similar to: How to optimize a matrix

Team, I am trying to resolve the self-selection bias of a sample in an experiment and would like to run the Heckman Correction Estimation using R. Can someone help me with the R-Code... I tried searching for the discussion, but not successful. Thanks in advance, Best, Kishore/.. http://kaykayatisb.blogspot.com [[alternative HTML version deleted]]

Hello everyone, I know where is wrong. I forget to specify the parameters in my function. Thank you for anyone who was trying to help me! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > It seems that I was not successfully attached the code. Here is the > code. I appreciate any help! > > Best, > Yen > > ?? b88207001 at ntu.edu.tw: > >> Hello

Hello everyone, I have been working on a code which simply repeatedly appends a number into a vector and write a file. However, it could not be properly implemented when I use it. It works when I run it line by line. I wonder what is the problem and I appreciate anyone who is willing to help. The function and the example code is attached. Any advice is appreciated! Best, Yen

Hello everyone, It seems that I was not successfully attached the code. Here is the code. I appreciate any help! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > I have been working on a code which simply repeatedly appends a > number into a vector and write a file. However, it could not be > properly implemented when I use it. It works when I run it line by

Hello dear uesRs, I am working on modeling both level one and level two heteroscedasticity in HLM. In my model, both error variance and variance of random intercept / random slope are affected by some level two variables. I found that nlme is able to model heteroscedasticity. I learned how to use it for level one heteroscedasticity but don't know how to use it to model the level

Dear R users, I have a table with the following form STATION X Y 1 -70 30 1 -70 30 1 -70 30 2 -72 29 2 -72 29 2 -72 29 2 -72 29 How want to extract unique value for those columns ... I am sure it is very simple, but I can not achieve to find the correct way ! I want to obtain something like STATION X Y 1

*How can I do a t-test with survey data?* Thanks. Marie -- --------------------------------------------------------------------- Le Bureau f?d?ral du Plan f?te ses 50 ans en 2009. Het Federaal Planbureau viert zijn 50-ste verjaardag in 2009. The Federal Planning Bureau celebrates its 50-th anniversary in 2009. ---------------------------------------------------------------------

I need a script that works for Bootstrap validation. Could someone explain me when should I use the Bootstrap technical or Jackknife? Thanks -- View this message in context: http://www.nabble.com/BOOTSTRAP_CROSS-VALIDATION-tp22529500p22529500.html Sent from the R help mailing list archive at Nabble.com.

Hello, everyone, There's a problem about zero in R and I really need your help. I have a vector shown as x=c(0.1819711,0.4811463,0.1935151,0.1433675), The sum of this vector is shown as 1 in R, but when I type 1-sum(x), the value is not zero, but -2.220446e-16. I can accept that this value is quite small and could be seen as zero, but there would be a problem when it's not really

Have the counter function in R ? if we use the software SAS /*** SAS Code **************************/ data tmp(drop= i); retain seed x 0; do i = 1 to 5; call ranuni(seed,x); output; end; run; data new; counter=_n_; ***** this keyword _n_ ****; set tmp; run; /* _n_ (Automatic variables) are created automatically by the DATA step or by DATA step statements. */ /*** Output

I have a data frame in long format and I would like to randomly divide this data frame in half. The data frame consists of 39622 rows and I initially tried ... randomsample1 <- data[sample(nrow(data),19811), ] Where allows me to randomly select half of the rows and assign them to randomsample1 but then I couldn't figure out how to select those rows that were not selected and assign

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If you don't get a response it is because you did not read the Posting Guide which indicates that the R-sig-ME mailing list is where this question would have been on-topic. -- Sent from my phone. Please excuse my brevity. On August 16, 2017 6:17:03 AM PDT, b88207001 at ntu.edu.tw wrote: >Hello dear uesRs, > >I am working on modeling both level one and level two

A better place for this post would be on R's mixed models list: r-sig-mixed-models . Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Aug 16, 2017 at 6:17 AM, <b88207001 at ntu.edu.tw> wrote: > Hello dear

Dear R Gurus: I read somewhere that functions are considered vectors. Is this true, please? thanks Edna Bell

I'm new to post in R-help and my native language is not English. I apologize if my sentence is not fluent to read. I am doing a simulation study and I need to execute SAS and read a SAS code in R. I try the following code but it doesn't work. system('"c:\\program files\\SAS\\SAS 9.1\\sas.exe" "c:\\syntax.sas"') can anyone give me some help with this?

Dear all, I've written a function and repeated it for 5000 times with loops with different value, and the messages returned are the output I set and 15 warnings. I would like to trace the warnings by stopping the loop when warning came out. Does anyone know how to make it? Thanks a lot for your help. Yen [[alternative HTML version deleted]]

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x["V2"] is more efficient than using drop=FALSE, and perfectly normal syntax (data frames are lists of columns). I would ignore the naysayers, or put a comment in if you want to accelerate their uptake. As I understand it, one of the main reasons tibbles exist is because of drop=TRUE. List-slice (single-dimension) indexing works equally well with both standard and tibble types of data

You could declare a matrix much larger than you intend to use. This works with a few megabytes of data. It is not very efficient, so scaling up may become a problem. m22 <- matrix(NA, 1:600000, ncol=6) It does not work to add a new column to the matrix, as in you get an error if you try m22[ , 7] but convert to data frame and add a column m23 <- data.frame(m22) m23$x7 <- 12 The only