similar to: Categorial Response Questions

Dear all, I need to clean up one variables in a dataset. e.g. lets say the dataset is "trial", the variable for cleaning up is "V1" >trial$V1 [1] 0(a=1) 0(b=1) 0.133(b=1) 0.555(a=1) >5.32(a=1) what i need to do is to remove the text (a=1) and (b=1) and the ">" in the V1, and then convert to a numeric variable, and als I am aslo requested that when the

Hi all, I have a queston about Categorical response. i have a data frame containing age, sex, class, success(1=success, 0=non sucess). age, sex,class are the explantory variables, and sucess is the response variable. and i can get n (the nunber of times each age occurs) and r (the number of sucess of that age). when I try to creat the regression relationship for these variables, I have seen

Hi, I am a long time SPSS user but new to R, so please bear with me if my questions seem to be too basic for you guys. I am trying to figure out how to analyze survey data using logistic regression with multiple imputation. I have a survey data of about 200,000 cases and I am trying to predict the odds ratio of a dependent variable using 6 categorical independent variables (dummy-coded).

Hi all, I am kind of stuck of using Predict function in R to make prediction for a model with continuous variable and categorial variables. i have no problem making the model, the model is e.g. cabbage.lm2<- lm(VitC ~ HeadWt + Date + Cult) HeadWt is a continuous variable, Date and Culte are factors. Date have three levels inside (d16,d20,d21), Cult has two levels(c39,c52). I need to

Dear Dr Hornik / R help list, I am using the mda package and in particular the fda routine to classify a set of 162 neurons falling in to 11 neuronal cell types according to 17 morphological variables. I would like to use a cross-validation approach in which I split the data, train with one part amd then test the predictive accuracy of the discriminant functions with the remaining part. However

Hi there fellow R users, R has many different clustering packages (e.g. mclust,cluster,e1071). However, can anyone recommend a method to deal with data sets that contain categorial and continuous variables? Regards Wayne KSS Ltd Seventh Floor St James's Buildings 79 Oxford Street Manchester M1 6SS England Company Registration Number 2800886 Tel: +44 (0) 161 228 0040 Fax: +44 (0)

Dear all, in a previuos message was asked how get the mode of continous distribution. Now I'm asking if there an R function to obtain the mode in case of a discrete distribution or categorial data. The only way is to use table(): > x<-rep(1:5,100) > s<-sample(x,40) > t<-table(s) > t s 1 2 3 4 5 13 10 5 4 8 the mode is value=1 Thanks Cordially Vito =====

Signed-off-by: Ilia Mirkin <imirkin at alum.mit.edu> --- nouveau/nouveau.c | 29 ++++++++++++++++++++++++++++- nouveau/private.h | 3 ++- 2 files changed, 30 insertions(+), 2 deletions(-) diff --git a/nouveau/nouveau.c b/nouveau/nouveau.c index ee7893b..72c31cf 100644 --- a/nouveau/nouveau.c +++ b/nouveau/nouveau.c @@ -85,6 +85,12 @@ nouveau_device_wrap(int fd, int close, struct

Dear R-List, I would like to recode categorial variables into binary data, so that all values above median are coded 1 and all values below 0, separating each var into two equally large groups (e.g. good performers = 0 vs. bad performers =1). I have not succeeded so far in finding a nice solution to do that in R. I thought there might be a better way than ordering each column and recoding the

Dear R-List, I would like to recode categorial variables into binary data, so that all values above median are coded 1 and all values below 0, separating each var into two equally large groups (e.g. good performers = 0 vs. bad performers =1). I have not succeeded so far in finding a nice solution to do that in R. I thought there might be a better way than ordering each column and recoding the

Thanking John for his suggestion I build this function which get the mode of both categorial and discrete data. Mode<-function(x){t<-table(x) if (is.numeric(x)) as.numeric(names(t)[t == max(t)]) else (names(t)[t == max(t)]) } Any other improvement and suggestion will welcome. Best Vito > s [1] 1 1 6 1 1 7 6 5 6 2 1 4 5 6 6 7 3 5 4 1 7 3 7 3 3 7 7 2 1 4 4 2 7 7 6 6 1 2 [39] 5 1 7 7

Hello again, everytime I think I got something to work, the next issue comes up... I have the following data.frame, I want to visualize: > data_rb tld spam1 spam2 share 1 ca 826436 73452 0.0889 2 org 470550 25740 0.0547 3 de 156042 15531 0.0995 4 com 140753 7527 0.0535 5 edu 34845 2507 0.0719 6 net 12781 382 0.0299 7 ru 7648 18 0.0024

Hello List, I am having a great trouble using svm function in e1071 package. I have 4gb of data that i want to use to train svm. I am using Amazon cloud, my Amazon Machine Image(AMI) has 34.2 GB of memory. my R process was killed several times when i tried to use 4GB of data for svm. Now I am using a subset of that data and it is only 1.4 GB. i remove all unnecessary objects before calling

Dear Fil, I am not sure if my answer can help you. I had ever asked a similar question to Daniel and I was using a thirty-party card. As a container uses a shared kernel with the host, so hostdev mode='subsystem' doesn't make sense. Maybe you can try to use hostdev mode='capabilities'. Please see http://libvirt.org/formatdomain.html#elementsHostDevCaps Hope this helps Cheng

From: Ben Skeggs <bskeggs at redhat.com> The latter is deprecated, and will not be valid for newer clients. Signed-off-by: Ben Skeggs <bskeggs at redhat.com> --- nouveau/abi16.c | 32 +++++++++++++++----------------- nouveau/nouveau-symbol-check | 1 - nouveau/nouveau.c | 43 +++++++++++++++++++++---------------------- nouveau/nouveau.h | 1 -

I have some data I would like to model which involves choice of food by dung beetles. There are a number of experiments where in each case, there are five choices. Overall there are more than 5 different foods being compared (including a placebo) and different experiments use different comparisons. The problem is a generalization of Bradley-Terry but it differs from some generalizations in

This hides all the abi16_* functions and the nouveau_debug variable, they should have been private to begin with. Signed-off-by: Maarten Lankhorst <maarten.lankhorst at canonical.com> --- nouveau/Makefile.am | 1 + nouveau/bufctx.c | 10 +++++----- nouveau/nouveau.c | 40 ++++++++++++++++++++-------------------- nouveau/private.h | 1 + nouveau/pushbuf.c | 20

From: Ben Skeggs <bskeggs at redhat.com> This commit also modifies the install path of the main libdrm_nouveau header to be under a nouveau/ subdirectory. Signed-off-by: Ben Skeggs <bskeggs at redhat.com> --- include/drm/nouveau_drm.h | 1 + nouveau/Makefile.am | 11 +++- nouveau/libdrm_nouveau.pc.in | 2 +- nouveau/nvif/cl0080.h | 45 ++++++++++++++

you can go to http://www.tmtm.org/en/ruby/mysql/ to download the tar file, and run the command below # ruby ./install.rb to install the mysql.rb -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to

From: Ben Skeggs <bskeggs at redhat.com> Signed-off-by: Ben Skeggs <bskeggs at redhat.com> --- nouveau/abi16.c | 62 ++++++++++++++++++++++++++++++++++++++++++++++++++----- nouveau/nouveau.c | 56 +++++++------------------------------------------ nouveau/private.h | 7 ++----- 3 files changed, 67 insertions(+), 58 deletions(-) diff --git a/nouveau/abi16.c b/nouveau/abi16.c index