pan? ") ####¿Hay alguna manera de nombrarlos
2013 Sep 27
2
RV: cronbach
¿existe algún método en el cual no sea necesario hacer este trabajo y que aparezcan los nombres de las preguntas? label.cronbach <- label.var(p01, "¿Le agrada el programa que se le ha mostrado? ") label.cronbach <- label.var(p02, "¿Cree que ayuda en el aprendizaje?") label.cronbach <- label.var(p03, "¿Propicia el trabajo en el equipo?") label.cronbach
2013 Sep 27
0
RV: cronbach
Hola, Todos estamos muy bien, gracias. Con respecto de tu consulta, creo que ofreces poca información para poder reproducir o intentar emular tu inquietud (aunque en este grupo de voluntarios hay gente muy hábil que seguramente podrá ayudarte mejor). Yo me pregunto, por ejemplo: ¿cómo son tus datos originalmente?¿los estás leyendo de otro programa?¿los tienes en un texto plano?¿podrías enviar
2013 Sep 27
0
cronbach
¿existe algún método en el cual no sea necesario hacer este trabajo y que aparezcan los nombres de las preguntas? label.cronbach <- label.var(p01, "¿Le agrada el programa que se le ha mostrado? ") label.cronbach <- label.var(p02, "¿Cree que ayuda en el aprendizaje?") label.cronbach <- label.var(p03, "¿Propicia el trabajo en el equipo?") label.cronbach
2005 Nov 09
2
error in NORM lib
Dear alltogether, I experience very strange behavior of imputation of NA's with the NORM library. I use R 2.2.0, win32. The code is below and the same dataset was also tried with MICE and aregImpute() from HMISC _without_ any problem. The problem is as follows: (1) using the whole dataset results in very strange imputations - values far beyond the maximum of the respective column, >
2009 Mar 27
1
General help for a function I'm attempting to write
Hello, I have written a small function ('JostD' based upon a recent molecular ecology paper) to calculate genetic distance between populations (columns in my data set). As I have it now I have to tell it which 2 columns to use (X, Y). I would like it to automatically calculate 'JostD' for all combinations of columns, perhaps returning a matrix of distances. Thanks for any help
2004 Jul 22
1
[PATCH] add LOGIN authentication mechanism
Hello, attached patch (1.0-test29) adds LOGIN authentication mechanism. Tested with KMail and seems working. Please consider applying. Best regards. P.S. I also have NTLM authentication working and plan to submit it RSN. -- Andrey Panin | Linux and UNIX system administrator pazke at donpac.ru | PGP key: wwwkeys.pgp.net -------------- next part -------------- diff -urpNX /usr/share/dontdiff
2013 Oct 03
0
cronbach
Estimado José, Es la segunda vez que veo te pregunta en este Foro, la primera vez se te pidió mas detalles y luego se te dio una respuesta. El hecho que reiteres tu pregunta, sin detalles y sin mencionar que es lo que no funcionó con la respuesta anterior, me hace recordar algunas recomendaciones que leí en una excelente respuesta en http://stackoverflow.com/, que trato de adaptar a
2004 Jul 22
0
[PATCH] POP3 CAPA command RFC violation
Hello, looks like SASL capability reported by dovecot in response to POP3 CAPA command doesn't conforms with rfc2449 which says: Examples: C: CAPA S: +OK Capability list follows S: TOP S: USER S: SASL CRAM-MD5 KERBEROS_V4 S: RESP-CODES S: LOGIN-DELAY 900 S: PIPELINING
2007 Dec 19
1
strange timings in convolve(x,y,type="open")
Dear R-ophiles, I've found something very odd when I apply convolve to ever larger vectors. Here is an example below with vectors ranging from 2^11 to 2^17. There is a funny bump up at 2^12. Then it gets very slow at 2^16. > for( i in 11:20 )print( system.time(convolve(1:2^i,1:2^i,type="o"))) user system elapsed 0.002 0.000 0.002 user system elapsed 0.373
2001 Jun 05
2
a bug? (PR#968)
--T4sUOijqQbZv57TR Content-Type: text/plain; charset=us-ascii Content-Disposition: inline Dear R, I would like to report what I think is a bug in R. I am running R within emacs on a Digital AlphaStation. See the version information at the end of my R session for details. I also attach a copy of the file that is read in the `read.table' command. Here's my R session, with a few
2008 Nov 26
2
Chi-Square Test Disagreement
I was asked by my boss to do an analysis on a large data set, and I am trying to convince him to let me use R rather than SPSS. I think Sweave could make my life much much easier. To get me a little closer to this goal, I ran my analysis through R and SPSS and compared the resulting values. In all but one case, they were the same. Given the matrix [,1] [,2] [1,] 110 358 [2,] 71 312 [3,]
2008 Nov 25
1
Efficient passing through big data.frame and modifying select
> -----Original Message----- > From: William Dunlap > Sent: Tuesday, November 25, 2008 9:16 AM > To: 'johannes_graumann at web.de' > Subject: Re: [R] Efficient passing through big data.frame and > modifying select fields > > > Johannes Graumann johannes_graumann at web.de > > Tue Nov 25 15:16:01 CET 2008 > > > > Hi all, > > > >
2008 Dec 23
1
quotation problem/dataframe names as function input argument.
Dear R friends: Can someone help me with the following problem? Many thanks in advance. # Problem Description: # I want to write functions which take a (character) vector of dataframe names as input argument. # For example, I want to extract the number of observations from a number of dataframes. # I tried the following: nobs.fun <- function (dframe.vec) { nobs.vec <-
2012 Mar 30
1
How to use access results of gregexpr in data frames
Hello, I'm trying to figure out how to find the index of the second occurrence of "/" in a string (which happens to represent a date) within a data frame column. I've used the following code successfully to find the first instance of "/". dframe <- data.frame(date=c("5/14/2011", "4/7/2011")) dframe$x1 <- regexpr("/", dframe[, 1])
2011 Jun 09
3
How to subset based on column name that is a number ?
Hi, I have a data frame with column names "1", "2", "3", ... and I'd like to extract a subset based on the values in the first column. None of the methods I tried worked (below). x <- subset(dframe, 1 = = "My Text") x <- subset(dframe, "1" = = "My Text") x <- subset(dframe, names(dframe)[1] = = "My Text") Q
2006 Mar 21
3
Rsync 4TB datafiles...?
I need to rsync 4 TB datafiles to remote server and clone to a new oracle database..I have about 40 drives that contains this 4 TB data. I would like to do rsync from a directory level by using --files-from=FILE option. But the problem is what will happen if the network connection fails the whole rsync will fail right. rsync -a srchost:/ / --files-from=dbf-list and dbf-list would contain this:
1998 Jul 29
0
Printing on a Window Client from AIX
Hi all... First, thank you to Matt Chapman for pointing out why I could not connect to a non-domain participating machine. I needed to have a local account on that machine (it wasn't checking back with the domain controllers as I thought it would). I guess I'm going to have to start venturing out of the UNIX world and into the NT one. Scary :-) Either way, I now successfully am
2011 Jul 08
1
Referencing a vector of data labels in ggplot function
Hi, I really feel I've looked everywhere, although I know this can't be a hard problem. I'd like to be able to call the graph below as a function, but I can't get the function to recognize variables beyond 'dframe'. I've read through many papers on writing functions in R, but I can't get this to work. data <- data.frame('date' = as.Date(rep(c(15101,