similar to: read.spss: variable.labels

** High Priority ** I have been trying to read an SPSS file into R using read.spss ("C:/Documents and Settings/Roderick Harrison/My Documents/RWORK/ihisdat.sav", use.value.labels = TRUE, to.data.frame = FALSE, max.value.labels = 500, trim.factor.names = FALSE, trim_values = TRUE, reencode = NA, use.missings = to.data.frame) Each time (at least 5 or 6 by now) I get the following

Hi dear all, I am trying to import a dataset from SPSS into R (R x64 2.15.0). I used both   read.spss("D:/Untitled2.sav", use.value.labels = TRUE, to.data.frame = TRUE, max.value.labels = Inf, trim.factor.names = FALSE,trim_values = TRUE, reencode = NA, use.missings = to.data.frame) & read.spss("D:\\Untitled2.sav", to.data.frame = TRUE, stringsAsFactors = FALSE)   but the

r11 -- r16 are variables showing a reason for usage of a product in 6 different situations. Each variable is a factor with 4 levels imported from a SPSS sav file with labels ranging from "not important" to "very important", and NA's for a sample of N = 276. (1) I need a chi square test of independence showing that the reason does not differ depending on the

SPSS seems to have changed its default datafile format, resulting in issues for read.spss(). In Windows this results in a warning, in Debian the import completely fails: Debian (R version 2.8.0 (2008-10-20) i486-pc-linux-gnu, foreign_0.8-29) > read.spss("/home/jeroen/samples/Tomato.sav") Error in iconv(names(rval), cp, "") : unsupported conversion from 'CP65001'

I have created a function to do something: i <- factor(sample(c("A", "B", "C", NA), 793, rep=T, prob=c(8, 7, 5, 1))) k <- factor(sample(c("X", "Y", "Z", NA), 793, rep=T, prob=c(12, 7, 9, 1))) mytable <- function(x){ xtb <- x btx <- x # do more with x, not relevant here cat("The table has been created,

Hi, I have one doubt about one of the parameter of 'read.spss()' from 'foreign' package. Here is the syntax :- read.spss ( file, use.value.labels = TRUE, to.data.frame = FALSE, max.value.labels = Inf, trim.factor.names = FALSE, trim_values = TRUE, reencode = NA, use.missings = to.data.frame ) In above syntax when I pass *'to.data.frame=

### example:start v <- sample(rnorm(200), 100, replace=T) k <- rep.int(c("locA", "locB", "locC", "locD"), 25) tapply(v, k, summary) ### example:end ... (hopefully) produces 4 summaries of v according to k group membership. How can I transform the output into a nice table with the croups as columns and the interesting statistics as lines? Thx,

A Likert scale may have produced counts of answers per category. According to theory I may expect equality over the categories. A statistical test shall reveal the actual equality in my sample. When applying a chi square test with increasing number of repetitions (simulate.p.value) over a fixed sample, the p-value decreases dramatically (looks as if converge to zero). (1) Why? (2) (If

I must be missing something obvious here: According to the help page for read.spss, the reencode option is only active when R is run under a UTF-8 locale. read.spss can only import the SPSS file when run under a iso88591(5) locale, under a UTF-8 locale I get: Error in read.spss("wo.sav") : error reading system-file header In addition: Warning message: In read.spss("wo.sav")

Dear R-users, I'm facing a problem with the import of data in R. I have a sav file that, I presume, uses some Arabic encoding (but I don't know which one) and I would like to read it with R. When I use the function read.spss (I also tried spss.get(Hmisc)), I get the following message: > read.spss("Hhld.sav") Erreur dans read.spss("Hhld.sav") : erreur ? la lecture

Hi, after updating to foreign version 0.8-32, I experienced the following error when I tried to load a SPSS file: Fehler in inherits(x, "factor") : objekt "cp" nicht gefunden Zus?tzlich: Warning message: In read.spss("***l.sav", use.value.labels = TRUE, to.data.frame = TRUE) : ***.sav: File-indicated character representation code (1252) looks like a Windows

Dear R users, I am trying to get R to read an .sav data file generated in SPSS 17 for Mac. Here is the command and the error message: > data = read.spss('/Users/userdir/Desktop/filename.sav') Error in iconv(names(rval), cp, "") : unsupported conversion In addition: Warning message: In read.spss("/Users/userdir/Desktop/filename.sav") :

How to I "recode" a factor into a binary data frame according to the factor levels: ### example:start set.seed(20) l <- sample(rep.int(c("locA", "locB", "locC", "locD"), 100), 10, replace=T) # [1] "locD" "locD" "locD" "locD" "locB" "locA" "locA" "locA"

A list contains several matrices. Over all matrices (list elements) I'd like to access one matrix cell: m <- matrix(1:9, nrow=3, dimnames=list(LETTERS[1:3], letters[1:3])) l <- list(m1=m, m2=m*2, m3=m*3) l[[3]] # works l[[3]][1:2, ] # works l[[1:3]][1, 1] # does not work How can I slice all C-c combinations in the list? S?ren -- S?ren Vogel, Dipl.-Psych. (Univ.), PhD-Student, Eawag,

New to R, can't afford SPSS! Why can't I assign spss variables? Here are the details. > ### I've read in my collaborator's sav file using read.spss, eg > children = read.spss(filename) > ### It has many variables > length(children) [1] 347 > ### and I would like to assign individual variables. > ### I can of course type out all the ones I want, eg >

Hi, y is nominal (3 categories), x1 to 3 is scale. What I want is a regression, showing the probability to fall in one of the three categories of y according to the x. How can I perform such a regression in R? Thanks for your help S?ren

Hello, I read the help as well as the examples, but I can not figure out why the following code does not produce the *given* row names, "x" and "y": x <- 1:20 y <- 21:40 rbind( x=cbind(N=length(x), M=mean(x), SD=sd(x)), y=cbind(N=length(y), M=mean(y), SD=sd(y)) ) Could you please help? Thank you S?ren

Hello, how can I return the name of a variable, say "a$b", from a function? fun <- function(x){ return(substitute(x)); } a <- data.frame(b=1:10); fun(a$b) ... returns a$b, but this is a type language, thus I can't use it as a character string, can I? How? Thanks for help, S?ren

A dataframe holds 3 vars, each checked true or false (1, 0). Another var holds the grouping, r and s: ### start:example set.seed(20) d <- data.frame(sample(c(0, 1), 20, replace=T), sample(c(0, 1), 20, replace=T), sample(c(0, 1), 20, replace=T)) names(d) <- c("A", "B", "C") e <- rep(c("r", "s"), 10) ### end:example How do I get the

Hello, after the creation of a data.frame I like to add NAs as follows: n <- 743; x <- runif(n, 1, 7); Y <- runif(n, 1, 7); Ag6 <- runif(n, 1, 7); df <- data.frame(x, Y, Ag6); # a list with positions: v <- apply(df, 2, function(x) sample(n, sample(1:ceiling(5*n/100), 1), repl=F)); # a loop too much? for (i in 1:length(df)){ df[unlist(v[i]), i] <- NA; } summary(df); This