similar to: count zero or one in a list

Hallo, I have an other problem, I have this vector signData with an alternation of 1 and -1 that corrispond to the duration of two different percepts. I extracted the durations like this: signData<- scan("dataTR10.txt") dur<-rle(signData)$length Now I would like to extract only the positive duration, e.g. signData <- c(1,1,1,1,-1,-1,-1,1,1,-1,-1) posduration <- c(4,2) I

Hi all, I've a vector with entries, which are all of the same type, e.g. string: k <- c("bb", "bb", "bb", "aa", "cc", "cc") and want to create a second vector containing the number of each entry in k in the same order as in k, i.e. c(3, 1, 2) or: k <- c(5,5,5,5,2,2,4) => c(4,2,1) thanks

I am trying to plot a graph but the points on the graph should be different symbols and colors. It should represent what is in the legend. I tried using the points command but this does not work. Is there another command in R that would allow me to use different symbols and colors for the points? Thank you kindly. data(mtcars) plot(mtcars$wt,mtcars$mpg,xlab= "Weight(lbs/1000)",

dear all, i'm just about to do some straightforward contingency tables using ftables (and ctab() for percents). the problem: factor "a" are regions, factor "b" are subregions. every region "a" consists of some subregions "b", but obviously not every subregion "b" is part of every region "a". if i use the ftable() function, the

Hello List, Can anybody point me to a number-to-string formatting function? I need to convert, say, 12 to 00012. I tried format() but its too stubborn: it seems to only pad with spaces. Thank you, Your culpritNr1 -- View this message in context: http://www.nabble.com/Paddding-an-integer-with-zeros-tp20095300p20095300.html Sent from the R help mailing list archive at Nabble.com.

Dear Helpers:   I spend more than half a day to solve this problem in R:   Let x be a vector of a string of 0s and 1s, such as x<-c(0,0,1,1,0,0,0,0,1,1,0,0,0,0). It can be a very long vector. How to sub vectors of 0s? In the above example, I would like get the vectors (0,0), (0,0,0,0), (0,0,0,0). I can use which(x==0) to get the index of the 0 elements, but I don't know how to get the

hey, I can not find a function for the following problem, hopefully you can help me. I have a vactor like this one v = c(NA,NA,TRUE,TRUE,NA,TRUE,NA,TRUE,TRUE,TRUE) and I would like to the TRUE values by the their "local sequence number". This means, the result should look thike this: c(NA,NA,1,2,NA,1,NA,1,2,3) Of course I could solve the problems using a loop, but this would be

All, I am constructing a pharmacokinetic dataset and have hit a snag. The dataset can be demonstrated in the following way: myData <- data.frame( evid = c(1, 0, 0, 0, 1, 0, 1, 1, 1, 0), time = 1:10, last.dose.time = c(1, 1, 1, 1, 5, 5, 7, 8, 9, 9) ) The evid field is an indicator variable for whether the associated observation is a dosing record (when it takes value 1) or an

Hi all, I am not a skillful R programmer and has I am handling with large dataframes (about 30000 x 300) I am in need of an efficient function. I have 4 dataframes with the same dimension. I need to generate other dataframe with the some dimension than the others where in each position it has the median value of the 4 values in the same position coming from the 4 dataframes. Grateful by your

something like ... > x<-c(1,2,3,0,5,6,0) > is.na(x[x==0])<-T > x [1] 1 2 3 NA 5 6 NA ~~~~~~~~~~~~~~~~ Robert Kinley ~~~~~~~~~~~~~~~~ [[alternative HTML version deleted]]

I want to create a list based on the information from a data.frame, Model. So I tried the following: MyList <- list(colnames(Model)[2] = levels(Model$(colnames(Model)[2]))) but it failed with an error: Error: unexpected '=' in "list(colnames(Model)[2] =" I have the following problems with this command line: (1) I wanted to use colnames(Model)[2] as a tag for the list:

Hi I deal with long vectors almost all of whose elements are zero. Typically, the length will be ~5e7 with ~100 nonzero elements. I want to deal with these objects using a sort of sparse vector. The problem is that I want to be able to 'add' two such vectors. Toy problem follows. Suppose I have two such objects, 'a' and 'b': > a $index [1] 20 30 100000000

Hi all, Suppose I had the below example where a survey was carried out recording the number of each type of pet in each house count<-c(2,1,2,1,2,3,4) house<-c("house1","house1","house2","house3","house4","house4","house4")

Hello, I create this array: x <- cbind(c(1:4, rep(0,10)), c(rep(0,4), 1:2, rep(3,6), 4,5)) [,1] [,2] [1,] 1 0 [2,] 2 0 [3,] 3 0 [4,] 4 0 [5,] 0 1 [6,] 0 2 [7,] 0 3 [8,] 0 3 [9,] 0 3 [10,] 0 3 [11,] 0 3 [12,] 0 3 [13,] 0 4 [14,] 0 5 I would like to do the following in vector syntax:

Hi, I have a data frame containing two columns: x<-as.factor(c('a','a','a','a','a','b','b','b','c','d','d','d')) y<-c(1,3,6,8,12,3,4,7,5,6,7,10) X<-data.frame(x,y) X x y 1 a 1 2 a 3 3 a 6 4 a 8 5 a 12 6 b 3 7 b 4 8 b 7 9 c 5 10 d 6 11 d 7 12 d 10 I would like to

Hi list I loaded the content of a file dureetasks.txt to variable a. This file contains an interger per line. when I print a vector, it displays correctly. however, when I try to print the histogram, I get this error message > a=read.table("dureetasks.txt") > hist(a) Error in hist.default(a) : 'x' must be numeric Can you help please? regards -- PhD candidate in

Dear all, I am looking for a function to count values belonging to a class within a dataframe (and ignore NAs). grp = c(1,1,1, 1,2, 2,2) val = c(2,1,5,NA,3,NA,1) dta = data.frame(grp=grp, val=val) The result should look like: grp count 1 3 2 2 At the moment, I am trying to find a function for FUN in aggregate, but with no success. Can anybody help me? Thanks in advance. Marcus

Hi, Is there are function similar to excel vlookup in R. Please let me know. Thanks, Sachin ____________________________________________________________________________________ [[alternative HTML version deleted]]

R-helpers, Below is a simple example of some output that I am getting while trying to work with a data frame in R 2.12.1 for Mac. ----- > testdat <- data.frame(matrix(ncol=10, nrow=10)) > colnames(testdat) <- c('a','b','c','d','e','f','g','h','i','j') > testdat[seq(1,10,3),] <-

Hi, I am trying to plot two distribution graph on one plot. But I dont know how. I set them to the same x, y limit, even same x, y labels. Code: x1=rnorm(25, mean=0, sd=1) y1=dnorm(x1, mean=0, sd=1) x2=rnorm(25, mean=0, sd=1) y2=dnorm(x2, mean=0, sd=1) plot(x1, y1, type='p', xlim=range(x1,x2), ylim=range(y1, y2), xlab='x', ylab='y') plot(x2, y2, type='p',