similar to: YALAQ - Yet Another LApply Question

Hello, I'm trying to convert a character column in several dataframes to lower case. ### # # Sample data and 'spp' column summaries: # dput(ban.ovs.1993[sample(row.names(ban.ovs.1993), 20), 1:4]) ban.ovs.93 <- structure(list(oplt = c(43L, 43L, 38L, 26L, 35L, 8L, 39L, 1L, 34L, 50L, 10L, 29L, 31L, 24L, 18L, 12L, 27L, 49L, 28L, 51L), rplt = c(NA_integer_, NA_integer_,

Good Morning, I am trying to create a new column of character strings based on the first two letters in a string in another column. I believe that I need to use some combination of ifelse and grep but I am not totally sure how to combine them. I am not totally sure why the command below isn't working. Obviously it isn't finding anything that matches my criteria but I am not sure why. Any

Hello, I have a set of one-liners (many thanks to previous responses from this list) that I use to look at newly imported data sets with functions like dim(), names(), str(), etc. within lapply(). Generally, these commands work for me but, I am apparently still missing some aspect of list manipulation. I don't understand why I get a set of NULL list elements at the end of each output as

Modern distributions are moving toward a common boot scheme called "The Boot Loader Specification". This patch enables syslinux to parse the drop-in files that are defined by this new specification. Link to documentation of the options added to syslinux by this patch: https://drive.google.com/uc?export=download&id=1nuRISVJeE1whYggFURywoQFpPzc6s1MC MD5 (syslinux-bls1.txt) =

Modern distributions are moving toward a common boot scheme called "The Boot Loader Specification". This patch enables syslinux's (vesa)menu.c32 modules to parse the drop-in files that are defined by this new specification. Link to The Boot Loader Specification: https://systemd.io/BOOT_LOADER_SPECIFICATION Link to demonstration bootdisk image (82MB gzipped):

hi again, i still cannot open the file in spss :( i type: library(foreign) read.spss("H:\\Desktop\\bd1\\experiencia1") and the error comes: Error in read.spss("H:\\Desktop\\bd1\\experiencia1") : unable to open file can you help me? margarida,portugal

hi, i can?t download a file in access. when i type: > library(foreign) > read.spss("H:\Desktop\bd1\experiencia1") comes the error: Error in read.spss("H:Desktop\bd1experiencia1") : unable to open file do you know what is the problem? can you help me? margarida,porto,portugal

Muchas gracias, pero claro en una muestra de 50 datos se ejecuta, en la muestra original de 1000 registros me tira error :( 2013/10/30 daniel <daniel319@gmail.com> > Amalia, > > No obtengo tus resultados. Corrí tus formulas y datos y el resultado es > x <- structure(list(ï..psraid = c(202517L, 202518L, 202520L, 202523L, > + 202527L, 202537L, 202543L, 202544L, 202551L,

Dear all; What can be wrong with this simple example? library(boot) d1<-c(rnorm(10,mean=10)) fm<-function(d,i) mean(d[i]) bd1<-boot(d1,fm,10000) > Error: evaluation nested too deeply: infinite recursion / options(expressions=)? Thanks for any idea

Saludo gente, antes que nada gracias por la ayuda que puedan aportarme, soy iniciante en R, estoy usando el paquete Mice para realizar imputaciones múltiples sobre variables en su mayoría categóricas. El problema está que cuando expresó este comando imp <- mice(dataset,method="polr",maxit=1) donde el dataset es un data.frame me tirá este error : iter imp variable 1 1 pial1a

Hi I'm trying to extract complete rows from a dataframe by group based on the maximum in a column within that group. Thus I have a dataframe: cvd_basestudy ... es_time ... _____________ study1 ... 0.3091667 study2 ... 0.3091667 study2 ... 0.2625000 study3 ... 0.3033333 study3 ... 0.2625000 __________ etc I can extract the basestudy and the max(es_time)

I am trying to set up a data set for a survival analysis with time-varying covariates. The data is already in a long format, but does not have a variable to signify the stopping point for the interval. The variable DaysEnrolled is the variable I would like to use to form this interval. This is what I have now: ID Age DaysEnrolled HAZ WAZ WHZ Food onARV

Hello, I''m new to Ruby on Rails. I am creating a form for searching purpose: <% form_for :src_cond, :url => {:action =>''search''} do |p| %> <%= p.radio_button("bd", "1") %> a <%= p.radio_button("bd", "2") %> b <%= p.select :bd2, %w[1 2 3 4],{},{:index=>nil} %> <%=

I'm trying to populate the column ?pf_mcl? in myDF1 with values from myDF2, where rows match based on column "studyno" but the solutions I have found so far don't seem to be giving me the desired output. Below is a snapshot of the data.frames. myDF1 <- structure(list(studyno = c("J1000/9", "J1000/9", "J1000/9", "J1000/9",

Hello, Try the following. myDF1$studyno <- as.character(myDF1$studyno) myDF2$studyno <- as.character(myDF2$studyno) i1 <- which(names(myDF1) == "pf_mcl") merge(myDF1[-i1], myDF2, by = "studyno") Hope this helps, Rui Barradas Em 13-10-2017 20:09, Kevin Wamae escreveu: > I'm trying to populate the column ?pf_mcl? in myDF1 with values from myDF2, where rows

?merge Bert On Oct 13, 2017 12:09 PM, "Kevin Wamae" <KWamae at kemri-wellcome.org> wrote: > I'm trying to populate the column ?pf_mcl? in myDF1 with values from > myDF2, where rows match based on column "studyno" but the solutions I have > found so far don't seem to be giving me the desired output. > > Below is a snapshot of the data.frames. >

Your example used one distinct studyno in DF1 and one distinct pf_mcl in DF2. I think that makes it hard to see what is going on, but maybe I completely misunderstand the problem. In any case, let's redefine myDF1 and myDF2. Note that myDF1 contains a studyno not in myDF2 and vice versa. myDF1 <- structure(list(studyno = c("J1000/9", "J895/7", "J931/6",

Dear @Bert Gunter<mailto:bgunter.4567 at gmail.com>, I tried merge and I faced many challenges. @Rui Barradas<mailto:ruipbarradas at sapo.pt> solution is working. From: Bert Gunter <bgunter.4567 at gmail.com> Date: Friday, 13 October 2017 at 22:44 To: Kevin Wamae <KWamae at kemri-wellcome.org> Cc: R-help <R-help at r-project.org> Subject: Re: [R] Populate one data

>>>>> Martin Maechler >>>>> on Fri, 11 Jan 2019 09:44:14 +0100 writes: >>>>> Michael Chirico >>>>> on Fri, 11 Jan 2019 14:36:17 +0800 writes: >> Identified as root cause of a bug in data.table: >> https://github.com/Rdatatable/data.table/issues/3267 >> On my machine, strtoi("", base =

Dear @Rui Barradas, thank you for the solution. It works perfectly. On 13/10/2017, 23:35, "Rui Barradas" <ruipbarradas at sapo.pt> wrote: Hello, Try the following. myDF1$studyno <- as.character(myDF1$studyno) myDF2$studyno <- as.character(myDF2$studyno) i1 <- which(names(myDF1) == "pf_mcl") merge(myDF1[-i1], myDF2,