similar to: How to pass a collection to paginate?

Hi there, I''ve been trying to paginate over a list of members that all share a tag in common using the acts_as_taggable plugin. The regular way of paginating over a collection doesn''t seem to work with acts_as_taggable. Here''s what my method looks like that takes in a tag name, finds all the members that share the tag and then displays all the members. Nothing too fancy

I have the following: def index begin @restaurant_pages, @restaurants = paginate :restaurants, :order => (params[ :sort ] || "name"), :per_page => 2 @cuisines = Cuisine.find_all rescue redirect_to :action => :index end end # sort by cuisine def

Hi! I''ve got a list of project on the main page and if one of them is selected i render a partial using ajax with data of selected project. How to create links to next/previous project using pagination? -- Posted via http://www.ruby-forum.com/.

Hi to all!! I am new to ruby. I am trying to write a program to fetch the data from Database and written the data using pagination. I could get the data from DB. but pagination is not working. When i see the log file it is showing the following error. NoMethodError: undefined method ''paginatior'' #<Hash...> my pginate.rb and pagination.rb files are not in the same folder

Hi! I''ve got list of project on the main page and some content. If user clicks on one of the project i use ajax to update div with content with project data. I''m displaying only one project at a time. In index action i just collect all projects: @projects = Project.find(:all, :order => "date DESC") In show action i render project partial: render :partial =>

I have searched for days for an example that demonstrates what i would like to do, and this morning i thought i''d worked it out, but no....here''s what i have: Controller ========== class ProfilesController < ApplicationController def friends current_user.profile.friends end def list_friends @profile_pages, @profiles = paginate( friends, :per_page => 10) end end

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

Hi all, I''m creating admin module. in that module i need to get the list of users and also the projects created by the each user. No doubt i''m getting the list of users. but i''m not getting the list of projects done by each user.. This is my code:: <% for user in @users %> <%=link_to

Hi all, Is there a way to create pagination with a complex SQL, more complex than the :conditions option will support? I have two databases, houses and images. Houses has_many images, and each Image belongs_to house. I''m creating a search engine for the house records and I''d like to be able to filter out all the houses without any associated images. So far I''m

Is there a count_by_content alternative to the find_by_content action? This is because I''m wanting to do the following in my pagination method: def list # step 1: set the variables you''ll need page = (params[:page] ||= 1).to_i items_per_page = 20 offset = (page - 1) * items_per_page # step 2: instead of performing a find, just get a count item_count =

I''m just wondering where I would put the pagination for search results when using "acts_as_ferret". At the moment my search code is.. def search @query = params[:query] || '''' unless @query.blank? @results = Tutorial.find_by_contents @query end end Cheers SchmakO -- Posted via http://www.ruby-forum.com/.

Hello, I was talking with someone in IRC, trying to get one form with however many fields to make new rows. He worked with me on the controller, but then I didn''t get the help with the view I needed, and I''ve been trying to do it on my own. I''m uploading pictures to my Pictures table. As you know, I need a few fields for each picture. I''ll need the filename,

Hi, I am using the rails find command as below @project_pages, @projects = paginate :projects, :per_page => 20, :conditions => "clients.organisation_id = " + params[''search''][''organisation_id''], :joins => ''inner join clients ON clients.id = projects.client_id'' There seems to be a problem with project.id being over written

hi All, i wants to implement ajax pagination but i am facing a lot of problem , i found i lots of links on google but their is no explanation like what object we have to pass and condition can any body help me out in this concern pls i need your help as soon as possible thanks sachin --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the

Hi everyone, I''m at the end of my rope on this. I can''t get pagination to work with anything but a standard find on a model. If I try to do a search and customize the pagination, I get lots of different variations. My thought was to have the list action do what it does, but to pass it a list of search conditions from the search action. So, if search determines that we need

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

I am a Rails newbie and I am trying to build a test site in which users will have their own sets of data. I understand how to manipulate shared data very well. Most of the Rails examples out there seem to deal with such shared data. I am struggling with the "best practice" method for a user to work with their own data however (and not be able to view/edit other users''

Hi everyone, I have 3 types of people (for now): Staff Faculty Students To break them up into classes, but keep them in the same People table, I''ve broken them up like so (code and ''ends'' snipped): class Person < ActiveRecord::Base class Employee < Person class Staff < Employee class Faculty < Employee class Student < Employee So, when I insert

I have my list view filtering rows shown within the table <tr> tags like most of the introductory tutorials do. As I''m adding a few dozen entries I''m noticing the standard scaffolding pagination doesn''t pick up the number of rows from the filter since it is not being passed the number of rows returned within the scope of the filter statement. >From a

Just wondering how to best integrate with pagination and still stick to MVC... Say I have a Post model that has a published attribute. I want to show all the recent published posts on a page. My first instinct is to create a method in the Post model called recent that does the find with proper conditions and order, but the problem I have is how do I use that with pagination (which definitely