similar to: how to iterate through a list using ls

suppose I have two sets of vectors: x1,x2,...,xN and y1,y2,...,yN. I want N correlations: cor(x1,y1), cor(x2,y2), ..., cor(xN,yN). my sets of vectors are arranged as data frames x & y (vector=column): x <- data.frame(a=rnorm(10),b=rnorm(10),c=rnorm(10)) y <- data.frame(d=rnorm(10),e=rnorm(10),f=rnorm(10)) cor(x,y) returns a _matrix_ of all pairwise correlations: cor(x,y)

I need to get the names of the list elements when I iterate over a list. I'm wondering how to do so? alist=list(a=c(1,3),b=c(-1,3),c=c(-2,1)) sapply(alist,function(x){ #need to use the name of x for some subsequent process })

Dear R Users. This seems like a simple task, but I'm stuck. I have a list with 3 elements: (2 vectors and 1 matrix). I wish to extract each of these data elements using index subscripts and multiply them with a vector multiplier. What I have: > betas [1] 0.01 0.01 0.01 > LData[1] $int [1] 1 1 1 1 1 1 1 1 1 1 $date [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,]

Dear All, This is a simple question, but I'm stumped about the simplest way to search a list object such as the following: This randomish snippet: n <- c(round(runif(round(runif(1,1,10),0),1,10),0)) alist <- new("list") for (i in seq_along(n)) { alist[[i]] <- c(round(runif(round(runif(1,1,10),0),1,10),0)) } names(alist) <- sample(letters[1:length(n)]) rm(n);c(alist)

Hi All, I've been successfully using the with function for analyses and the transform function for multiple transformations. Then I thought, why not use "with" for both? I ran into problems & couldn't figure them out from help files or books. So I created a simplified version of what I'm doing: rm( list=ls() ) x1<-c(1,3,3) x2<-c(3,2,1) x3<-c(2,5,2)

On 06/22/2015 05:14 PM, Fred Smith wrote: > On Mon, Jun 22, 2015 at 03:52:17PM -0400, ken wrote: >> On 06/22/2015 02:51 PM, Fred Smith wrote: >>> On Mon, Jun 22, 2015 at 02:30:00PM -0400, ken wrote: >>>> On 06/22/2015 12:43 PM, Scott Robbins wrote: >>>>> On Mon, Jun 22, 2015 at 11:31:34AM -0400, ken wrote: >>>>>> For some reason the

Hi there, I have a multiple for loop over a list of data frames for ( i in 1:(N-1) ) { for ( j in (i+1):N ) { for ( p in 1:M ) { v_i[p] = alist[[p]][i,"v"] v_j[p] = alist[[p]][j,"v"] } rho_s = cor(v_i, v_j, method = "spearman") rho_p = cor(v_i, v_j, method = "pearson"

Hi All, I'm still pretty new to using R - and I was hoping I might be able to get some advice as to how to use 'apply' or a similar function instead of using nested for loops. Right now I have a script which uses nested for loops similar to this: i <- 1 for(a in Alpha) { for (b in Beta) { for (c in Gamma) { for (d in Delta) { for (e in Epsilon) { Output[i] <-

Hi all, I have a bunch of int vectors. Each vector holds a bunch of ints that correspond to row numbers of an existing matrix. I use the int vectors to pull out rows of data from a matrix, i.e. data <- my_matrix[int_vector,] I would like to store these int vectors in some sort of data structure that will preserve them as-is and allow iteration. I guess what I'm looking for would be

For a long time I've wanted a way to conveniently extract multiple elements from a list, which [[ doesn't allow. Can anyone suggest an efficient function to do this? Wouldn't it be a sensible addition to R? For example, alist <- list() alist[[1]] <- list() alist[[1]]$name <- "first" alist[[1]]$vec <- 1:4 alist[[2]] <- list() alist[[2]]$name <-

This seems odd. When I try to look up a list element which has a space in the name using just the first word (i.e. no spaces), it will sometimes return the element with a space in the name and sometimes it will return NULL. Try this: alist <- list( 'hello'=10, bye=20, 'hello world'=30, 'goodbye world'=40, 'hi world'=50, 'goodbye foo'=60, 'goodbye

Found it. It happens from the process buffer inside Lugaru Epsilon. I think ls thinks it's doing a DIRED output instead of a shell output. Now I need to figure out why it thinks that. This wasn't happening in CentOS 7.

On 06/22/2015 02:51 PM, Fred Smith wrote: > On Mon, Jun 22, 2015 at 02:30:00PM -0400, ken wrote: >> On 06/22/2015 12:43 PM, Scott Robbins wrote: >>> On Mon, Jun 22, 2015 at 11:31:34AM -0400, ken wrote: >>>> For some reason the "tech support" people at Hewlett-Packard don't >>>> know what the default password is to access their printer's

Hello :) I'm just starting out with R and would appreciate your help with a couple of problems I am running into. I have used Sys.glob to get a list of all filenames having a particular file extension (in my case, *.txt) I would now like to use this list in the following manner: I would like to use each filename from the list and open that file into a tab separated matrix and proceed. How can

I must set up a backup server for failover and have used tdbbackup to create backup files from the functioning primary server. I then copied the files to the backup server and used tdbbackup to restore all the databases, along with copying the smb.conf and other text files from /etc/samba. This does not seem to work and I was hoping someone could assist. Primary server is RHEL 5.4 with Samba

This is tangentially related to Hadley's question. Suppose I'm building a function programmatically; I have assembled an expression for the body and I know the names of the arguments it wants to take. Suppose I have some convenience function such that writing make_function(alist(a=, b=), quote(a+b), environment()) is equivalent to writing function(a,b) a+b So how do I make the

Dear list, I have a list of number sequences. Each number sequence has different numbers of elements. Is there a quick way (other than to iterate through the entire list) way to coerce list to matrix with NAs filling in the short sequences? An example of what I mean is this: A <- list(c(3,2,3),c(6,5)) I'd like to get A so that it is 3 2 3 6 5 NA Best, Ken

Is there a way of getting the argument list of a function from within that function? For example, something like f <- function(x, y = 3) { fargs <- getFunctionArgList() print(fargs) ## Should be `alist(x, y = 3)' } Thanks, -roger

In trying to get NULL members into a list, I found out about alist(). x<-alist() x$one<-1 x$two<-NULL but x$two doesn't exist. It seems, though, that an alist is just a list. How can one put NULL members into a list?

There are a few version of apply() (e.g., lapply(), sapply()). I'm wondering if there is one that does not return anything but just silently apply a function to the list argument. For example, the plot function is applied to each element in 'alist'. It is redundant to return anything from apply. apply(alist,function(x){ plot each element of alist})