similar to: using newdata in survfit with categorical variable

Displaying 20 results from an estimated 500 matches similar to: "using newdata in survfit with categorical variable"

2008 Dec 15
5
how to create duplicated ID in multi-records per subject dataset
Hi R helpers, If I have a dataset looks like: ID record 1 20 . 30 . 25 2 26 . 15 3 21 4..................... And I want it becomes ID record 1 20 1 30 1 25 2 26 2 15 3 21 4..................... That is, I have to duplicate IDs for those with multiple records. I am wondering it is possible to be
2007 Mar 08
1
how to assign fixed factor in lm
Hi there, > Value=c(709,679,699,657,594,677,592,538,476,508,505,539) > Lard=rep(c("Fresh","Rancid"),each=6) > Gender=rep(c("Male","Male","Male","Female","Female","Female"),2) > Food=data.frame(Value,Lard,Gender) > Food Value Lard Gender 1 709 Fresh Male 2 679 Fresh Male 3 699 Fresh
2008 May 04
2
Ancova_non-normality of errors
Hello Helpers, I have some problems with fitting the model for my data... -->my Literatur says (crawley testbook)= Non-normality of errors-->I get a banana shape Q-Q plot with opening of banana downwards Structure of data: origin wt pes gender 1 wild 5.35 147.0 male 2 wild 5.90 148.0 male 3 wild 6.00 156.0 male 4 wild 7.50 157.0 male 5 wild 5.90
2007 Feb 24
1
Woolf's test, Odds ratio, stratification
Just a general question concerning the woolf test (package vcd), when we have stratified data (2x2 tables) and when the p.value of the woolf-test is below 0.05 then we assume that there is a heterogeneity and a common odds ratio cannot be computed? Does this mean that we have to try to add more stratification variables (stratify more) to make the woolf-test p.value insignificant? Also in the
2011 Dec 19
2
summary vs anova
Hi, I'm sure this is simple, but I haven't been able to find this in TFM, say I have some data in R like this (pasted here: http://pastebin.com/raw.php?i=sjS9Zkup): > head(df) gender age smokes disease Y 1 female 65 ever control 0.18 2 female 77 never control 0.12 3 male 40 state1 0.11 4 female 67 ever control 0.20 5 male 63 ever state1 0.16
2003 Dec 04
2
Comparing Negative Binomial Regression in Stata and R. Constants differ?
I looked for examples of count data that might interest the students and found this project about dropout rates in Los Angeles High Schools. It is discussed in the UCLA stats help pages for the Stata users: http://www.ats.ucla.edu/stat/stata/library/count.htm and See: http://www.ats.ucla.edu/stat/stata/library/longutil.htm To replicate those results, I used R's excellent foreign package to
2012 Dec 10
3
Warning message: In eval(expr, envir, enclos) : non-integer #successes in a binomial glm!
Hi there I'm trying to fit a logistic regression model to data that looks very similar to the data in the sample below. I don't understand why I'm getting this error; none of the data are proportional and the weights are numeric values. Should I be concerned about the warning about non-integer successes in my binomial glm? If I should be, how do I go about addressing it? I'm
2012 May 16
1
survival survfit with newdata
Dear all, I am confused with the behaviour of survfit with newdata option. I am using the latest version R-2-15-0. In the simple example below I am building a coxph model on 90 patients and trying to predict 10 patients. Unfortunately the survival curve at the end is for 90 patients. Could somebody please from the survival package confirm that this behaviour is as expected or not - because I
2005 Jun 15
3
Error using newdata argument in survfit
Dear R-helpers, To get curves for a pseudo cohort other than the one centered at the mean of the covariates, I have been trying to use the newdata argument to survfit with no success. Here is my model statement, the newdata and the ensuing error. What am I doing wrong? > summary(fit) Call: coxph(formula = Surv(Start, Stop, Event, type = "counting") ~ Week + LagAOO + Prior.f +
2004 Jun 14
1
olesolve: stepsize
Hi, I am doing a project on the simulation of glucose metabolism based on a pharmacokinetic modeling in which we have 4 differential equations. I did this in R by using the odesolve package. It works very well, but I have two questions: Here is the odemodel function _________________________________________________ Ogtt.Odemodel <- function(t, y, p) { absx <- c(-60, -45, -30,
2008 Feb 23
1
clarification about glm
Hello, I have a question about glm: if i have a binary covariate (unit=1,0) the reference group would be 0? (prediction for unit=1) example: dat1<-data.frame(y,unit,x1,x2) log_u <- glm(y~.,family=binomial,data=dat1) summary(log_u) Estimate Std. Error z value Pr(>|z|) (Intercept) -0.54247 0.24658 -2.200 0.0278 * unit1 -0.13052 0.22861 -0.571 0.5680 aps
2009 Jul 12
0
ERROR message while using <-invMillsRatio()
Hi I have been trying so many different things to get my Inverse Mills Ratio going for a Two stage Heckman Model, I have tried the following so far (the commands are listed below till teh point where I get an error), I get an error in the last sentence (marked in bold below), if this were successful then I could have used the IMR as a control in my OLS (which would be the OLS for the outcome
2010 Mar 17
1
constrOptim - error: initial value not feasible
Hello at all, working with a dataset I try to optimize a non-linear function with constraint. test<-read.csv2("C:/Users/Herb/Desktop/Opti/NORM.csv") fkt<- function(x){ a<-c(0) s<-c(0) #Minimizing square error for(j in 1:107){ s<-(test[j,2] - (x[1] * test[j,3]) - (x[2] * test[j,4]) - (x[3]*test[j,5]) - (x[4]*test[j,6]) - (x[5]*test[j,7]))^2 a<- a+s} a<-as.double(a)
2010 Jun 26
1
predict newdata question
Hi: I am using a subset of the below dataset to predict PRED_SUIT for the whole dataset but I am having trouble with 'newdata'. The model was created with 153 records and want to predict for 208 records. wolf2 <- structure(list(gridcell = c(367L, 444L, 533L, 587L, 598L, 609L, 620L, 629L, 641L, 651L, 662L, 674L, 684L, 695L, 738L, 748L, 804L, 805L, 872L, 919L, 929L, 938L, 950L, 958L,
2007 Jan 22
0
predict.survreg() with frailty term and newdata
It can't be done with the current code. In a nutshell, you are trying to use a feature that I never got around to coding. It's been on my "to do" list, but may never make it to the top. Terry
2012 Sep 04
1
predict rpart newdata - introduce only values variables used in the tree
Dear community, I've a tree which included at first 23 variables. Then I've pruned this tree, and there are only 8 variables involved. I'd like to predict and only introduce in newdata the values of these 8 variables involved. However, as the tree was built with the 23, it asked me for 15 values, even if it doesn't need them. Is there a way to introduce only this 8 values?
2007 Jan 22
0
[UNCLASSIFIED] predict.survreg() with frailty term and newdata
Dear All, I am attempting to make predictions based on a survreg() model with some censoring and a frailty term, as below: predict works fine on the original data, but not if I specify newdata. # a model with groups as fixed effect model1 <- survreg(Surv(y,cens)~ x1 + x2 + groups, dist = "gaussian") # and with groups as a random effect fr <- frailty(groups,
2003 Nov 11
0
Mismatches in predict(newdata)
One of the reports recently was of predict.lm misbehaving if newdata=data.frame(x=rep(NA, 10)) was given a logical column when it had been fitted as a numeric one. The exact problem was because model.matrix was trying to handle a 0-level factor (which is what that logical column got converted to by contrasts<-). However, the problem is more general and I have added to R-devel a layer of
2011 Apr 27
0
standard format for newdata objects
On Wed, 2011-04-27 at 12:00 +0200, Peter Dalgaard wrote: > Er... No, I don't think Paul is being particularly rude here (and he > has been doing us some substantial favors in the past, notably his > useful Rtips page). I know the kind of functionality he is looking > for; e.g., SAS JMP has some rather nice interactive displays of > regression effects for which you'll need to
2004 Mar 01
1
pca scores for newdata
Hi I used princomp on a dataset x[!sub,]. How can I get the scores for another dataset, say x[sub,]? I didn't succeed using predict() thanks for a hint cheers christoph -- Christoph Lehmann <christoph.lehmann at gmx.ch>