similar to: perl expression question

I have a matching problem that I cant solve. mystring = "xxx{XX}yy{YYY}zzz{Z}" where "x","X","y","Y","z","Z" basiclly can be anything, letters, digits etc. I'm only interested in the content within each "{}". I am close but not really there yet. library(gsubfn) strapply(mystring,"\\{[^\\}]+",, perl=F)

Hi List, I've got a count matrix like this: [-11.9,-11] (-11,-10.2] (-10.2,-9.3] (-9.3,-8.44] [-11.9,-10.6] 0 0 0 0 (-10.6,-9.3] 0 0 0 0 (-9.3,-8.01] 0 0 0 0 (-8.01,-6.73] 0 0 0 0 I want to

the content of th character vector (of length 1) is as follows: a <- "something2 ....pat1 name1 pat2 something2....pat1 name2 pat2....pat1 name3 pat2 " I would like to extract the character bewteen pat1 and pat2. That's to say, I would like to get a vecter of c("name1", "name2","name3"). What I did is use strsplit() twise. But I wonder if there

Hello, assume I have an "unstructured" text line from a connection. Unfortunately, it is in string format: R> x [1] "\talpha0\t-0.638\t0.4043\t0.4043\t-2.215\t-0.5765\t-0.137\t501\t2000" How can I extract the data included in this string object "x" in order to get the elements for the parameter vector called "alpha0", i.e. -0.638 0.4043 0.0467

Hi all, I swear this used to work: library(gsubfn) strapply("S(AC,P)TVDK(8)EELVQK(8), ".[(].{1,2}[)]|.")[[1]] But somewhere along the update path it stopped ... now giving me this Error in base::gsub(pattern, rs, x, ...) : invalid backreference 2 in regular expression Can't figure it out. What am I doing wrong? Thanks for any hints, Joh

On Wed, 12 Apr 2023 08:29:50 +0000 Emily Bakker <emilybakker at outlook.com> wrote: > Some example data: > ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? > ?leucocyten ? grampositieve coccen +? > ? > I want to split the strings such that I get the following result: > c(?leucocyten +?, ??gramnegatieve staven +++?, > ??grampositieve staven ++?) >

Dear List, I have an ascii text file with data I'd like to extract. Example: Year Built: 1873 Gross Building Area: 578 sq ft Total Rooms: 6 Living Area: 578 sq ft There is a lot of data I'd like to ignore in each record, so I'm hoping there is a way to use strings as delimiters to get the data I want (e.g. tell R to take data between "Built:" and "Gross" -

can someone show me how to use a regular expression to break the string at the bottom up into its three components : (-0.791,-0.263] (-38,-1.24] (0.96,2.43] I tried to use strplit because of my regexpitis ( it's not curable. i've been to many doctors all over NYC. they tell me there's no cure ) but it doesn't work because there also dots inside the brackets. Thanks.

I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

I have had some comments on sqldf regarding its dependence on tcltk such as the second last sentence on this blog post: http://translate.google.com/translate?hl=en&sl=zh-CN&u=http://www.wentrue.net/blog/%3Fp%3D453&prev=http://blogsearch.google.com/blogsearch%3Fhl%3Den%26ie%3DUTF-8%26q%3Dsqldf%26lr%3D%26sa%3DN%26start%3D10 sqldf does not directly use tcltk but it does use strapply in

Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",

Hi, I have this string, in which I want to extract some of it's element: > x <- "Best-K Gene 11340 211952_at RANBP5 Noc= 3 - 2 LL= -963.669 -965.35" yielding this array [1] "211952_at" "RANBP5" "2" In Perl we would do it this way: __BEGIN__ my @needed =(); my $str = "Best-K Gene 11340 211952_at RANBP5 Noc= 3 - 2 LL= -963.669

Are there packages that allow improved String and URL processing? E.g. extract parts of a URLs such as sub-domains, top-level domain, protocols (e.g. https, http, ftp), file type based on endings, check if a URL is valid or not, etc... I am currently only using split and paste. Are there better and more efficient ways to handle strings e.g. finding sub-strings or to do pattern matching? What

Dear list, I have the following example, from which I am hoping to retrieve numeric values of the factor levels (that is, without the brackets): > > x <- seq(1, 15, length=100) > y <- sin(x) > > my.cuts <- cut(which(abs(y) < 1e-1), 3) > levels(my.cuts) hist() does not suit me for this, as it does not necessarily respect the number of breaks. getAnywhere

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

Hello, I just don't get this and would appreciate if someone could write a line or two: I'm trying to build this package and it stops installing after I add the following to the NAMESPACES file: >importFrom(gsubfn,strapply) The error during the package test is: Error in MyPackage::MyFunction : package 'MyPackage' has no name space and is not on the search path Calls:

Hi, Is there a way in R to get the string which matches the expression, where the expression is a substring of the parent string. Lets say, I have $i <- "transcript:ENST0000112334 pid:ENSP000012345" What I need is the string "pid:ENSP000012345" from $i using the query "ENSP". Appreciate your comments. Praveen Surendran School of Medicine and

Hi All, Is there a means to extract the "10" from "23:10:34" in one pass using strsplit (or something else)? tst <- "23:10:34" For example my attempt strsplit(as.character(tst),"^[0-9]*:") gives [[1]] [1] "" "" "34" Obviously it is matching the first two instances of [0-9]. Note that there may be only one digit

dear all, I am trying to implement some perl scripting in R to improve the performance of some scripts. I found RSPerl library, but it seems to be quite tricky to import variables. this is a simple example. is there any simpler way to do it? furthermore is there any other available resource to interface the two language? RSPerl seems to be no longer supported and when I load it R complains about