similar to: How can I create a vector of vector?

Does anyone know of a test for stationarity of a time series, or like all ordination techniques it is a qualitative assessment of a quantitative result. Books, papers, etc. suggestions welcome. thanks Stephen -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are

Is there any implementation in R for finding the phase shift between two continuous signals. I would like to find the average phase shift for tow signals over two years. thanks Stephen -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are mammals, and have not exhausted

I have a thirty thousand row data frame imported from excel and a 60,000 row data frame imported from excel. they share a common subset of the same data and I would like to combine the two into one data frame merged together on the data in common. I have looked at the help file for merge and intersect and cbind and rbind etc... And I can't figure it out. Thanks in advance Stephen --

Dear helpers, I am trying to plot two survival curves in the same figure. plot(survival) // in matlab, one just need to call "hold on" plot(survival2) I am wondering how to do it in R. Thank you very much! -- Zhandong Liu Genomics and Computational Biology University of Pennsylvania 616 BRB II/III, 421 Curie Boulevard University of Pennsylvania School of Medicine Philadelphia, PA

These are date and times in the format YYYYMMDDhhmmss. I would like to take this column and make a chron object form them. I have tried a couple of the split family of functions but they need character input here is the data: date.time <- c(19851001001500, 19851001003000, 19851001004500, 19851001010000, 19851001011500, 19851001013000, 19851001014500, 19851001020000, 19851001021500,

I have found an existing image on Amazon EC2 including R. But unfortunately, it is 32-bit R on 32-bit Linux. Does anybody know if there exists an mage (R 64-bit on Linux 64-bit) on Amazon EC2? Or how can I install 64-bit R on my own Linux instance there? Thanks. -- View this message in context:

Hi all, Is there a way in R to plot points using symbols as defined in another vector without adding a separate points line for each symbol? For example, I have the results from an ordination with ~ 35 points and an associated vector that corresponds to different symbols in pch for the 35 symbols. I would like to write one line, rather than dividing up the 35 points into categories first, but I

Greetings -- I have a dataframe a with one element a vector, time, of POSIXct values. What's a good way to split the data frame into periods of a$time, e.g. days, and apply a function, e.g. mean, to some other column of the dataframe, e.g. a$value? Cheers, Alexy

plot(1,2, ylab= paste("insects", expression(m^2), sep=" ")) I get insects m^2 I would like m to the 2 what is the problem? -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are mammals, and have not exhausted the annoying little problems of being

I can't figure this one out- I am the administrator, The file that I want to install is a .tar.gz which is located on my desktop. How do I get it into my packages directory- through the GUI or through brute force? thanks stephen -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel

Hi, How can I create an NA? for example, i have this program but it has errors > x=scan() 1: 1 2 3 4 5 6: Read 5 items > "na"*x Error in "na" * x : non-numeric argument to binary operator what should I multiply x so that I will get an NA? And I really need to multiply that with my x vector. I need this output: (na,na,na,na,na) Thank you for your time and help!=) --

#copy and paste this into R f <- (structure(list(TKN = c(0.103011025, 0.018633208, 0.104235702, 0.074537363, 0.138286096), RM = c(215, 198, 148, 119, 61)), .Names = c("TKN", "RM"), class = "data.frame", row.names = 25:29)) plot(f$TKN~f$RM, type="b") I would like to reverse the X-Axis. How do I do this? -- Let's not spend our time and resources

RM215.sp <- SpatialPoints(RM215, proj4string=CRS("+proj=longlat +datum=WGS84")) d060101 <- as.POSIXct("2006-01-01", tz="EST") study_seq <- seq(from=d060101, length.out=761, by="days") up.215 <- sunriset(RM215.sp, study_seq, direction="sunrise", POSIXct.out=TRUE) down.215 <- sunriset(RM215.sp, study_seq, direction="sunset",

There is a series of data contains time in fixed step and energy varying with time, how to test its periodicity?In R, it seems there is no direct tools since I have search the R manual with periodic and I have not found any related topic. Thanks a lot

Does anyone know of a package to make a map from GIS data, and/or would it be easier in one of the free GIS programs. I would like to make a map of the savannah river area with our sampling locations. thanks stephen -- Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us feel like gods. We are

#I am putting a test together for an introductory biology class and I would like to put different cross hatching inside of each bar for the bar plot below color <- c("Brightly Colored", "Dull", "Neither") lizards <- c(277, 70, 3) liz.col <- data.frame(color, lizards) qplot(color, lizards, data=liz.col, geom="bar", ylab="Observed Matings",

#this is my little function that I would like to use the column names of the x and y arguments in the function. I would like it to read # site1-site2 how would I do this diff.temp <- function(x, y ,use="pairwise.complete.obs") { na.method <- pmatch(use, c("all.obs", "complete.obs", "pairwise.complete.obs")) par(mfrow=c(2,1))

Hi everyone, > does any one knows how can I calculate mean for different samples > i.e. I have a data like this: > > s1 s2 s3 s4 > 1 0 0 0 1 > 2 1 0 1 0 > 3 0 0 0 0 > 4 0 0 0 0 > 5 0 1 0 1 > 6 1 0 0 0 > 7 0 0 0 0 > 8 0 0 0 0 > 9 0 0 0 0 > 10 0 0 0 1 > > I need to make 5 different sample with 5

d <- structure(c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, NA, NA, NA, 14), .Dim = c(14L, 2L ), .Dimnames = list(NULL, c("a", "b"))) plot(d, type="b") This is simplified, but Is there an option I am missing that will force all of the points to be joined by a line? Stephen Sefick -- Let's not spend our time and resources

x <- "1041281__2009_08_20_.lev" I would like to split this string up and only extract the leading numbers. 1041281 to use as a label for a data column in a bigger for loop function to read in data. regards, -- Stephen Sefick Let's not spend our time and resources thinking about things that are so little or so large that all they really do for us is puff us up and make us