similar to: question about the tisPlot function in package tis

Displaying 20 results from an estimated 1000 matches similar to: "question about the tisPlot function in package tis"

2010 Apr 30
1
tis: cannot alter subset when input matrix contains NAs
When using the tis time series package (v1.9), I cannot select or alter a subset of a time series when the time series is created from a matrix and the matrix contains NA values. Example: x<-tis(t(c(1:10,NA)), start=c(2000,1), freq=12) x[x>0]<-0 The second line yields "Error in if (any(i > nrow(x))) { : missing value where TRUE/FALSE needed" However, both of the following
2006 Sep 12
1
openssh (OpenBSD) , bsdauth and tis authsrv
nuqneH, I've tried using TIS authsrv authentication via bsd auth and found it quite limited. The most important restriction it does not log ip and fqdn of the remote peer, nor the application name, to the authentication server. It does not matter much for TIS authsrv, but since other applications do provide such information, our authsrv version uses it for extra authentication restrictions.
2000 Dec 07
1
[PATCH] tis authserv support
Hi, We at BalaBit IT Security Ltd developed a patch against openssh 2.3.0p1 to support TIS authserv authentication. TIS authserv uses a simple protocol, and supports CryptoCard, SKey, password etc. authentication. The commercial versions of SSH support this protocol, OpenSSH implemented SKey on its own using the protocol primitives originally invented for TIS authentication. Our patch is an
2017 Aug 22
4
boot.stepAIC fails with computed formula
I'm trying to use boot.stepAIC for feature selection; I need to be able to specify the name of the dependent variable programmatically, but this appear to fail: In R-Studio with MS R Open 3.4: library(bootStepAIC) #Fake data n<-200 x1 <- runif(n, -3, 3) x2 <- runif(n, -3, 3) x3 <- runif(n, -3, 3) x4 <- runif(n, -3, 3) x5 <- runif(n, -3, 3) x6 <- runif(n, -3, 3) x7
2017 Aug 23
3
boot.stepAIC fails with computed formula
Until I get a fix that works, a work-around would be to rename the 'y1' column, used a fixed formula, and rename it back afterwards. Thanks for your help. SGO. -----Original Message----- From: Bert Gunter [mailto:bgunter.4567 at gmail.com] Sent: 22 August 2017 20:38 To: Stephen O'hagan <SOhagan at manchester.ac.uk> Cc: r-help at r-project.org Subject: Re: [R] boot.stepAIC
2017 Aug 23
0
boot.stepAIC fails with computed formula
It seems that if you build the formula as a character string, and postpone the "as.formula" into the lm call, it works. instead of frm1 <- as.formula(paste(trg,"~1")) use frm1a <- paste(trg,"~1") and then strt <- lm(as.formula(frm1a),dat) regards, Heinz Stephen O'hagan wrote/hat geschrieben on/am 23.08.2017 12:07: > Until I get a fix that works, a
2017 Aug 22
0
boot.stepAIC fails with computed formula
OK, here's the problem. Continuing with your example: strt1 <- lm(y1 ~1, dat) strt2 <- lm(frm1,dat) > strt1 Call: lm(formula = y1 ~ 1, data = dat) Coefficients: (Intercept) 41.73 > strt2 Call: lm(formula = frm1, data = dat) Coefficients: (Intercept) 41.73 Note that the formula objects of the lm object are different: strt2 does not evaluate the formula. So
2019 Sep 23
2
What is the best way to loop over an ALTREP vector?
Sorry for post a lot of things, for the first part of code, I copied my C++ iter macro by mistake(and you can see an explicit type casting). Here is the macro definition from R_exts/Itermacros.h #define ITERATE_BY_REGION_PARTIAL(sx, px, idx, nb, etype, vtype, \ strt, nfull, expr) do { \ * const** etype *px = DATAPTR_OR_NULL(sx); *
2019 Oct 23
2
Unexpected behavior when using macro to loop over vector
Hi all, I found an unexpected behavior when I was trying to use the macro defined in "R_ext/Itermacros.h" to loop over an atomic vector. Here is a minimum example: C++ code ``` #include "R_ext/Itermacros.h" #define GET_REGION_BUFSIZE 2 //Redefine the macro since C++ is not happy with the implicit type conversion #define ITERATE_BY_REGION_PARTIAL(sx, px, idx, nb, etype,
2017 Aug 22
1
boot.stepAIC fails with computed formula
Failed? What was the error message? Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Tue, Aug 22, 2017 at 8:17 AM, Stephen O'hagan <SOhagan at manchester.ac.uk> wrote: > I'm trying to use boot.stepAIC for
2017 Aug 22
0
boot.stepAIC fails with computed formula
The error is "the model fit failed in 50 bootstrap samples Error: non-character argument" Cheers, SOH. On 22/08/2017 17:52, Bert Gunter wrote: > Failed? What was the error message? > > Cheers, > > Bert > > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along > and sticking things into it." > -- Opus (aka
2019 Aug 28
3
What is the best way to loop over an ALTREP vector?
Hi devel team, I'm working on C/C++ level ALTREP compatibility for a package. The package previously used pointers to access the data of a SEXP, so it would not work for some ALTREP objects which do not have a pointer. I plan to rewrite the code and use functions like get_elt, get_region, and get_subset to access the values of a vector, so I have a few questions for ALTREP: 1. Since an
2017 Aug 22
1
boot.stepAIC fails with computed formula
SImplify your call to lm using the "." argument instead of manipulating formulas. > strt <- lm(y1 ~ ., data = dat) and you do not need to explicitly specify the "1+" on the rhs for lm, so > frm2<-as.formula(paste(trg," ~ ", paste(xvars,collapse = "+"))) works fine, too. Anyway, doing this gives (but see end of output)" bst <-
2019 Oct 25
2
Unexpected behavior when using macro to loop over vector
On 10/25/19 11:01 AM, Tomas Kalibera wrote: > On 10/23/19 6:45 AM, Wang Jiefei wrote: >> Hi all, >> >> I found an unexpected behavior when I was trying to use the macro >> defined >> in "R_ext/Itermacros.h"? to loop over an atomic vector. Here is a >> minimum >> example: >> >> C++ code >> ``` >> #include
2019 Sep 24
2
What is the best way to loop over an ALTREP vector?
Hi Bob, Thanks for sending around the link to that. It looks mostly right and looks like a useful onramp. There are a few things to watch out for though (I've cc'ed Romain so he's aware of these comments). @romain I hope you taake the following comments as they are intended, as help rather than attacks. The largest issue I see is that the contract for Get_region is that it *populates
2011 Sep 22
1
nlm's Hessian update method
Hi R-help! I'm trying to understand how R's nlm function updates its estimate of the Hessian matrix. The Dennis/Schnabel book cited in the references presents a number of different ways to do this, and seems to conclude that the positive-definite secant method (BFGS) works best in practice (p201). However, when I run my code through the optim function with the method as "BFGS",
2009 Jun 02
2
Adding a method to a generic in another package
I am the maintainer of the 'tis' package. One of the functions in my package is 'nberShade'. A user wants to make nberShade generic, with the old version renamed as nberShade.default, all of which is fine with me. And he wants to add a new method, nberShade.ggplot, which works for objects of class ggplot. He also wants to add a method fortify.tis for the generic fortify defined
2006 Oct 24
0
[PATCH] [HVM] [TPM] [3/3] TIS device model for Qemu
This patch adds a TIS device model compliant to the 1.2 TPM specification to Qemu. It implements all registers necessary to make the Linux TIS driver work (tpm_tis.c). All of the basic registers supported by this type of device are implemented. Also the locality selection has been implemented, but has not been tested. The legacy registers as described in the specification are not supported.
2006 Jul 21
2
glm cannot find valid starting values
glm(S ~ -1 + Mdif, family=quasipoisson(link=identity), start=strt, sdat) gives error: > Error in glm.fit(x = X, y = Y, weights = weights, start = start, etastart > = > etastart, : > cannot find valid starting values: please specify some strt is set to be the coefficient for a similar fit glm(S ~ -1 + I(Mdif + 1),... i.e. (Mdif + 1) is a vector similar to Mdif. The error
2010 Mar 05
2
question on maximum of each row of the matrix
Hi, I used the apply()function to compute the maximum of the each row of the matrix, but in my application sometime the matrix has just one row, and the apply() dosen't work. Could you please give me some hints? thank you khazaei