similar to: querry in simple "for" loop in Box plot

Hi I was trying to have a graph whose axes are X axis: m, Y axis: var[X ((a,b) in suffix, and (n,d) in the power)]. X ((a,b) in suffix, and (n,d) in the power)- X^(n,d) _ (a,b). Actually I require many plots involving different values of a,b,n,d, so need to keep this complicated notation. The expression() didn't work out for this case. Can anyone help me out. Thanks, in advance.

Hi, I want to use a more accurate value of exp(1).  The value given by R is 2.718282. I want a value which has more than 15 decimal places. Can anyone let me know how can I increase the accuracy level. Actually there are some large multipliers of exp(1) in my whole expression, and I want a more accurate result at the last step of my program, and for that I need to use highly accurate value

Hi, I wanted to compute the value of the function ifn at certain values of n. But I am receiving the following error when I was using the following code(given at the end). Error: evaluation nested too deeply: infinite recursion / options(expressions=)? I feel that since the function Grx is recursively related, perhaps making the code too complicated too handle. Can anyone let me know if

Hi, I was trying to have a graph whose axes are of the following type: X axis: n and Y axis: var[U ((a,b) in suffix, and (n,d) in the power)]. U ((a,b) in suffix, and (n,d) in the power)- U^(n,d) _ (a,b). Actually I require many plots involving different values of a,b,n,d, so need to keep this complicated notation. The code I used: plot(n, hn$h_pg,

Hello, I want to draw a histogram of the mean of sample observations drawn from multivariate t distribution. I am getting the following error corresponding to the code I used. Though I am getting the graph, but I am curious to know the warning message. Warning messages: 1: In if (freq) x$counts else { : the condition has length > 1 and only the first element will be used 2: In if (!freq)

Hi R-users, I was plotting the differences of the variances of the three estimators- T^(1), T^(2), T^(3), ofcourse taking two at a time. I was using the expression() in the legend function in order to show which line correspond to which of the difference, but the following that I had used didn't gave desired result. I would be grateful, if you help me out. plot(n, pg,

Hello everyone! I want to use density function of R to compute the density at x(=0, say). But it is giving me the 5-number summary and mean of the data and densities at that point. I just want the densities at different values specified by me. Can anyone let me know how can I find that? For example Thanks in advance for your help. Shant [[alternative HTML version deleted]]

Hello R users, I have two data sets like the following. Form of dataset: data: X1 X2 X3 X4 X5 1902 RE 3 594 9 1903 RE 3 1340 7 1904 AA 3 760 14 1908 RE 4 1759 18 1909 EX 2 387 1 2901 AU 6 3116

Hi, I wanted to compute the value of the function ifn at certain values of n. But I am receiving the following error when I was using the following code(given at the end). Error: evaluation nested too deeply: infinite recursion / options(expressions=)? I feel that since the function Grx is recursively related, perhaps making the code too complicated too handle. Can anyone let me know if

I have 2 columns for weight. There are NAs in each column but not for the same observation. Some observations have values for both. I would want to prioritize the WT2 values so I would like to do the following: >From this: ID WT1 WT2 1 134 NA 2 145 155 1 NA 175 3 NA 187 To this: ID WT1 WT2 WT 1 NA

Hello, I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the following error. Can anyone please help me out. Error in uniroot(function(x) x * (3^x) * log(4) - x * log(4/3) - (3^x) + : f() values at end points not of opposite sign.

Hi! Can anyone please let me know what numerical integration procedure does the integrate function in package stats follow? Thank you in advance Shant [[alternative HTML version deleted]]

Hi, I want to find a value of n1. I used the following code but I am getting the error - Error in as.vector(x, mode) : cannot coerce type 'closure' to vector of type 'any' n=10 a_g<-(1/(n*(n-1)))*((pi/3)*(n+1)+(2*sqrt(3)*(n-2))-4*n+6) a_s<-function(n1) { t1=(n1-1)/2; (t1*(gamma(t1)/gamma(n1/2))^2)/2-1-a_g } xm<-solve(a_s) Can anyone help me out. Thanks in

Hi, I was plotting or creating a map for Texas school districts using the shape file of Texas. I could not find any other helpful mail in the mailing list. txshp<-read.shape(system.file("S:\\Districts_10_11.shp", package="maptools")) Error- read.shape no found. But read.shape is there in maptools. If anyone can help me out it will be great. Thanks in advance. Shant

Hello all, I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)! for m when values of n and k are provided n1<-c(10,13,18,30,60,100,500)         # values of n kx<-seq(1,7,1);                               # values of k slv2<-lapply(n1,function(n){    slv1<-lapply(kx,function(k){              lhs<-function(m)              {                

I have a need to connect to a separate database in order to get some information from that DB but I am trying to figure out the most elegant way to do it. With this application there will be times when a new DB will be added to the mix and I would rather not have to add models to my app every-time a new database is added. I could do it this way if that is how everyone tells me to go, but

Need to know the setting which generates following message every 300 seconds Name Query <1d> - Broadcast message every 300 seconds This is Coming from the samba clients running on a Solaris box. Using this with a WINS server where the setting for refresh interval of name is 6 days.

Hi R users, I want to calculate the partial correlation (first or second order) and their corresponding significance test (p-value). I used > library(corpcor) and "cor2pcor" function to calculate partial correlation but could not calculate "p-value". If some one knows the R package or function to calculate corresponding "p-value", It will be great help. Thanks  

Apologies for thickness - I'm sure that this operates as documented and with good reason. However... My understanding of arima.sim() is obviously imperfect. In the example below I assume that x1 and x2 are similar white noise processes with a mean of 5 and a standard deviation of 1. I thought x3 should be an AR1 process but still have a mean of 5 and a sd of 1. Why does x3 have a mean of ~7?

I have been quantreg library for a number of projects but have just hit a snag. I am using nlrq to examine an asymptotic relationship between 2 variables at the 99th percentile. It performs as expected, however when I try to extract the coefficients along with se and significance I am running into problems. The problem is that for the nlrq regression Dat.nlrq, summary(Dat.nlrq) reports a different