similar to: print data frames without row names (within a list)

Is it possible to print a data.frame without the row names? I checked ?data.frame, ?print, ?format and didn't see anything that helped. In the example below, I would just like to show the two columns of data and not the row.names 1:10. > a<-data.frame(1:10, 21:30) > a X1.10 X21.30 1 1 21 2 2 22 3 3 23 4 4 24 5 5 25 6 6 26 7

Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can I get

Dear R-ers! I have a badly organized data base in Excel. Once I read it into R it looks like this (all variables become factors because of many spaces and other characters in Excel):

Hi all, I have the following problem: I have a data frame (actually it is a prop.table) which I want to print as a list, e.g.: C1 C2 C3 R1 0.0 0.0 1.0 R2 1.0 0.0 0.0 R3 0.0 0.0 0.0 R4 0.0 1.0 0.0 should be printed like C1;R1;0.0 C2;R1;0.0 C3;R1;1.0 C1;R2;1.0 C2;R2;0.0 ..... Is there any existing solution out there or could somebody please give me a hint on how to

Hello, I'm switching over from SAS to R and am having trouble merging data frames. The data frames have several columns with the same name, and each has a different number of rows. Some of the values are missing from cells with the same column names in each data frame. I had hoped that when I merged the dataframes, every column with the same name would be merged, with the value in a complete

In R and S, the general idea is that data.frames must have unique row.names (aka dimnames(.)[[1]]). Several observations / problems (in R *and* S !). [Example code at the end] 1) Both in S and R, data.frame(..) (and e.g., also cbind(<data.frame>, ..) which dispatches to data.frame()) silently drops the whole row.names and replaces it by "1" "2" ...

Dear R-devel, Can anyone help me to understand this? It seems that subscripting the rows of a data.frame without actually changing their order, somehow changes an internal representation of row.names that is revealed by e.g. dput/dump/serialize I have read the docs and inspected the (R) code for data.frame, rownames, row.names and dput without enlightenment. df=data.frame(a=1:10, b=1)

Dear R gurus, I trying to convert a list of data frames to one data frame, but one of the values within the list is NULL, so I get the error "arguments imply differing number of rows." Do you know of a quick way to tell R to combine all that are not null? Here is a simple example: >

(following up on myself:) >>>>> "MM" == Martin Maechler <maechler@stat.math.ethz.ch> writes: MM> In R and S, the general idea is that data.frames MM> must have unique row.names (aka dimnames(.)[[1]]). MM> Several observations / problems (in R *and* S !). .... MM> 2) MM> Now, in S (but not in R), MM> the

Hi everybody. I'll first explain my problem and what I'm trying to do. Admit this example: I'm working on 5 different weather stations. I have first in one file 3 of these 5 weather stations, containing their data. Here's an example of this file: DF1 <- data.frame(station=c("ST001","ST004","ST005"),data=c(5,2,8)) And my two other stations in

Hi a) I want to make a list out of a data.frame, where each element of the list is a column of the data.frame. I looked in the archives and saw a lot of postings but surprsingly none elucidated me. I also tried the split, aggregate help files and counldn't see any easy way to do this. I wouldn't be surprised if it's there, but I really didn't see it. I solved the problem

Running R.app on Mac OS X 10.4 > version _ platform powerpc-apple-darwin8.6.0 arch powerpc os darwin8.6.0 system powerpc, darwin8.6.0 status major 2 minor 3.1 year 2006

Running R.app on Mac OS X 10.4 > version _ platform powerpc-apple-darwin8.6.0 arch powerpc os darwin8.6.0 system powerpc, darwin8.6.0 status major 2 minor 3.1 year 2006

R users, I posted a message on "error message for row names". I looked at a saved file that has a list structure. I found that some of list components have row.names = c(NA, 1000). I compared what I did with R.2.3.0 with what I did with R.2.4.0. Previously, with R.2.3.0, row.names = c("1", "2", "3", ...., "1000"). What do I need to read the

Hi, Does anybody know if row.name = FALSE actually works in v2.6.2? Because it isn't working for me... here is some sample code and output: ====+====+====+====+====+====+====+====+====+====+ > print(x,row.names = FALSE) party_abbr candidate_name votes_candidate 2 DFL AMY KLOBUCHAR 1,278,849 5 R MARK KENNEDY 835,653 4 IP

Hi, I have a dataframe (say myData) and want to get a list (say myList) that contains a matrix for each row of the dataframe myData. These matrices are calculated based on the corresponding row of myData. Using a for()-loop to do this is very slow. Thus, I tried to use apply(). However, afaik apply() does only return a list if the matrices have different dimensions, while my matrices have

Hi all, I just stumbled across the difference between explicit and 'automatic' row names for data frames. Is there a quick way to find out if a data frame has automatic row names or not? Of course I know this for data frames that I create myself, but what if a function needs to extract this information for an argument? The following example shows that this property is not easily

R 4.2.3 OS X Colleagues, I am printing a large number of tables using the print command. A simple example is: print(data.frame(COL1=1:5, COL2=10:6)) The result in this case is: COL1 COL2 1 1 10 2 2 9 3 3 8 4 4 7 5 5 6 I would like to print the table WITHOUT the row numbers: COL1 COL2 1 10 2 9 3 8 4 7 5 6 Is there any simple

as.data.frame methods behave inconsistently when they are given a row.name argument of the wrong length. The matrix method silently ignores row.names if it has the wrong length and the numeric, integer, and character methods do not bother to check and thus make an illegal data.frame. > as.data.frame(matrix(1:6,nrow=3), row.names=c("One","Two")) V1 V2 1 1 4 2 2 5 3 3

With a recent R 2.4 I notice the following: df <- data.frame(x=1:2) > row.names(df) [1] "1" "2" > rownames(df) [1] 1 2 This seems related to recent changes in the internal storage format of the row names data for data frames. The man page for rownames says: For a data frame, 'rownames' and 'colnames' are equivalent to 'row.names'