similar to: subsetting matrix according to columns with character index

Hi all, I'm just a beginner with R but I have not been able to search for any relevant answer to my problem. I apologize if it has in fact been asked before. Recently I've realized that I need to combine hundreds of pairs of data frames. The filenames of the frames I need to combine have unique strings. This is my best guess as to the approach to take: filenames<-list.files()

Hello all, I have a matrix whose column names look like a1 a2 b1 b2 b3 c1 c2 1 2 3 7 1 3 2 4 6 7 8 1 4 3 Now, I can have any number of a's. not just two as shown above and same goes for b's and c's. I need to extract all the a's columns and put them in another matrix, extract all b's columns and put them in some matrix

Hi, I am trying to aggregate the sum of my test data.frame as follow: testDF <- data.frame(v1 = c("a", "a", "a", "a", "a", "b", "b", "b", "b", "b", "c", "c", "c", "c", "c", "d", "d", "d", "d",

Hi, I have a three dimensional array, e.g., my.array = array(0, dim=c(2,3,4), dimnames=list( d1=c("A1","A2"), d2=c("B1","B2","B3"), d3=c("C1","C2","C3","C4")) ) what I would like to get is then a dataframe: d1 d2 d3 value A1 B1 C1 0 A2 B1 C1 0 . . . A2 B3 C4 0 I'm sure there is one function to do

I have a dataset that is basically structureless. Its dimension varies from row to row and sep(s) are a mixture of tab and semi colon (;) and example is HEADER1 HEADER2 HEADER3 HEADER3 A1 B1 C1 X11;X12;X13 A2 B2 C2 X21;X22;X23;X24;X25 A3 B3 C3 A4 B4 C4 X41;X42;X43 A5 B5 C5 X51 etc., say. Note that a blank

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Colleagues, I have created a list in the following manner: TEST <- list(c("A1", "A2"), c("B1", "B2"), c("C1", "C2")) I now want to delete one element from the list, e.g., the third. The command TEST[[3]] yields (as expected): [1] "C1" "C2" The command TEST[[-3]] yields: Error:

Hi all, I'm using R to analyze some research and I'm not sure which test would be appropriate for my data. I was hoping someone here might be able to help. Short version: Evaluate null hypothesis that change A1->A2 is similar to change C1->C2, for continuous, non-normal datasets. Long version: I have two populations A and C. I take a measurement on samples of these

Hi, I ran a program that was exhausting the (unix) server's available memory. I got a bus error and then chose to save and quit workspace (option 4). That may not have been a smart idea - when I try to use R now, I get the error message: Error in load(name, envir = .GlobalEnv) : ReadItem: unknown type 0, perhaps written by later version of R Fatal error: unable to restore saved data in

Greetings, I have a CSV file with three fields. eg. a1,b1,c1 a2,b2,c2 .... I wanted the output to be: b1,c1,a1 b2,c2,a2 .... the command cut -d, -f2,3,1 <file> returns a1,b1,c1 cut -d, -f2,3 <file> works as advertised. Is it specific to linux? In that case how do I go about swapping two columns? I do not think a gazzillion byte gui is required. The file size is about 43Megs.

Dear all: I have this: A1 B1 C1 D1 E1 A2 B2 C2 D2 E2 A3 B3 C3 D3 E3 And I want this A1 E1 B1 E1 C1 E1 D1 E1 A2 E2 B2 E2 C2 E2 D2 E2 A3 E3 B3 E3 C3 E3 D3 E3 Example: m<- matrix(1:15,nrow=3,byrow=T) m v<- unlist(list(t(m[,1:4]))) u<- rep(c(5,10,15),c(4,4,4)) data.frame(v,u) This is the result I want but I would like to learn a simpler way to do it. Any clue?

From: Ben Skeggs <bskeggs at redhat.com> Signed-off-by: Ben Skeggs <bskeggs at redhat.com> --- src/gallium/drivers/nouveau/nv50/g80_defs.xml.h | 279 ++++++++++++++++++++++++ 1 file changed, 279 insertions(+) create mode 100644 src/gallium/drivers/nouveau/nv50/g80_defs.xml.h diff --git a/src/gallium/drivers/nouveau/nv50/g80_defs.xml.h

Just to repeat: you have NamesWide<-data.frame(Name1=c("Tom","Dick"),Name2=c("Larry","Curly")) and you want NamesLong<-data.frame(Names=c("Tom","Dick","Larry","Curly")) There must be something I am missing, because NamesLong <- data.frame(Names = c(NamesWide$Name1, NamesWide$Name2)) appears to

Hello I have a table describing butterfly range traits. It is composed of three columns as below Species name range size (X) latitude of range midpoint (Y) There are 11 kinds of butterflies. Each has its range size, and the latitude of each range midpoint ranges from 9 to 19. I would like to have the average range size of every degree of latitude. For example, the average range

Hi suppose I have two arrays x1,x2 of dimensions a1,b1,c1 and a2,b2,c2 respectively. I want x = x1 "+" x2 with dimensions c(max(a1,a2), max(b1,b2),max (c1,c2)) with x[a,b,c] = x1[a1,b1,c1] + x2[a2,b2,c2] if a <=min(a1,a2) , b<=min (b1,b2), c<=min(c1,c2) and the other bits either x1 or x2 or zero according to whether the coordinates are "in range" for

Hi all, I frequently encounter datasets that require me to repeat the same calculation across many variables. For example, given a dataset with total employment variables and manufacturing employment variables for the years 1990-2010, I might have to calculate manufacturing's share of total employment in each year. I find it cumbersome to have to manually define a share for each year and

On Mon, 14 May 2012 11:46:02 -0700 Preston Briggs <preston.briggs at gmail.com> wrote: > On Sat, Apr 21, 2012 at 6:08 AM, Sanjoy Das > <sanjoy at playingwithpointers.com> wrote: > > > > Sorry for having been quiet for so long, I have my university exams > > going on, and will be able to contribute only after the coming > > Friday. > > Gents, >

Hi, I've this dataframe: V1 V5 V6 1 MOD13Q1_2000049 0.1723 A1 2 MOD13Q1_2000049 0.1824 B1 3 MOD13Q1_2000049 0.1824 C1 4 MOD13Q1_2000049 0.1774 A2 5 MOD13Q1_2000049 0.1953 B2 6 MOD13Q1_2000049 0.1824 C2 7 MOD13Q1_2000065 0.1921 A1 8 MOD13Q1_2000065 0.1938 B1 9 MOD13Q1_2000065 0.2009 C1 10 MOD13Q1_2000065 0.2035 A2 11 MOD13Q1_2000065 0.2157 B2 12

Dear R-gurus, being very new to R, (as well as lazy and not too smart !) I have some problems (and get lost in the docs) trying to write something to find the 9 values (A1,B1,C1,A2,B2,C2....C3) which are solutions of a 12 equations system of the form : > x1-(A1/(A1+B1+C1)) = 0 > y1-(B1/(A1+B1+C1))= 0 > z1-(C1/(A1+B1+C1)) = 0 > 3 same equations with subscript 2 > 3 same

Dear R users, I need to reorder a dataframe using 3 variables for the determine the sorting order. When I create a simple dataframe to test the method, things work as I expected: a1 <- rep(1:10, each=8) a2 <- rep(rep(1:2, each=4), 10) a3 <- rep(c(1:4),20) (a <- data.frame(a1, a2, a3)) for each combination of a1 and a2, a3 is increasing t <- order(a$a1, a$a2, rev(a$a3)) b