Displaying 20 results from an estimated 10000 matches similar to: "ylab with an exponent"
2008 Apr 08
3
simple graphing question
#copy and paste this into R
f <- (structure(list(TKN = c(0.103011025, 0.018633208, 0.104235702,
0.074537363, 0.138286096), RM = c(215, 198, 148, 119, 61)), .Names = c("TKN",
"RM"), class = "data.frame", row.names = 25:29))
plot(f$TKN~f$RM, type="b")
I would like to reverse the X-Axis. How do I do this?
--
Let's not spend our time and resources
2008 Oct 20
2
calculating mean for samples
Hi everyone,
> does any one knows how can I calculate mean for different samples
> i.e. I have a data like this:
>
> s1 s2 s3 s4
> 1 0 0 0 1
> 2 1 0 1 0
> 3 0 0 0 0
> 4 0 0 0 0
> 5 0 1 0 1
> 6 1 0 0 0
> 7 0 0 0 0
> 8 0 0 0 0
> 9 0 0 0 0
> 10 0 0 0 1
>
> I need to make 5 different sample with 5
2009 Aug 13
3
split number in a vector and then make a chron object out of it
These are date and times in the format YYYYMMDDhhmmss. I would like
to take this column and make a chron object form them. I have tried a
couple of the split family of functions but they need character input
here is the data:
date.time <- c(19851001001500, 19851001003000, 19851001004500, 19851001010000,
19851001011500, 19851001013000, 19851001014500, 19851001020000,
19851001021500,
2008 Jun 25
2
I want to install a package on Max OS X from a local file
I can't figure this one out- I am the administrator, The file that I want
to install is a .tar.gz which is located on my desktop. How do I get it
into my packages directory- through the GUI or through brute force?
thanks
stephen
--
Let's not spend our time and resources thinking about things that are so
little or so large that all they really do for us is puff us up and make us
feel
2009 Jan 15
3
Bar Plot ggplot2 Filling bars with cross hatching
#I am putting a test together for an introductory biology class and I
would like to put different cross hatching inside of each bar for the
bar plot below
color <- c("Brightly Colored", "Dull", "Neither")
lizards <- c(277, 70, 3)
liz.col <- data.frame(color, lizards)
qplot(color, lizards, data=liz.col, geom="bar", ylab="Observed
Matings",
2008 Jan 21
4
Stationarity of a Time Series
Does anyone know of a test for stationarity of a time series, or like
all ordination techniques it is a qualitative assessment of a
quantitative result. Books, papers, etc. suggestions welcome.
thanks
Stephen
--
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods. We are
2008 Jul 15
2
POSIXct extract time
RM215.sp <- SpatialPoints(RM215, proj4string=CRS("+proj=longlat
+datum=WGS84"))
d060101 <- as.POSIXct("2006-01-01", tz="EST")
study_seq <- seq(from=d060101, length.out=761, by="days")
up.215 <- sunriset(RM215.sp, study_seq, direction="sunrise",
POSIXct.out=TRUE)
down.215 <- sunriset(RM215.sp, study_seq, direction="sunset",
2008 Aug 18
4
Multiple Plotting help (lines don't always connect)
d <- structure(c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 1,
2, 3, 4, 5, 6, 7, 8, 9, 10, NA, NA, NA, 14), .Dim = c(14L, 2L
), .Dimnames = list(NULL, c("a", "b")))
plot(d, type="b")
This is simplified, but Is there an option I am missing that will
force all of the points to be joined by a line?
Stephen Sefick
--
Let's not spend our time and resources
2008 Sep 11
3
periodicity validation
There is a series of data contains time in fixed step and energy
varying with time, how to test its periodicity?In R, it seems there is
no direct tools since I have search the R manual with periodic and I
have not found any related topic.
Thanks a lot
2008 Nov 04
2
Zoo seems to be running slow in R 2.8.0 windows
R version 2.8.0 (2008-10-20)
i386-pc-mingw32
locale:
LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
States.1252;LC_MONETARY=English_United
States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] StreamMetabolism_0.01 chron_2.3-24 zoo_1.5-4
loaded
2008 Jul 19
2
extracting colnames to label plots in a function
#this is my little function that I would like to use the column names of the
x and y arguments in the function. I would like it to read
# site1-site2 how would I do this
diff.temp <- function(x, y ,use="pairwise.complete.obs")
{
na.method <- pmatch(use, c("all.obs", "complete.obs",
"pairwise.complete.obs"))
par(mfrow=c(2,1))
2009 Jul 15
2
ifultools on ppc debian
I have tried to compile this from source. I don't know what Endianess
is, but it is probably not debian power pc. Am I would of luck with
this package?
Stephen Sefick
* Installing *source* package ?ifultools? ...
** libs
gcc -std=gnu99 -I/usr/local/lib/R/include -I"../inst/include/"
-D"MUTIL_STATIC" -D"DEF_TF" -D"INTERRUPT_ENABLE"
2010 Feb 18
3
row indexes from logical statment
Is there any easy way to pull out the row indexes for a logical
matching statment?
#################example code#########################################
foo <- data.frame(name=c(rep("A", 25), rep("B", 25), rep("C", 25),
rep("A", 25)), stuff=rnorm(100), and=rnorm(100), things=rnorm(100))
#this is what I want but I would like the row indexes
2009 Aug 21
5
splitting a string up
x <- "1041281__2009_08_20_.lev"
I would like to split this string up and only extract the leading numbers.
1041281
to use as a label for a data column in a bigger for loop function to
read in data.
regards,
--
Stephen Sefick
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us
2011 Mar 31
2
Linear Model with curve fitting parameter?
I have a model Q=K*A*(R^r)*(S^s)
A, R, and S are data I have and K is a curve fitting parameter. I
have linearized as
log(Q)=log(K)+log(A)+r*log(R)+s*log(S)
I have taken the log of the data that I have and this is the model
formula without the K part
lm(Q~offset(A)+R+S, data=x)
What is the formula that I should use?
Thanks for all of your help. I can provide a subset of data if necessary.
2008 Apr 14
1
Vegan R^2 and tau values for metaMDS
I am using the function metaMDS with jaccard distances to ordinate a
set of constituent by site matrix. I can post this data if it would
be helpful, but it is large to include in an email. I can also
provide reproducable code if necessary. I would like to get an R^2
value for the axes of the ordination configuration that I get with
metaMDS in the vegan package is there a way to do this- is it
2008 Jul 31
2
S 3 generic method consistency warning please help
I would like to include this in a package. The S3 methods on R CMD check
says
* checking S3 generic/method consistency ... WARNING
window:
function(x, ...)
window.chron:
function(data, day1, hour1, day2, hour2, ...)
See section 'Generic functions and methods' of the 'Writing R Extensions'
manual.
I have looked and can not figure it out. This function is for convience.
What
2008 Feb 12
4
summary statistics
below is my data frame. I would like to compute summary statistics
for mgl for each river mile (mean, median, mode). My apologies in
advance- I would like to get something like the SAS print out of PROC
Univariate. I have performed an ANOVA and a tukey LSD and I would
just like the summary statistics.
thanks
stephen
RM mgl
1 215 0.9285714
2 215 0.7352941
3 215 1.6455696
4 215
2008 Dec 02
2
ggplot2 45deg axis labels
I would like to rotate the axis labels 45 deg.
--
Stephen Sefick
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us feel like gods. We are mammals, and have not exhausted the
annoying little problems of being mammals.
-K. Mullis
2008 Sep 15
4
getting data into correct format for summarizing ... reshape, aggregate, or...
I would like to reformat this data frame into something that I can
produce some descriptive statistics. I have been playing around with
the reshape package and maybe this is not the best way to proceed. I
would like to use RiverMile and constituent as the grouping variables
to get the summary statistics:
198a 198b
mean mean
sd sd
... ...
etc. for all of these.
I have tried