similar to: re order vector in order given by another vector

Hi guys, I want to create variable on the fly: for example for (i in 1:10) { cat(paste("VAR",i,sep="")) } Will print VAR1, VAR2 etc up to VAR10. However I want to make these into variables, and then give them a value, for example: vect = c(10:20) for (i in 1:10) { cat(paste("VAR",i,sep="")) = vect[i] } THis doesnt work but I hope it demonstrates

Is there a way of reading in a file in a way that each line becomes a vector: for example: meals.txt breakfast bacon eggs sausage lunch sandwich apple marsbar crisps dinner chicken rice custard pie I want to read in this file and end up with 3 different vectors, one called breakfast which contains "bacon", "eggs", sausage" One called

Hi guys, Suppose I have 2 data frames ie: values one 0.32 two 0.25 three 0.11 and values two 0.66 one 0.74 three 0.19 nb the first column is the row names in both cases How can I combine them on the row names column? Ie to make something like values.1 values.2 one 0.32 0.74 two 0.25 0.66 three 0.11 0.19 I guess its

Dear all I've got stuck when trying to replace values in a vector by selecting replacements from a replacement table. I'm trying to use only base functions. Here's a dummy example: > (x <- rep(letters,2)) [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l"

Hello, Sorry, I know the topic has been talked about already but I searched the archives and I'm still unsure of the proper way to have dovecot (imap-login) listen to several addresses and/or several ports. 1. how do I translate dovecot-1 protocol imap { listen = xx.xx.xx.xx:143 yy.yy.yy.yy:143 ssl_listen = xx.xx.xx.xx:993 yy.yy.yy.yy:939 } I started by service imap-login {

Dear R users... I'd like to change this character vector, "zz", zz <- c("12","56","89") to the following numeric matrix. [,1] [,2] [1,] 1 2 [2,] 5 6 [3,] 8 9 Actually, "zz" vector has a long length. Any comments will be greatly appreciated. Kathryn Lord -- View this message in context:

I have a list of groups of xy positions I want to set to 0 in an array full of 1s. When the assignments are done directly from the list, they are incorrect, while if I use a temporary array derived from the list the assignments are correct. The following example will hopefully make my problem clearer. The matrices z and zz are initialised with 1. The z and zz values at coordinates in

Hi, I found that using different contrasts (e.g. contr.helmert vs. contr.treatment) will generate different fitted probabilities from multinomial logistic regression using multinom(); while the fitted probabilities from binary logistic regression seem to be the same. Why is that? and for multinomial logisitc regression, what contrast should be used? I guess it's helmert? here is an example

Dear all, We used the following function to create a spatial plot of a raster image: filled.contour(xx,yy,zz, color = terrain.colors, nlevels=10, main=naamjaar, plot.axes = { contour(Xcoord/1000,Ycoord/1000,lim.data, nlevels = 4, col=4,drawlabels = T, axes = FALSE, frame.plot = FFALSE, add = TRUE);axis(1); axis(2);

Hello - and sorry for what might look like a simple graphics question. I am building an interaction plot for d: d=data.frame(xx=c(3,3,2,2,1,1),yy=c(4,3,4,3,4,3),zz=c(5.1,4.4,3.5,3.3,-1.1,-1.3)) d[[1]]<-as.factor(d[[1]]) d[[2]]<-as.factor(d[[2]]) print(d) interaction.plot(d$xx, d$yy, d$zz, type="b", col=c("red","blue"), legend=F, lty=c(1,2), lwd=2,

Dear R users, I have a data frame (test) including five columns of upper (numeric), lower (numeric), observed (numeric), best_sim (numeric) and stname (factor with 80 levels, each level with different length). Now I would like to write a short program to draw one graph as follow for each level of stname but I would like also to draw each time 12 graphs for the 12 levels of stname in the same

>>>>> Stephen Berman <stephen.berman at gmx.net> >>>>> on Thu, 19 Oct 2017 17:12:50 +0200 writes: > On Wed, 18 Oct 2017 18:09:41 +0200 Martin Maechler <maechler at stat.math.ethz.ch> wrote: >>>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>>>> on Mon, 16 Oct 2017 19:13:31 +0200

Hello I'm having trouble figuring out how to use the output of "segmented()" with a new set of predictor values. Using the example of the help file: ??set.seed(12) xx<-1:100 zz<-runif(100) yy<-2+1.5*pmax(xx-35,0)-1.5*pmax(xx-70,0)+15*pmax(zz-.5,0)+rnorm(100,0,2) dati<-data.frame(x=xx,y=yy,z=zz) out.lm<-lm(y~x,data=dati) o<-## S3

Hi, all, I want to use asterisk SIP as a proxy, and two softphone (Ubiquity SIP Phone) as user agent, like below: Softphone1<-------------->Asterisk SIP<------------>Softphone2 (User Agent) (Proxy) (User Agent) 155.69.xx.xx 155.69.yy.yy 155.69.zz.zz zhou mysipproxy.com

station month bas 190 5 0.000 190 7 1.563 190 10 0.000 190 11 0.000 202 4 18.750 202 5 18.750 202 7 6.250 202 10 4.800 202 11 3.125 198 4 18.750 198 5 31.250 198 7 3.125 198 10 3.200 198 11 12.500 205 4 0.000 205 5 0.000 205 7 0.000

Hi R users, I am new to R and am trying to merge data frames in the following way. Suppose I have n data frames each with two fields. Field 1 is common among data frames but may have different entries. Field 2 is different. Data frame 1: Src Target1 1 aaa 1 bbb 1 ccc 2 aaa 3 ddd Data frame 2: Src Target2 2 aaaa 3 dddd 4 bbbb 4

Hi everyone, I have a question. Now I am reading the resource code of the package "ssfcov". The resource code is as following. I cannot find the resource code of the function "myss2d" anywhere in the package. Can anyone give me a hint how to find it in the package. Thanks a lot!!bv > ssfcov function (time, x, subject, nbasis = 5, centered = FALSE, noDiag = TRUE) {

Hi R, I have a matrix x with repeating row names. > dim(x) [1] 862 19 zz<-matrix(0,4,4) rownames(zz)=c("a","a","b","b") data.frame(zz) (?) I need to use x in a linear regression lm(as.formula(paste("final_dat[,5]~",paste(colnames(x),collapse="+"))),x ) this gives me a error Error in

The following example involves a function whose on.exit() expression both generates an error and catches the error. The body of the function also generates an error. When calling the function wrapped in a tryCatch, should that tryCatch's error function be given the error from the body of the function, since the one from the on.exit has already been dealt with? Currently the outer tryCatch

Hi Thanks Gabor for your suggestion. I am posting the code that worked for me. dataframe1 = data.frame(cbind(Src = c(1,1,1,2,3), Target1 = c('aaa','bbb','ccc','aaa','ddd'))); #must be data frame dataframe2 = data.frame(cbind(Src = c(2,3,4,4,4), Target2 = c('aaaa','dddd','bbbb','eeee','ffff'))); dataframe3 =