similar to: subsetting a data frame

Hello I have a data frame and one of its columns is as follows: Col chr1:71310034 chr14:23354088 chr15:37759058 chr22:18262638 chrUn:31337214 chr10_random:4369261 chrUn:3545097 I would like to get rid of colon (:) and replace this column with two new columns containing the terms on each side of the colon. The new columns should look as follows: Col_a Col_b chr1

Hello I have 2 columns of short sequences that I would like to compare and count the number of mismatches and record the number of mismatches in a new column. The sequences are part of a data frame that looks like this: seq1=c("CGGTGTAGAGGAAAAAAAGGAAACAGGAGTTC","CGGTGGTCAGTCTGGGACCTGGGCAGCAGGCT", "CGGGCCTCTCGGCCTGCAGCCCCCAACAGCCA")

Hello I have 2 data frames DF1 and DF2 where DF2 is a subset of DF1: DF1= data.frame(V1=1:6, V2= letters[1:6]) DF2= data.frame(V1=1:3, V2= letters[1:3]) How do I create a new data frame of the difference between DF1 and DF2 newDF=data.frame(V1=4:6, V2= letters[4:6]) In my real data, the rows are not in order as in the example I provided. Thanks much Joseph [[alternative HTML version

Hi Jim I am trying to prepare a bed file to load as accustom track on the UCSC genome browser. I have a data frame that looks like the one below. > x V1 V2 V3 1 chr1 11255 55 2 chr1 11320 29 3 chr1 11400 45 4 chr2 21680 35 5 chr2 21750 84 6 chr2 21820 29 7 chr2 31890 46 8 chr3 32100 29 9 chr3 52380 29 10 chr3 66450 46 I would like to insert the following 4 lines at the beginning:

Dear List, I am having a problem using gsub to remove dates from a date/time string. For example: x<-c("5/31/2009 12:34:00","6/1/2009 1:14:00") I would like to remove the date and have just the time. I have tried: gsub("[0-9+]/[0-9+]/[0-9+]","",x) and various versions. I think my problem is that the / is a special character and is telling it

Hi merge() takes only 2 data frames. What can you do to it to make take more than two data frames? or is there another function that does that? Thanks joseph ____________________________________________________________________________________ Looking for last minute shopping deals? [[alternative HTML version deleted]]

Hello I have 2 data frames df1 and df2. I would like to create a new data frame new_df which will contain only the common rows based on the first 2 columns (chrN and start). The column score in the new data frame should be replaced with a column containing the average score (average_score) from df1 and df2. df1= data.frame(chrN= c(“chr1”, “chr1”, “chr1”, “chr1”, “chr2”, “chr2”, “chr2”),

Hello, I have a big number lets say of around hundred digits. I want to subset that big number into consecutive number of 5 digits and find the product of those 5 digits. For example my first 5 digit number would be 73167. I need to check the product of the individual numbers in 73167 and so on. The sample number is as follows:

Hi Matt Your method is the easiest way for me to install the 64-bit R. I followed the directions on your web site and then did the following: R --arch=x86_64 source("http://bioconductor.org/biocLite.R") biocLite(type = "source",lib = "/Library/Frameworks/R.framework/Versions/2.8/Resources/RLib64") I got many errors and warnings which I copied to the attached file.

Hi I have a character vector with thousands of names which looks like this: > V=c("Fred", "Mary", "SAM") > V [1] "Fred" "Mary" "SAM" > class(V) [1] "character" I would like to change it to a list: > L=as.list(V) > L [[1]] [1] "Fred" [[2]] [1] "Mary" [[3]] [1] "SAM" but I need to

I run R 2.1.1 in a Linux environment (RedHat 9) although my question is not platform-specific. Consider the following: > A <- c("Prefix-aaa", "Prefix-bbb", "Prefix-ccc") > B <- strsplit(A, "-") > B [[1]] [1] "Prefix" "aaa" [[2]] [1] "Prefix" "bbb" [[3]] [1] "Prefix" "ccc" How

I'm sure there's a simple way to do this, but I can only think of complicated ones. I have a number of character vectors that look something like this: "12 78 23 9 76 43 2 15 41 81 92 5(92 12) (81 78 5 76 9 41) (23 2 15 43)" I wish to get it into a list of numerical vectors like this: $Group [1] 12 78 23 9 76 43 2 15 41 81 92 5 $Subgroup1 [1] 92 12 $Subgroup2 [1] 81 78 5

I want to remove the column names from a data frame. I do it the long way, can any body show me a better way ? df= data.frame(chrN= c(“chr1”, “chr2”, “chr3”), start= c(1, 2, 3), end= c(4, 5, 6), score= c(7, 8, 9)) df #I write a txt file without row or column names write.table(df,"df1.txt",sep='\t',quote=FALSE,row.names=F,col.names=F) #then I read it with the header = F

hello can you show me how to create a data.frame from two factors x and y. column 1 should be equal to x and column 2 is 1 if it is common to y and 0 if it is not. x=factor(c("A","B","C","D","E","F","G")) y=factor(c("B","C","G")) the output should look like this: A 0 B 1 C 1 D 0 E

I have a data.frame with all character columns, I would like to convert the last two columns into numeric.> x[1:5, ] chrN start end 1 chr1 71310034 71310064 2 chr14 23354088 23354118 3 chr14 71310034 71310064 4 chr15 37759058 37759088 5 chr22 18262638 18262668 > apply(x, 2, FUN = mode) chrN start end

Hello again, I'm trying to do the following: subset(dataframe,list %in% strsplit(dataframe[[Field]],",")) But This returns always the complete dataframe, since the strsplit(dataframe[[Field]],",") is evaluated as one big list for the whole data frame rather than one list per row. How can I have this evaluated on a per row basis? After 1.5 h hitting head against wall -

Hi Peter I have the following data frame with chromosome name, start and end positions: chrN start end 1 chr1 11122333 11122633 2 chr1 11122333 11122633 3 chr3 11122333 11122633 8 chr3 111273334 111273634 7 chr2 12122334 12122634 4 chr1 21122377 21122677 5 chr2 33122355 33122655 6 chr2 33122355 33122655 I would like to count the positions that have the same start and

Hi, I'm looking for some way to pick up the numbers which are contained and buried in a long character. For example, outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:17139.21);" num.char =

I find that after subsetting (you may prefer "conditional selection") a data frame and assigning it to a new object, the str(new object) reflects the original data frame, not the new one: A <- rnorm(20) B <- factor(rep(c("t", "g"), 10)) C <- factor(rep(c("h", "l"), 10)) D <- data.frame(A, B, C) str(D) # reports correctly E <-

Hi, I've had this problem for a while and tackled it is a quite dirty way so I'm wondering is a better solution exists: If we have two vectors: v1 = c(0,1,2,3,4) v2 = c(5,3,2,1,0) How to remove one instance of the "3,1" / "1,3" double? At the moment I'm using the following solution, which is quite horrible: v1 = c(0,1,2,3,4) v2 = c(5,3,2,1,0) ft <-