similar to: Formatted text output

Hi I am very new to R and have not able to find the answer to my question in the manual or any other post. I have a dataset that has various different sites names with data relating to each site. The data is in one dataset. I want to loop through the different site names and perform my test on each site. The sites are named not numbers for example "YYC". How do I do this. I hope I

Simple question: is there a way to compile R scripts to native code?  If not is there anything else that might improve speed?  I'm not even sure that R compiles internally to byte code or not.  I assume it does since all modern languages seem to do this.  Maybe there's a JIT compiler?  Yes, I have searched Google and get lots of stuff that's seems confusing.  I just want to know what

I just discovered that some evil spammer has somehow gotten my contacts list and used it to send out a bunch of spam. This is just to notify you that if you get an email from me on May 26, 2011 (other than this one or one like it - the problem was more extensive than I first thought) it wasn't from me. Please don't add me to your spam filters. I've changed my password and

Dear all, Is there an elegant way to add citations of packages when using Sweave? Ideally I'd like a function which creates a Bibtex-file with the packagenames as keys. The idea is to use \cite{packagename} or \cite{R} in LaTeX. I know you can get the Bibtex entry with toBibtex(citation("packagename")). But after updating R or a package one needs to update the bib-file too. When

Hello, I wanted to install MergeMaid package in v 2.2.1. I could install it but couldn't use without its dependant, Biobase. at biobase installation, I got the following error message In method for function "split": expanding the signature to include omitted arguments in definition: drop = "missing" Error in .MakeSignature(new("signature"), def, signature) :

Dear all, I have written some R source program with many thousands of lines. I didn’t insert line breaks automatically or manually for the long lines. But now I would like to edit the source code in Emacs/ESS to make it more formal as a package. One of the major problems here is how to break the long lines automatically. Emacs auto-fill-mode only works for the lines you are typing in currently,

If I copy the following commands in my batch file to the R console, R creates a file named "basicStatsIBM.lis" with the program output in it: Sortie <- file(description = "basicStatsIBM.lis", open = "wt", blocking = TRUE, encoding = "UTF-8") sink(file = Sortie, append = FALSE, type = "output", split = FALSE) basicStats(ibm) close(Sortie)

  Dear R-helpers, hello I am seeking your help in somehow getting names of variables without quotes (" "). Let us say, we have a table with 3 variables V1, V2 and V3. After the table is read, I get names of the variables (thro' the following code) as under quotes (like "V1" rather than the original representation V1)  

Does anyone know of a literature reference, or a piece of code that can help me calculate the amount of variation explained (R2 value), in a regression constrained to have a slope of 1 and an intercept of 0? Thanks! Sebastian J. Sebastián Tello Department of Biological Sciences 285 Life Sciences Building Louisiana State University Baton Rouge, LA, 70803 (225) 578-4284 (office and lab.)

Hi, While playing with quantile-quantile plots, I wrote up some code which plots something strangely different. Here's the pseudocode: testhist <- hist(sample_data) refhist <- hist(rnorm(n, mean=0,sd=1)) # for some large-ish n cumtest <- cumsum(testhist) cumref <- cumsum(refhist) plot(cumref,cumtest) This produces a straight line of slope 1 for a sample with the same

I have been able to adapt the main LLVM sources to work with vectors of 16 x FP16 values and I have introduced the 'v16f16' data type to CLang and LLVM, but I am stumped on how to get TableGen to recognise this type. At the moment I am trying to optimise the calling convention code, and whenever I refer to 'v16f16' I get a crash in TableGen (unrecognised type). Unfortunately I

I?ve been using Frank Harrell?s rms package to do bootstrap model validation. Is it the case that the optimum penalization may still give a model which is substantially overfitted? I calculated corrected R^2, optimism in R^2, and corrected slope for various penalties for a simple example: x1 <- rnorm(45) x2 <- rnorm(45) x3 <- rnorm(45) y <- x1 + 2*x2 + rnorm(45,0,3) ols0 <- ols(y

I am trying to use Rails and an Oracle 7 database. I have the following error message: (eval):3:in `__send__'': ORA-12663: Services required by client not available on the server (OCIError) from (eval):3:in `describe'' and the line oracle_adapter,rb:361: (owner, table_name) = @connection.describe(table_name) Do I need this describe line? Can I replace with something else just

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Hi all, I was wondering whether it is possible to use the lapply() function to alter the value of the input, something in the spirit of : a1<-runif(100) a2<-function(i){ a1[i]<-a1[i-1]*a1[i];a1[i] } a3<-lapply(2:100,a2) Something akin to a for() loop, but using the lapply() infrastructure. I haven't been able to get rapply() to do this. The reason is that the "real"

Hi there, I have a binary matrix (dim 100x100) filled with values 0 and 1. I need select a record "n" positions of that matrix when values are 1. How can I do that? Thanks for all, Miltinho Brazil --------------------------------- [[alternative HTML version deleted]]

While writing a function that includes placing grid lines at the same position as the axis ticks, I found that the axis* functions don't return anything. Thus I have had to copy the appropriate function, removing the call to axis() and adding a line to return the tick positions. Is there a more elegant way to determine the tick positions on an axis? Thanks. Jim (normally bitwrit at

Dear List, I have a simple model as follows: x <- rnorm(500) library(logspline) fit <- logspline(x) n <- 1000000 y <- replicate(n, sum(rlogspline(rpois(1,10), fit))) # last line The problem I keep getting is R crashes when doing the last line. It seems to be fine if n is small, but not if n is 1000000. The message I keep getting is: "R for Windows GUI front-end has

Dear all, I have two variables, y and x. It seems that the relationship between them is Piecewise Linear Functions. The cutpoint is 20. That is, when x<20, there is a linear relationship between y and x; while x>=20, there is another different linear relationship between them. How can i specify their relationships in R correctly? # glm(y~I(x<20)+I(x>=20),family = binomial, data =

Hi, I am writing a basic function to extract the z scores for some linear regression coefficients: zscore<-function( y, x) { lm<-lm( y ~ x ) z <- coef(lm)/sqrt(diag(vcov(lm))) return(z) } I would like to pass a dataframe to the function as a argument so the function call changes from zscore(df$y1,df$x1) to zscore(y1,x1,data=df) but I am not sure how to reference the data