similar to: How to make a banner table.

Displaying 20 results from an estimated 2000 matches similar to: "How to make a banner table."

2003 Sep 16
2
How does "subset" replace arguments? (PR#4193)
Full_Name: Axel Benz Version: 1.7.1 OS: Windows Submission from: (NULL) (137.251.33.43) Hello, I guess many people will answer me again that this is a S language feature, but I am only a stupid computer scientist and I simply do not understand this logic, despite of reading a lot about S: > test field tuckey 4 Kreis2 -1 5 Kreis5 -2 9 Metall -3 17
2008 Aug 01
2
is this a bug (apply and class) ?
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2023 Mar 30
1
Problems with foreign
Good day My name is Jos? Oscar, I'm from Mexico and I have some questions about foreign in your write.foreig( ) function. We know that this function generates the inputs to be able to run them or execute them in another program like SPSS, SAS or Stata. In these cases, when creating an example file, a matrix and using the function to execute the .sps file directly from SPSS, I don't care or
2003 Jan 21
1
[R] proposal: lattice/levelplot: panel.catlevelplot
I suggest to add a panel function to levelplot (or perhaps to an other 3d lattice function) which is able to translate the z values into the size of the rectangles. It could be used to display categorical data. I append the proposed code and two examples: - panel.catlevelplot() - example1.catlevelplot.esoph() - example2.catlevelplot.esoph() Wolfram Fischer #------ CODE
2005 Apr 09
4
make check-all fails (PR#7784)
Full_Name: Ed Borasky Version: R-beta 2.1.0 2005-04-08 OS: Linux 2.6.11 GCC 3.3.5 Submission from: (NULL) (24.21.57.139) I downloaded the latest R-beta tarball and did a build with the default options. OS is Linux 2.6.11 and compiler is GCC 3.3.5. "make check-all" failed with the following message: make[3]: Entering directory `/home/znmeb/R-beta/tests' running code in
2002 Aug 13
1
interaction.plot() legend too narrow when mfcol > 2 (PR#1899)
Here is an example: The legends (mainly the factor level names) are cut off on the right. Somehow the internal calculation which computes horizontal space for the legend is not flexible enough. ## Call a new graphics window {with default par()s !}: get(getOption("device"))() par(mfrow = c(2,2)) ## part of example(interaction.plot) _improved_ using with() : data(OrchardSprays)
2019 Apr 05
6
all.equal failure
This arose in testing [.terms and has me confused. data(esoph)?? # use a standard data set t0x <- terms(model.frame( ~ tobgp, data=esoph)) t1 <-? terms(model.frame(ncases ~ agegp + tobgp, data=esoph)) t1x <- (delete.response(t1))[-1] > all.equal(t0x, t1x) [1] TRUE # the above is wrong, because they actually are not the same > all.equal(attr(t0x, 'dataClasses'),
2008 Feb 13
2
apply on large arrays
I have a big contingency table, approximately of size 60*2*500*500, and I need to count the number of cells containing a count of 1 for each of the factors values defining the first dimension. Here is my attempt: tab1<-with(pisa1,table(CNT,GENDER,ISCOF,ISCOM)) tab2<-apply(tab1,1:4,function(x)ifelse(sum(x)==1,1,0)) tab3<-apply(tab2,1,sum) Computing tab2 is very slow. Is there a faster
2010 Jul 25
1
Left Outer Join 2 DF's on Multiple Conditions
Hi, I am trying to execute the following SQL statement using two data frames: tab1, tab2 : Two Tables Select tab1.*, tab2.*, tab1.tobiiTime - tab2.ruiTime as timeDiff, IFNULL(n-m, -9999999) as alwaysIncrement FROM tab1 LEFT OUTER JOIN tab2 On tab1.data1 - tab2.mouseX = 0 And tab1.data2 - tab2.mouseY = 0 I am trying to do the following in R:- *#Getting error here:* data
2013 Apr 10
6
means in tables
Hi. I have 2 tables, with same dimensions (8000 x 5). Something like: tab1: V1 V2 V3 V4 V5 14.23 1.71 2.43 15.6 127 13.20 1.78 2.14 11.2 100 13.16 2.36 2.67 18.6 101 14.37 1.95 2.50 16.8 113 13.24 2.59 2.87 21.0 118 tab2: V1 V2 V3 V4 V5 1.23 1.1 2.3 1.6 17 1.20 1.8 2.4 1.2 10 1.16 2.6 2.7 1.6 11 1.37 1.5 2.0 1.8 13 1.24 2.9 2.7 2.0 18 I need generate a table of averages, the
2006 Oct 27
3
How to best divide table by table
Hi all, how can I divide two tables of the same dimension so that all names are preserved, ie do not become NA? I have "tab1" and "tab2", each having names in the first column. I want "tab3" with the same names and values "tab1/tab2". Thanks, Serguei
2010 Apr 24
2
table command
Hi, Let s be a dataframe. > s A B C 0 0 1 1 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 0 1 1 0 0 1 > tab1=table(s[,c(1,2)]) > tab1 B A 0 1 0 3 3 1 3 0 > tab2=table(s[,c(1,3)]) > tab2 C A 1 0 6 1 3 The problem is I need to access frequency corresponding to (0,0). tab1[1] will give me the correct value
2011 Oct 29
1
Refresh tab content on click in JQuery UI Tabs
HI Guy''s TAB1 and TAB2 have some radio button, checkbox and dropdown menu. When TAB1 is selected, I have to switch to TAB2 and then back to TAB1 to refresh the loaded content. How to make TAB1 refresh loaded content when click on its tab? *code is something like that* <ul class="tabs"> <li><a *href="#tab1"*>Gallery</a></li>
2009 Dec 22
2
Nested For loops
Dear R experts, Might be very simple question to ask but would be insightful. As the same story of nested "for loops". following is the code that I am using to get the autocorrelation function of the sample data. I have tried to get rid of for loops but since I am touching R after such a long time that I need to practice more but I need help to revive my skills. I know that apply() or
2005 Jun 24
1
comparing strength of association instead of strength of evidence?
Hi, I asked this question before, which was hidden in a bunch of questions. I repharse it here and hope I can get some help this time: I have 2 contingency tables which have the same group variable Y. I want to compare the strength of association between X1/Y and X2/Y. I am not sure if comparing p-values IS the way even though the probability of seeing such "weird" observation under H0
2011 Nov 26
1
data.table merge equivalent for all.x
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2005 Nov 15
1
latex table and R codes
Dear R-help assistance; may you help me regrding to following inquiry!? you know what, i have generated three tables by xtable R function, right now i am trying to make a single table by putting these tables togethere; actully i am going to come upt with *.tex (latex) file. because i have more extera non-R material, i am using Sweave to read R instructions, and finally i hope to end up with a
2009 Aug 06
1
calasification table under conditions
hi, i have a file with 49000 lines i want to do a classification in two tables suppose data <- read.csv2("c:/total.csv", sep=",") if the second colonne contains ( A,B,C,D)------------> tab1 if the second colonne contains ( E,F,G,H)------------> tab2 How can do this ? Thank you for your help [[alternative HTML version deleted]]
2007 Jan 27
5
Prototype not processing javascript
I''m trying to change over from Rails 1.1.6 to 1.2.1 and have discovered that either something is wrong with Prototype of else something has changed that I am not aware of and cannot find documentation on. (I just joined this group, so if this has already been cussed and discussed here or in another list then please point me in the right direction.) I am trying to use the
2005 Oct 25
2
data.frame-question
Dear R-List, I am very new to R and programming itself, so my question may be easy to answer for you. I tried a lot and read through the manuals, but I still have the following problem: I have 2 data-frames: Number<-as.numeric (Number) Name<-as.character (Name) TAB1<-data.frame (Name,Number) - it looks like this:- Name Number A 2 A 3 A 6 B 8 B 12 B 7 C 8 D 90 E 12 E 45 佲仸