similar to: Request: Most repeated sequence considering combinations at each row

Dear Petr Thanks for the response. Hope it will now help me to proceed. best regards M.Azam ________________________________ From: Petr PIKAL <petr.pikal@precheza.cz> Cc: R Help <r-help@r-project.org>; r-help-bounces@r-project.org Sent: Monday, October 27, 2008 8:43:27 AM Subject: Odp: [R] Request: Most repeated sequence considering combinations at each row Hi not sure if this is

Hi there, According to ?par, 'font' is an integer which specifies which font to use for text, that 1 corresponds to plain text (the default), 2 to bold face, 3 to italic and 4 to bold italic. When I test Chinese character in pdf(), I found that 1 to bold face, 2 to italic, 3 to bold italic, 4 to symbol. and I don't find how to set plain text. In the following code, the font to use

Dear all, I''d like to ask help on R code to get the same results as the following Splus code: >indata<-importData("/home/data_new.csv") >indata[1:5,4] [1] 0930 1601 1006 1032 1020 I tried the following R code: > indata<-read.csv("/home/data_new.csv") > indata[1:5,4] [1] 930 1601 1006 1032 1020 I''d like the first

(Frenchy, sorry =) ) Hi everyone, i''ve got some troubles with aggregated attribute. I created a point and path class which receive postgresql point and path type data. Path object contains an array of point object. I''m currently working on a "hunting" module in web browser based game, and i need a crontab executed every n minutes to move the character on the map.

Hi all Can anybody help me with this? I am trying to include in an automatic way the argument in arg.names in a barplot. I generate the labels I want to appear below the bars with a for loop, and they contain subscripts, so I need to use expression anch<-0.05 esp<-4 for (i in 1:dim(Ntot)[1]) { naux<-Ntot[i,] naux2<-naux[naux>0] nind<-which(naux>0)

Dear R-list members, I would like to pose a question about the use and results of the glm() function for logistic regression calculations. The question is based on an example provided on p. 229 in P. Dalgaard, Introductory Statistics with R, 2nd. edition, Springer, 2008. By means of this example, I was trying to practice the different ways of entering data in glm(). In his book, Dalgaard

Hi R-users, I have a list a <- list(one=matrix(rnorm(20), 5, 4), two=matrix(rnorm(20, 3, 0.5),5,4)) How to add rowSums (calculated using lapply) to corresponding matrix in this list lapply(a, function(x) rowSums(x)) ?? -Lauri

Dear friends, I was drawing a circle with centrum in (1,-1) and radius 5 to show my girl that the line y=3*x+1 goes through (1,4) and (-2,-5) of the circle, but on Windows XP, R 2.20 the drawing was not good at all, and the known solutions were not shown in the graph. I guess I got it wrong? Is this use not intended ? Best wishes Troels Ring, MD Aalborg, Denmark

Hi, I have a matrix not unlike this: foo <- matrix(,5,5) foo[5,1] <- 1 foo[1:3,2] <- 1 foo[3:4,3] <- 1 foo[4:5,4] <- 1 foo[2:4,5] <- 1 foo [,1] [,2] [,3] [,4] [,5] [1,] NA 1 NA NA NA [2,] NA 1 NA NA 1 [3,] NA 1 1 NA 1 [4,] NA NA 1 1 1 [5,] 1 NA NA 1 NA I want to get a vector that is the column numbers as sorted

I'm trying to assign NAs to values that satisfy certain conditions (more complex than shown below) and it gives the right result, but breaks the loop having done the first one viz: new<-c(rep(5,4),6) for (i in 1:6) {new[new[i]>5.5][i]<-NA} gives the correct result, though an error message appears which causes a break if it's in a loop. If I can get rid of the error message and

Hi ,everyone. I want to draw a boxplot figure, main script shown as below. when I run the command "boxplot(bjavee~yearname)",it is wrong with the error information " model.frame.default(formula = bjavee ~ yearname) : variation 'bjavee' list is wrong". I want to add the yearname as the x-axis tick. And yearname is a array with the length 12,while bjavee is a 5*12

Hi all, I have one question on xyplot() function. I am trying to produce a graph by this code. tmp <- data.frame(a=rnorm(20), b=rnorm(20), rho=factor(rep(1:2, c(10,10))), k=factor(rep(1:5,4))) tmp.lattice <- xyplot(a ~ b | rho*k, data=tmp, par.strip.text=list(font=5), strip=function(...) strip.default(...,

Dear all, 'Apply' is a great thing for running functions on rows or columns of a matrix: X <- rnorm(20, mean = 0, sd = 1) dim(X) <- c(5,4) apply(X,2,sum) Is there a way to use apply for excluding rows or columns from a matrix to run functions on the remaining rows or columns? I know, I could do this with a 'for' loop, but 'apply' would be much easier and

Dear helpeRs, I have a dataframe (14947 x 27) containing measurements collected every 5 seconds at several different sampling locations. If one measurement at a given location is less than zero on a given day, I would like to delete all measurements from that location on that day. Here is a toy example: toy <- data.frame(CH = rep(3:5,3), DAY = c(rep(4,5), rep(5,4)), SLOPE =

somfunc<- function (file) { aa_som<-scale(file) final.som<-som(data=aa_som, rlen=10000, grid=somgrid(5,4, "hexagonal")) pdf(file="/home/cdu/changbin/file.pdf") #output graphic file. plot(final.som, main="Unsupervised SOM") dev.off() } I have many different files, if I want output pdf file with the same name as for each dataset I feed to the function

I thought I've understood the 'order' function, using simple examples like: order(c(5,4,-2)) [1] 3 2 1 However, I arrived to the following example: order(c(2465, 2255, 2085, 1545, 1335, 1210, 920, 210, 210, 505, 1045)) [1] 8 9 10 7 11 6 5 4 3 2 1 and I was completely perplexed! Shouldn't the output vector be 11 10 9 8 7 6 4 1 2 3 5 ? Do I have a damaged

Dear R-users, Suppose I have the following x-y coordinates which give the boundaries of a polygon: > x <- c(5,4,5,9,6,6,4,7,10,7,10,4,10) > y <- c(6,3,2,6,3,7,5,4,4,7, 5,4, 6) I would like to plot the following graph: > plot(x,y) > ord <- c(7,12,2,3,5,8,9,11,13,4,10,6,1) > polygon(x[ord],y[ord]) How I can obtain the above ordering (in the example an anti-clockwise

I am trying to learn R right now. I came from minitab and wanted to learn something a bit more robust. I am trying to figure out some simple probability to measures but I do not know the commands. I am using OSX. Are there resources for figuring out simple events? If I have data distributed as Normal(5,4) and I wanted to know what the probability of P(<6) would be this, I cannot quite

Hello! I got something to ask..whether you can help me with the R program...i got this for example 5x4 matrix..and i want to find: ?i) mean for each row of the matrix ii) median for each column of the matrix and i need to do this using a loop function...below is my program..u try to check it for me as the output that i got is not what i desired...thanks.. data<-rnorm(20,0,1)

Simple problem but I don't see the answer. I'm trying to clean up some data I have 120 columns in a data.frame. I have one value in a column named "blaw" that I want to change. How do I find the coordinates. I can find the row by doing a subset on the data.frame but how do I find out here "blaw " is in columns without manually counting them or converting names(Df) to a