similar to: Function output difficulties

Hi, I would like to turn my TRUE/FALSE matrix into a 1/0 matrix (i.e. True=1 and False=0) [,1] [,2] [,3] [1,] TRUE FALSE FALSE [2,] TRUE TRUE FALSE [3,] TRUE TRUE TRUE [,1] [,2] [,3] [1,] 1 0 0 [2,] 1 1 0 [3,] 1 1 1 Is there a quick way of doing this without a loop? Thanks Emma -- View this message in context:

Hi, I have several matrix in a list, for example: e [[1]] [,1] [,2] [1,] 1 3 [2,] 2 4 [[2]] [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 [[3]] [,1] [,2] [1,] 2 1 I would like to join them by column i.e. [,1] [,2] [,3] [,4][,5] [,6] [1,] 1 3 1 4 2 1 [2,] 2 4 2 5 NA NA [3,] NA NA 3 6 NA NA I have tried

Hi, Is there a quick way to go from this matrix: > A [,1] [,2] [,3] [1,] 1 1 1 [2,] 2 2 2 [3,] 3 3 3 [4,] 4 4 4 [5,] 5 NA 5 [6,] NA NA 6 [7,] NA NA NA to this matrix: > B [,1] [,2] [,3] [1,] 1 NA NA [2,] 2 NA 1 [3,] 3 1 2 [4,] 4 2 3 [5,] 5 3 4 [6,] NA 4 5 [7,] NA NA 6

Hi, I would like to sum some specific columns in my matrix- for example, my matrix looks like this: [,1] [,2] [,3] [,4] [,5] [1,] 1 NA NA NA NA [2,] 2 1 NA 1 NA [3,] 3 2 1 2 1 [4,] 4 3 2 3 2 [5,] NA NA NA 4 3 [6,] NA NA NA 5 NA I would like to find the sum of the first two columns, the second two columns and

I have a list of numbers with NAs as below: > A[,1] [1] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [19] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [37] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [55] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [73] NA NA NA 62 78 98

Im haveing a problem with my profiles share on my Samba 2.2.3 PDC server. I have a share like this: [profiles] path = /home/samba/profiles writeable = yes create mask = 0700 directory mask = 0700 browsable = no valid users = root,@smbusers The roaming profile works just fine with windows2k, and the users can't read the other profiles (they get a "access

Dear all, I'm having trouble installing Centos 6.8, in a VM using VirtualBox, and hoping that someone on this distribution can help. I'm running VirtualBox Version 5.1.4 r110228 (Qt5.5.1). I downloaded .iso files for Centos 6.8: - CentOS-6.8-x86_64-bin-DVD1.iso - CentOS-6.8-x86_64-bin-DVD2.iso I proceeded to set up a new VM, selecting Linux / RedHat 64 bit. I selected the DVD1 iso

On Fri, 9 Dec 2016 12:46:11 -0700 Emma M Birath wrote: > > I proceeded to set up a new VM, selecting Linux / RedHat 64 bit. I > > selected the DVD1 iso file above as "IDE Primary Master" and the DVD2 > > as "IDE Secondary Master". I have personally always had the best luck by installing the Live CD, and then customizing the installation from there. This

Prepare for the coming implementation by GCC and Clang of the __counted_by attribute. Flexible array members annotated with __counted_by can have their accesses bounds-checked at run-time checking via CONFIG_UBSAN_BOUNDS (for array indexing) and CONFIG_FORTIFY_SOURCE (for strcpy/memcpy-family functions). As found with Coccinelle[1], add __counted_by for struct vc4_perfmon. [1]

Prepare for the coming implementation by GCC and Clang of the __counted_by attribute. Flexible array members annotated with __counted_by can have their accesses bounds-checked at run-time checking via CONFIG_UBSAN_BOUNDS (for array indexing) and CONFIG_FORTIFY_SOURCE (for strcpy/memcpy-family functions). As found with Coccinelle[1], add __counted_by for struct vc4_perfmon. [1]

Prepare for the coming implementation by GCC and Clang of the __counted_by attribute. Flexible array members annotated with __counted_by can have their accesses bounds-checked at run-time checking via CONFIG_UBSAN_BOUNDS (for array indexing) and CONFIG_FORTIFY_SOURCE (for strcpy/memcpy-family functions). As found with Coccinelle[1], add __counted_by for struct vc4_perfmon. [1]

Hello, I am trying to write a function that first requires randomly sampling items from a set of factors. I need to be able to sample from that same set of factors, but exclude the ones that have already been sampled previously. For example, suppose I have a set of items a-j (a,b,c,d,e,f,g,h,i, and j) and randomly sample a, c, and f from that group. How do I sample again from the larger group

Dear colleagues Please could someone kindly explain the following inconsistencies I've discovered when performing logical calculations in R: 8.8 - 7.8 > 1 > TRUE 8.3 - 7.3 > 1 > TRUE Thank you, Emma Jane [[alternative HTML version deleted]]

I don't think it's the same problem as you described. By printing I meant calling printf function and passing my global variable as one of the arguments. My code: Instruction* InstructionVisitor::incrementGlobalKey(Instruction* I) { IRBuilder<> Builder(I->getContext()); Builder.SetInsertPoint(I->getNextNode()); GlobalVariable* key =

Hi, I'm using GIT pull from a few days ago. I am trying to get ssh working with kerberos when samba is the KDC. I am having trouble getting my machine keytabs to work. Here's some of the problems I have: 1) root at morannon:~# samba-tool export keytab /tmp/test.keytab added interface ip=192.168.1.11 nmask=255.255.255.0 added interface ip=127.0.0.1 nmask=255.0.0.0 added interface

I have installed SAMBA (latest version) on my solaris machine, and I have gone through all the specified steps to configure it. I am trying to view the share (just "home") from a DOS window in Windows 2000, using : > net view \\myUNIXbox and am getting : System Error 5 has occurred. Access is denied Any suggestions greatly appreciated. Please reply to me at

We are seeking nominations for candidates for election to the X.Org Foundation Board of Directors. All X.Org Foundation members are eligible for election to the board. Nominations for the 2024 election are now open and will remain open until 23:59 UTC on 26 February 2024. The Board consists of directors elected from the membership. Each year, an election is held to bring the total number of

Hi, Can anyone help sort out the problem with the following script - I am a R newbie and I am self taught. obs.all = c() for(i in 1:386){ if (n.sim[i]>0){ obs = (1:133429)[event.details[,2] == i] obs.all = c(obs.all, sample(obs[obs < n.sim[i]], size = n.sim[i], replace=T)) } Basically, in the sample bit, I only want to get obs.all if the value of

Dear R users and developers After upgrading to Windows XP and R 1.9.1 and 2.0, I retried to execute plot.baysian() to a data set that I had used previously to plot with no problem in win2000 R1.8. The error I get is: Error in points(Mbar[-index], lods[-index], pch = ".") : only 0's may mix with negative subscripts Thanx in advance Dino P.S. I allready sent this message

Hello I am trying to fit a REML to some soil mineral data which has been collected over the time period 1999 - 2004. I want to know if the 19 different treatments imposed, differ in terms of their soil mineral content. A tree model of the data has shown differences between the treatments can be attributed to the Magnesium, Potassium and organic matter content of the soil, with Magnesium being the