similar to: Lattice question: plotting two sets of data, defining groups for the second set

Hi R community, I'm running R 2.7.2 on Windows XP SP2. I'm trying to (1) plot loess lines for each of my groupings using the same color for each group; (2) plot loess predicted values. The first part is easy: data1 <- data.frame(Names=c(rep("Jon",9),rep("Karl",9)),Measurements=c(2,4,16,25,36,49,64,81,100,1,2,5,12,17,21,45,54,67),PlotAt=c(1:9,1:9)) data2 <-

R Friends, I'm running R2.7.1 on Windows XP. I'm trying to get some lattice functionality which I have not seen previously documented--I'd like to plot the exact same data in multiple panels but changing the grouping variable each time so that each panel highlights a different feature of the data set. The following code does exactly that with a simple and fabricated air quality data

Since installing R 2.14.0 on my Mac (a Mac Pro running 10.6.8) an issue has arisen when using the vi editor in conjunction with the edit() command. More specifically, commented lines disappear from edited functions when using [functionname.R] <- edit(). That is, if you have created a function called “test.func” as such: function () { # This is a test ex _ 4 duh <- seq(1, 10) fuh

Dear R users: I want to have in the same column both symbols, line and points, one for a data, and the other for the model. How can I do that? Or is there other better form to show both data and model in the same graphic? I need to make the difference on time of the same subject (repeated measurements on time) Problem example: ###########################################################

Hi Rusers, I found sometimes that the same values cannot be judged to be the same in R. Anybody knows the probelm? I think i ignored some minor detail. Thanks. Here is the example. ############ data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)

Dear Rui; Many thanks for your email. I used one of your codes, "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works correctly for me. Actually I need to expand the codes so as to consider all "Levels" in the "Layer" column. There are more than hundred levels in the Layer column. If I use your provided code, I have to write it

?s 21:05 de 11/06/2023, javad bayat escreveu: > Dear R users; > I am trying to fill a column based on a specific value in another column of > a dataframe, but it seems there is a problem with the codes! > The "Layer" and the "LU" are two different columns of the dataframe. > How can I fix this? > Sincerely > > > for (i in 1:nrow(data2$Layer)){ >

?s 22:54 de 11/06/2023, javad bayat escreveu: > Dear Rui; > Many thanks for your email. I used one of your codes, > "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works > correctly for me. > Actually I need to expand the codes so as to consider all "Levels" in the > "Layer" column. There are more than hundred

Dear all I need some help with R. How can I save the estimates of a regression model in a file? here is what I did: 1) this is my regression model: fit1 <- lm(logmilk ~ logdays + days, data=data2) 2) however, I want to get the parameters estimates for each individual (by group): so i did the following: by(data2, list(data2$V2),function(.data2) lm(logmilk ~ logdays + days, data= .data2)) 3)

At one time (version 1.7), the code below used to work for converting and extracting based on the Date Time. In version 1.8.1, something changed I know, but I cannot for the life of me figure out what... Data: UserName,RequestDate,PO,OrderDate,ExpDelivDate,Vendor,Total "Woody, Jim",12/19/2002,AP15063,1/7/2003,2/10/2003,Ames ,8570 "Harrold,

Hello All, Many thanks to the help I have received so far. Here is an example data set I hope to plot Data1 Year Data SE 1 2005 2 0.01 2 2006 4 0.01 3 2007 5 0.01 4 2008 2 0.01 5 2009 3 0.01 6 2010 6 0.01 Data2 Year Data SE 1 2006 32 1 2 2007 100 2 3 2008 60 4 4 2009 67 3 5 2010 8 1 Notice Data2 has one less years worth of data than Data1 (which is my

Dear R users; I am trying to fill a column based on a specific value in another column of a dataframe, but it seems there is a problem with the codes! The "Layer" and the "LU" are two different columns of the dataframe. How can I fix this? Sincerely for (i in 1:nrow(data2$Layer)){ if (data2$Layer == "Level 12") { data2$LU == "Park"

I have two set of data, Data1 and Data2 . Data1 has a header and Data2 does not. I would like to merge the two data sets after removing some columns from data2 . I am having a problem merging so I had to write and read final data and specify the ?header=F? so the merge can be done by?V1?. Is there a way to avoid this step. The problem is when I do cbind the FinalData has different column names

Hi, I'm quite new using R and have got no one to help me get through it. Hopefully someone can help me with one problem I've been struggling with for the last hours!! (Sorry if I'm using the wrong terminology as well!) I have a data matrix in which SIE is one of my variables. What I need to do now is to create a new variable (group) if a certain condition in SIE is met. I tried:

Hello R community, I am trying to combine two CSV files that look like this: File A Row_ID_CR, Data1, Data2, Data3 1, aa, bb, cc 2, dd, ee, ff File B Row_ID_N, Src_Row_ID, DataN1 1a, 1, This is comment 1 2a, 1, This is comment 2 3a,

From: David Winsemius <dwinsemius at comcast.net> On Jul 16, 2011, at 12:15 PM, Rory Campbell-Lange wrote: > On 16/07/11, David Winsemius (dwinsemius at comcast.net) wrote: >> >> On Jul 16, 2011, at 11:19 AM, Rory Campbell-Lange wrote: >> >>> I'm an R beginner, and I would like to construct a set of boxplots >>> showing database function runtimes.

#I have a data frame with a numeric and a character variable. x=c(1,2,3,2,0,2,-1,-2,-4) md=c(rep("Miller",3), rep("Richard",3),rep("Smith",3)) data1=data.frame(x,md) #I subset this data.frame in a way such that one level of the character variable does not appear in the new dataset. data2=data1[x>0,] data3=subset(data1,x>0) #However, when I check the levels

Using R 2.6.2, say I have the following list of lists, "comb": data1 <- list(a = 1, b = 2, c = 3) data2 <- list(a = 4, b = 5, c = 6) data3 <- list(a = 3, b = 6, c = 9) comb <- list(data1 = data1, data2 = data2, data3 = data3) So that all names for the lowest level list are common. How can I most efficiently access all of the sublist items "a" indexed by the outer

Hello, I am trying to match lat/lon from one dataset with the lat/lon from a second dataset and use that rows data for calculations. I am using match, but this is finding the first match and not comparing the pair, how can I determine if the lat/lon are the same? See example below. Is there a better way to determine to a matching pair of lat/lon values? Example Datasets: > data2

Morning All! Anyone ever tried exporting a StorNext CVFS filesystem from a Linux box??? I?ve got this Samba server (3.5.6) running on CentOS 5.4 and it?s working fine, exporting ext3, nfs and an IBM GPFS filesystem just fine. So I know Samba is good an my configuration is working. I tried to add the exportation of a StorNext CVFS volume and that doesn?t work. All the other volumes still work