similar to: regexpr syntax question

Dear list, I'm trying to write my first looping function in R. After many hours of searching help files and previous posts, I'm at wits end. Please forgive my programming ignorance...any help is greatly appreciated. I need to sort through a vector (x) and identify the point at which 2 successive values become smaller than the previous value. I've written a "while"

Dear list, After searching many old posts, I can't find the solution to a simple problem. can someone tell me how to create a character string with multiple backslashes, as in: file_dir <- c("C:\files\data\") I need to create this string and then paste it to many files names for batch processing in another software program. R won't accept the backslash and removes

Dear list, I'm trying to download a text file directly from the internet using the RCurl package and the command getURL. Duncan Lang graciously helped me solve the first step in this problem using the following command: ################# txtfile <- getURL('ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt', ftp.use.epsv = FALSE) #################

Dear List, I'm stuck on what seems like a simple indexing problem, I'd be very grateful to anyone willing to help me out. I queried a dataframe which returns a character vector called "plot". I have another dataframe from which I want to subset or select only those rows that match "plot". I've tried subset, and also the "which" command. plot

Dear list, I've recently installed R on a 64 bit machine with 8 GB of RAM. I set this computer up as a dual-boot system, with windows XP 64 and Ubuntu 7.10. I downloaded the Linux 64 bit version of R and installed it. I'm trying to run rather large Random forest models and was running into severe memory limitations with my old windows 32 bit machines. When I run Random Forest models

Dear list, I would like to plot 2 series of numbers with very different ranges/scales as lines on the same plot. I assumed this is commonly done and easy, but I have not found any help files (e.g. axis() or matplot() that show how. I've searched many old posts to no avail. I'll be very grateful for any suggestions on how this is done. Best, Zack

Dear list, I am trying to download a text file from an ftp site using download.file(). I used the following code: url <- "ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt" dest <- "c:/test/downloadtest.txt" download.file(url, dest) I get this error message, indicating that R is unable to open the connection: trying URL

Dear list, I'd like to use path.analysis in the package agricolae in batch format on many files, retrieving the path coefficients for each run and appending them to a table. I don't see any posts in the help files about this package or the path.analysis package. I've tried creating an object out of the call to path.analysis, but no matter what I try, the function automatically prints

Dear list, Below I've written a clunky for loop that counts NA's in a row, replacing all with NA if there are more than 3 missing values, or keeping the values if 4 or more are present. This is sample code from a very large dataframe I'm trying to clean up. I know there are many simpler more elegant solutions to this little problem. Would someone be willing to show me how to

Dear R Helpers, I am running R 2.6.2 on a Windows XP machine. I am trying to use regexpr to locate full stops in strings, but, without success. Here an example:- f="a,b.c at d:" #define an arbitrary test string regexpr(',',f) #find the occurrences of ',' in f - should be one at location 2 # and this is what regexpr finds #[1] 2

R-help, Sorry if this is more of a regex question than an R question. However, help would be appreciated on my use of the regexpr function. In the first example below, I ask for all characters (a-z) in 'abc123'; regexpr returns a 3-character match beginning at the first character. > regexpr("[[:alpha:]]*", "abc123") [1] 1 attr(,"match.length") [1] 3

Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #

Dear R wizards, I have a folder containing 1000 files. For each file, I need to extract the first row of each file, paste it to a new file, then write out that file. Then I need to repeat this operation for each additional row (row 2, then row 3, etc) for 23 rows in each file. I can do this with a for loop (as below). Is there a way to use some of the indexing power of R to get around this

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

Hi, I'm trying to parse lines of the form: dan001.hin (0): fingerprint={256, 411, 426, 947, 973, 976} What I need is the sequence of number between {}. I'm using grep as match <- grep("{([0-9,\s]*)}",s,perl=T,value=T) where s is a character vector. But all I get is the whole string s. I tried using regexpr in an attempt to get just the sequence I wanted: match <-

Dear all-- I am still forging my first arms with R and I am fighting with regexpr() as well as portability between unix and windoz. I need to extract barcodes from filenames (which are located between a double and single underscore) as well as the directory where the filename is residing. Here is the solution I came to: aFileName <-

I have a question about the llvm debugging records, especially wrt compile units. In the non-LLVM sense, a compile unit is essentially everything contained within a single .o file, and it is derived from one or more source and header files. Included in a compile unit are functions and global data. Dwarf records refer to compile units in the same way: a compile unit record has children which

Hi, I 'd like to match each member of a list to a target string, e.g. ------------------------------ mylist=c("MN","NY","FL") g=regexpr(mylist[1], "Those from MN:") if (g>0) { "On list" } ------------------------------ My question is: How to add an end-of-string symbol '$' to the to-match string? so that 'M' won't

https://bugzilla.samba.org/show_bug.cgi?id=14371 Bug ID: 14371 Summary: Combined Exclude & Protect Filter Type Product: rsync Version: 3.2.0 Hardware: All OS: All Status: NEW Severity: enhancement Priority: P5 Component: core Assignee: wayne at opencoder.net

Hi, > Suppose I have the following source: > > file1: > #include "file2" > #include "file3" > int fn1(void) ... > > file2: > int a; > > file3: > int fn2(void) ... > > then fn1, along with all the base types etc appear to be in compile unit > "file1", the variable a appears to be in compile unit