similar to: Help with maps

even for people who didn't like the outcome of the US elections this year, it must have been a joy to see all the nice (and not so nice) graphs that were shown. As an exercise, I recreated the map shown on the NY-Times website [ http://www.nytimes.com/packages/khtml/2004/11/03/politics/ 20041103_px_ELECT_GRAPHIC.html ] If you're interested,

I'm sure this is smack-head moment, but I haven't been able to find an example of this on Nabble or SO, so thought I'd ask. This works: michigan <- map_data('county', 'michigan') mich_points <- data.frame(x = rnorm(n = 200, median(michigan[,1]), 0.75), y = rnorm(n = 200, median(michigan[,2]), 0.75)) ggplot() + geom_path(aes(long, lat, group = group), data =

Hi everyone! I'm digging into ggplot for some while now, I must say it's great! But - as some others have posted before, and hadley knows very well himself - the documentation is lacking some bits... So I have to pose that question directly: I'd like to produce a series of maps with different data on, but exactly the same extent in each plot. Is there a way of switching the

Dear all, I'm trying to plot some data over a geographic map. I'm reading the documentation (?map)... The problem is here: *map(database = "world", regions = ".", exact = FALSE, boundary = TRUE,* * interior = TRUE, projection = "", parameters = NULL, orientation = NULL,* * fill = FALSE, col = 1, plot = TRUE, add = FALSE, namesonly = FALSE,* * xlim =

I'm trying to get Sweave running for automatic report generation, and it seems to run fine when just using verbatim output. However, I've ran into a problem with xtable. I would like to print the following matrix using xtable: > dim(counts) [1] 19 15 All columns are filled with real/integer numbers > 0 and < 1000. Just typing xtable(counts) gives correct LaTeX output, but

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

A couple of months ago, probably using an older version of R, R used to run the following code just fine: library("foreign") data.exp1 <- as.data.frame(read.spss("dataDef.sav")) Issuing the same commands now (after starting R using --vanilla), gives me the following behavior: > library("foreign") > x <- read.spss("dataDef.sav") Error

I am having trouble getting data labels to display over the provinces in a GADM map of Canada. Specifically, I need the variable "Number" from the data set "by_province", grouped by "region", to appear on the corresponding regions of the map. The data set "by_province" looks like this: long lat order hole piece region

Hedderik van Rijn <hedderik@cmu.edu> writes: > If the second argument to unsplit is not a simple vector (but a "list > containing multiple lists"), the function seems to have some problems. > > Given a slight modification of the examples in help(split): > > > xg <- split(x,list(g1=g,g2=g)) > > unsplit(xg,list(g1=g,g2=g)) > [1] -0.7877109

Dear all, I've got a quite large dataframe (stor) with rows subject and rt (reaction time). I would like to split the reaction times per subject into 6 bins of equal size. Right now, I'm using the following code: bindata <- function(rt) { bindata <- rep(-1,length(rt)) binwidth <- length(rt)/6 bindata[order(rt)[(0*binwidth)+1:(1*binwidth)]] <- 1

I use AfterStep on Linux. I made an R.xpm file (attached) and put this icon in the "wharf". To invoke R I click on the R icon. I did not find an offical R.xpm, and so I am submitting this one for your collective consideration.... The idea behind the icon is that it looks like a scatterplot, which is "statistical". My main beefs with my R.xpm are that it doesn't have a

Hi, [some background] I have a dataset which describes a number of subjects doing a "scientific discovery". That is, they have to discover the rules underlying a particular domain. To do so, they have to set the levels of 5 variables which leads to a certain outcome. To identify what kind of "experiments" the subjects did, I want to combine these levels into one variable

Hello all: A question from a new user. I have data on a geo-referenced curvilinear grid. This is a grid with 75 rows and 51 columns, is not aligned north-south, and the rows and columns are not straight. (And the coordinates are in meters.) I want to make image plots of this data, but where the grid is deformed according to the correct locations of the grid points, instead of coming out

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

ggplot2 ------------------------------------------------------------ ggplot2 is a plotting system for R, based on the grammar of graphics, which tries to take the good parts of base and lattice graphics and avoid bad parts. It takes care of many of the fiddly details that make plotting a hassle (like drawing legends) as well as providing a powerful model of graphics that makes it easy to produce

Dear all, I have a data set which has latitude, longitude (not in increasing order) and observed precipitation corresponding to those locations. I am using image.plot command for that. But I want to overlay a map of US on that plot. I know we can use map('usa') to draw it, but I dont know how can I overlay it on the plot of the precipitation data. Can anyone please help me with it?

I would be very thankfull for such a solution, too .... "R.E. Darnell" wrote: > > Would introducing a "Are you sure?" question after kill the *R* ( or > whatever) buffer with a hasty C-x k be a popular default > "feature". How can I include this for my own use? > > Thanks > > Ross Darnell --

Hi: How do I find average across three columns such as weight1, weight2, weight3 (20 people, each person has three different measures)? They have NA's also. Thanks Tom, Univ of Pittsburgh, ttrut at yahoo.com

I think I'm missing something tonight in the usage of 'legend': plot(0, type="n") legend(locator(1), month.abb[1:5], pch=15, col=1:5) gives me something similar to what I want. But legend(locator(1), month.abb[1:5], fill=T, col=1:5) gives me 5 black boxes. What am I doing wrong? Thank you, > version _ platform i686-pc-linux-gnu arch i686 os