similar to: gsubfn, strapply, REGEX Problem

Displaying 20 results from an estimated 1000 matches similar to: "gsubfn, strapply, REGEX Problem"

2008 Aug 06
2
matching problem
I have a matching problem that I cant solve. mystring = "xxx{XX}yy{YYY}zzz{Z}" where "x","X","y","Y","z","Z" basiclly can be anything, letters, digits etc. I'm only interested in the content within each "{}". I am close but not really there yet. library(gsubfn) strapply(mystring,"\\{[^\\}]+",, perl=F)
2008 Oct 20
0
New verion 0.3-7 of gsubfn package
Version 0.3-7 of the gsubfn package is available on CRAN. Changes to the package are: - all known bugs have been fixed. - in gsubfn and strapply the replacement object can be a list (or a function, formula, character string or proto object, as before). In the case of a list, regexp matches are looked up in the list names and the corresponding list component used. # Example 1 - at
2008 Oct 20
0
New verion 0.3-7 of gsubfn package
Version 0.3-7 of the gsubfn package is available on CRAN. Changes to the package are: - all known bugs have been fixed. - in gsubfn and strapply the replacement object can be a list (or a function, formula, character string or proto object, as before). In the case of a list, regexp matches are looked up in the list names and the corresponding list component used. # Example 1 - at
2006 Mar 28
0
New package gsubfn
gsubfn is a package with one function, gsubfn, that is like gsub except instead of taking a replacement string it takes a replacement function. For each match, that match is passed to the replacement function along with the backreferences, if any, and replaced with the output of the function. If the first two arguments are omitted the defaults are set to do perl-style (sort of) string
2006 Mar 28
0
New package gsubfn
gsubfn is a package with one function, gsubfn, that is like gsub except instead of taking a replacement string it takes a replacement function. For each match, that match is passed to the replacement function along with the backreferences, if any, and replaced with the output of the function. If the first two arguments are omitted the defaults are set to do perl-style (sort of) string
2007 Aug 23
2
Splitting strings
I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",
2006 Nov 29
1
Extract some character from a character vector of length 1
the content of th character vector (of length 1) is as follows: a <- "something2 ....pat1 name1 pat2 something2....pat1 name2 pat2....pat1 name3 pat2 " I would like to extract the character bewteen pat1 and pat2. That's to say, I would like to get a vecter of c("name1", "name2","name3"). What I did is use strsplit() twise. But I wonder if there
2010 Mar 15
2
tcltk and R
I have had some comments on sqldf regarding its dependence on tcltk such as the second last sentence on this blog post: http://translate.google.com/translate?hl=en&sl=zh-CN&u=http://www.wentrue.net/blog/%3Fp%3D453&prev=http://blogsearch.google.com/blogsearch%3Fhl%3Den%26ie%3DUTF-8%26q%3Dsqldf%26lr%3D%26sa%3DN%26start%3D10 sqldf does not directly use tcltk but it does use strapply in
2012 Apr 26
2
Using backreferences from node name regex match
I appears that backreferences when using regexes in node names doesn''t work. Can anyone confirm this? If I''m incorrect, how do I go about using a backreference to the name regex within the node definition container? Thanks, Guy -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To view this discussion on the web
2008 Jul 18
3
How to cut data elements included in a text line
Hello, assume I have an "unstructured" text line from a connection. Unfortunately, it is in string format: R> x [1] "\talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000" How can I extract the data included in this string object "x" in order to get the elements for the parameter vector called "alpha0", i.e. -0.638 0.4043 0.0467
2008 Jan 23
1
Package Building and Name Space
Hello, I just don't get this and would appreciate if someone could write a line or two: I'm trying to build this package and it stops installing after I add the following to the NAMESPACES file: >importFrom(gsubfn,strapply) The error during the package test is: Error in MyPackage::MyFunction : package 'MyPackage' has no name space and is not on the search path Calls:
2009 Oct 03
1
Named backreference in gsub()?
Hi, I'm running out of the *numbered* backreferences \\1, \\2, ..., \\9 for gsub(). Does R support *named* backreferences, and if so, what is the syntax? Thanks Henrik
2007 Sep 25
5
extracting data using strings as delimiters
Dear List, I have an ascii text file with data I'd like to extract. Example: Year Built: 1873 Gross Building Area: 578 sq ft Total Rooms: 6 Living Area: 578 sq ft There is a lot of data I'd like to ignore in each record, so I'm hoping there is a way to use strings as delimiters to get the data I want (e.g. tell R to take data between "Built:" and "Gross" -
2008 Jan 23
1
Package Building and Name Space
... sorry for reposting this in a more appropriate forum than r.general ... Hello, I just don't get this and would appreciate if someone could write a line or two: I'm trying to build this package and it stops installing after I add the following to the NAMESPACES file: >importFrom(gsubfn,strapply) The error during the package test is: Error in MyPackage::MyFunction : package
2023 Apr 12
1
Split String in regex while Keeping Delimiter
On Wed, 12 Apr 2023 08:29:50 +0000 Emily Bakker <emilybakker at outlook.com> wrote: > Some example data: > ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? > ?leucocyten ? grampositieve coccen +? > ? > I want to split the strings such that I get the following result: > c(?leucocyten +?, ??gramnegatieve staven +++?, > ??grampositieve staven ++?) >
2007 Mar 08
2
Named backreferences in replacement patterns
Hi I have a problem with substitutions involving named backreferences. I have a vector American.dates: > American.dates [1] "5/15/1976" "2.15.1970" "1.9.2006" which I want to change into British.dates: > British.dates [1] "15/5/1976" "15/2/1970" "9/1/2006" I know I can do it like this:
2008 Jan 18
1
Regex magic anyone?
Hi again, how to elegantly split s <- "ABCDEFGT(P)HIJK" into "A" "B" "C" "D" "E" "F" "G" "T(P)" "H" "I" "J" "K" (independently of which letters 'T' or 'P' actually represent ...). Please jumstart my regexing, Joh
2010 May 18
2
Function that is giving me a headache- any help appreciated (automatic read )
note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7
2008 Aug 12
2
perl expression question
I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be
2010 Mar 16
0
FW: How to parse a string (by a "new" markup) with R ?
A version using regular expressions, regexpr() and substr() functions is attached. Finally everything is packed into splitSeq() function (chunk 14 in the attached file) Seq<- "GCCTCGATAGCTCAGTTGGGAGAGCGTACGACTGAAGATCGTAAGGtCACCAGTTCGATCCTGGTTCGGGGCA" Str<-