similar to: ftables package, zero rows

-- apologies if this is a dup - i got a bounce saying the message was unprocessed. Is there a straightforward way to get a table with percents in the cells rather than counts? I've looked at table, ftable, xtabs, and ctab, which did the conversion but returned the results in a single row without labels. any suggestions are appreciated. thank you.

Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female

Dear list, I am trying to create a three-way table with percent occurrence instead of raw frequencies. However, I cannot get the results I expected: I have the following table: > ftable(table( mannerDF$agem, mannerDF$target, mannerDF$manner )) <snip> 50 bak 0 0 0 0 1 0 pak 0 0 0 0 3 0 sak

Dear All, I want to create a table for several variables. As example. I have a dataframe with following data: Gender transport driving 1 0 1 0 1 0 1 0 1 Now I want to create a table in the following form: Gender

I'm not sure how to best explain what I am after but here goes. I have a data frame with 2 geographical factors. One is the major region the other is the component regions. I am trying to process all the regions at the same time without using "for". So I need (think, I do) a list of matrices each structured according to the number of subregions within each region. So is there a

I would like to suggest that an 'append' argument be added to write.ftable(). This would allow, for example, the user to append ftable() output to a text report. I have attached an svn patch to ftable.R that makes the proposed change to write.ftable(). [A very trivial change since 'append' is simply passed to cat().] I have also attached a patch to read.ftable.Rd which documents

R has amazing capabilities, but percentage tables are a weak spot IMHO. There's prop.table but that's rather unwieldly, especially for multiway tables. CrossTable by Marc Schwartz in the gregmisc library makes percentage tables a breeze but is limited to two-way tables. So I decided to try my own hand at writing an R-function that would make it easy to produce nicely formatted percentage

I apologize in advance if this is the wrong forum for this report/request, and for the fact that I have not read the code for ftable.formula in any detail. >From reading the documentation for ftable.formula, I expected that the following two calls to ftable would produce the same results: data(UCBAdmissions) ftable(UCBAdmissions, row.vars = "Dept", col.vars = c("Gender",

Dear list. New to R, I'm looking for a way of using crosstab to output low-dimensional (higher than 2) contingency tables (frequencies, per-cents by rows, % by columns, mean, quantiles....) I'm looking for something of the following sort dataframe: singers, categorical variates: voice category (soprano,mezzo-soprano, ...) , voice type( drammatic, spinto, lirico-spinto, lirico,

The ftable structure is not an ordinary matrix. Instead, it has the body of the table with several cbind- and rbind-ed rows and columns of label information. The example in ?ftable has two row factors and two column factors. Continuing with the example in ?ftable, enter tmp <- ftable(mtcars$cyl, mtcars$vs, mtcars$am, mtcars$gear, row.vars = c(2, 4), dnn =

Dear R-developers, I would like to suggest a 'method' slot for format.ftable() (see an adjusted 'format.ftable()' below, taken from the source of R-2.15.2). At the moment, format.ftable() contains several empty cells due to the way the row and column labels are printed. This creates problems (= unwanted empty columns/rows) when converting an ftable to a LaTeX table; see an

Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp

Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp

How can I export an ftable object in the same format that appears in R command window? For testing that i was using this example that is in help of this function. ## Start with a contingency table. ftable(Titanic, row.vars = 1:3) ftable(Titanic, row.vars = 1:2, col.vars = "Survived") ftable(Titanic, row.vars = 2:1, col.vars = "Survived") ## Start with a data frame. x <-

Dear expeRts, What's the easiest way to convert an ftable object to a matrix such that the row names of the ftable object are shown in the first couple of columns of the matrix? This is (typically) required, for example, when the final goal is to print the matrix via xtable. Below is a rather complicated example of how to do it... Cheers, Marius ## Goal: convert an ftable() to a

I am generating an ftable (by running ftable on the results of a xtabs command) and I am getting the following. ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?Var1? Var2 date ? ? ? ? ? ? ? ? group? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 2007-01-01? ? ? ? ? q1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?1? ? 9 ? ? ? ? ? ? ? ? ? ? ?q2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?

Dear latexRs, I tried to make a latex printout of a simple categorial ftable. It should look like the output of print.ftable. Any ideas how to get the syntax of summary.formula right. Or some alternative? As far I see, xtable does not have method for ftable. Dieter library(Hmisc) n=500 sex <- factor(sample(c("m","f"), n, rep=TRUE)) treatment <-

On Tue, 2 Oct 2012 10:56:47 -0700 Eric Christopher <echristo at gmail.com> wrote: > On Mon, Oct 1, 2012 at 9:26 PM, Chris Lattner <clattner at apple.com> > wrote: > > > > On Oct 1, 2012, at 6:16 PM, greened at obbligato.org wrote: > > > >> Sanjoy Das <sanjoy at playingwithpointers.com> writes: > >> > >>> In short, I propose a

Dear all, I haven't received any feedback so far on my proposal to make "justify" argument available in stats:::format.ftable Is this list the appropriate place for this kind of proposal? I hope this follow-up to my message won't be taken as rude. Of course it's not meant to be, but I'm not used to the R mailing lists... Thank you in advance for your comments, Best,

Dear List, possibly called Frank, I tried to create an ftable lookalike of the following data set in LaTeX/Sweave with summary(formula,..), but I could not get it to work for count tables; numeric tables work fine. summary(formula,...,fun="table") does not give the full cross breakdown. Other suggestions welcome. Note that in the output there should be empty fields on repeated