similar to: Create data frame from header only

I would like to get the name of the user form the system. Is it possible ? Something like >system.user() returning something like [1] "etber12" Thanks, Etienne [[alternative HTML version deleted]]

Hi all, I am using ggplot2 and continuing to find it very useful and pretty. However, I am trying to create some graphics for publication that would be included in an MS Word document (not my choice!) in Windows Vista. The problem is that I want to use stat_smooth() to add an fitted linear model line along with its 95% confidence band, but I cannot seem to get the confidence band in a format

Hi, With two data sets, one complete and another one partial, I would like to merge them and keep the unmatched lines. The problem is that merge() dosen't keep the unmatched lines. Is there another function that I could use to merge the data frames. Example: completedf <- expand.grid(alpha=letters[1:3],beta=1:3) partdf <- data.frame( alpha= c('a','a','c'),

I try to use ColorRamp as ColorRampPalette (i.e. with the same gradient), but it seems there is a nuance that I've missed. pal.crp<-colorRampPalette( c("blue", "white", "red"), space = "rgb") plot(rep(0,40),pch=16,col=pal.crp(40)) # is great But, using the same gradient with colorRamp is giving erratic colors. pal.cr<-colorRamp(

Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20111212/239c1cbe/attachment.pl>

I can't find any R roadmap. Is it available somewhere ? Etienne -- View this message in context: http://www.nabble.com/Roadmap---tp21791647p21791647.html Sent from the R devel mailing list archive at Nabble.com.

Hello, I'm new in R and I want to do one thing that is very easy in excel, however, I cant do it in R. Suppose we have the data frame: data<- data.frame(A=c("a1","a2","a3","a4","a5")) I need to obtain another column in the same data frame (lets say B=c(b1,b2,b3,b4,b5) in the following way: b1=a1/(a1+a2+a3+a4+a5)

Dear R users, Basically, from the following arbitrary data set: a <- data.frame(id=c(c("A1","A2","A3","A4","A5"),c("A3","A2","A3","A4","A5")),loc=c("B1","B2","B3","B4","B5"),clm=c(rep(("General"),6),rep("Life",4))) > a

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I would like to compare two data sets saved as text files (example below) to determine if both sets are identical(or if dat2 is missing information that is included in dat1) and if they are not identical list what information is different between the two sets(ie output "a1", "a3" as the differing information). The overall purpose would be to remove "a1" and

Dear All, Here is a hypothetical sample (sorry for the clumsy code): A1 <- matrix(1:5, nrow=5, ncol=1) A2 <- matrix(6:10, nrow=5, ncol=1) A3 <- matrix(11:15, nrow=5, ncol=1) A4 <- matrix(16:20, nrow=5, ncol=1) A5 <- matrix(21:25, nrow=5, ncol=1) A6 <- matrix(26:30, nrow=5, ncol=1) B1 <- matrix(c(A1, A2, A3), nrow=5, ncol=3) B2 <- matrix(c(A2, A3, A4), nrow=5, ncol=3) B3

Hello I have a data set like below: plate.id well.id Group HYB rlt1 1 P1 A1 Control SKOV3hyb 0.190 2 P1 A2 Control SKOV3hyb 0.210 3 P1 A3 Control SKOV3hyb 0.205 4 P1 A4 Control SKOV3hyb 0.206 5 P1 A5 Control SKOV3hyb 0.184 385 P1 A1 ovca SKOV3hyb 0.184 386 P1 A2 ovca SKOV3hyb 0.229 387

Hi, How do I rename the column labels in the table? For Instance, if I have a table like this, and I want to have the column labels changed from "A1 A2 A3 A4 A5" to "Mike Kate Michelle Paul Young" A1 A2 A3 A4 A5 1 33 44 55 66 77 2 3 4 5 6 7 7 8 9 and my text file location is: ""/Users/MAC/Desktop/data.txt" When I type in

Dear colleagues, I'd like to reshape a datafame in a long format to a wide format, but I do not quite get what I want. Here is an example of the data I've have (dat): sp <- c("a", "a", "a", "a", "b", "b", "b", "c", "d", "d", "d", "d") tr <- c("A",

On Mon, 15 Dec 2003, jw schultz <jw@pegasys.ws> wrote: > OK, first pass on TODO complete. .... This hardlink bug report is nearly 21 months old... So I took a look at it using 2.5.7. See below. > BUGS --------------------------------------------------------------- > > Fix hardlink reporting 2002/03/25 > (was: There seems

Dear Rxperts, is there way to identify intervals from continuous data (having some kind of a pattern) and then pick the value of most frequency? a1 <- round(rnorm(50,mean=0,0.1),2) a2 <- round(rnorm(50,mean=1,0.2),1) a3 <- round(rnorm(50,mean=5,1),0) a4 <- round(rnorm(50,mean=14,4),0) a5 <- round(rnorm(50,mean=30,8),0) b1 <- rbind(a1,a2,a3,a4,a5) hist(b1,brea=100) # shows

Please help me in writing the R code for this problem. I've been solving this for 4 days. It was hard for me to solve it. It's a simulation problem in R. The problem is My true model is a normal mixture which is given as 0.5 N(-0.8,1) + 0.5 N(0.8,1). This model has two components. I will get a random sample of size 100 from this model. I will do this 300 times. That means, I will have

We have a wireless network that uses 802.1x authentication, in which domain joined computers use their machine credentials to connect. Windows machines do this automatically, and until recently Linux computers could join using wicd, wpa-supplicant, and a simple script that would retrieve the machine password with tdbdump. ( specifically tdbdump -k SECRETS/MACHINE_PASSWORD/DOMAIN

Is there an easy way (or any way) to determine the size of all the objects in an R workspace. I know that "dim" will work on matrices, "length" will work on lists, but what gives the size of a function? After I have worked for a few days I often get confused about what is what in the workspace, so I'm looking for something like "ls -l", to point me toward

Dear friends Hope you all are fine. Suppose we have a list of arrays. a1=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a1=array(a1,dim=c(4,4)); a2=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a2=array(a2,dim=c(4,4)); a3=c(4,4,4,4,0,3,3,4,0,4,4,0,0,0,0,0); a3=array(a3,dim=c(4,4)); a4=c(4,4,4,4,4,0,3,3,3,3,0,4,4,4,0,0,0,0,0,0); a4=array(a4,dim=c(5,4)); a5=c(4,4,4,4,4,0,4,4,4,4,0,3,3,3,0,0,1,1,0,0);