similar to: trivial list question

Hi, I am new in R and stumbled on a problem my (more experienced) friends can not help with with. Why isnt this code working? The function is working, also with the loop and the graph appears, only when I build another loop around it (for different values of p) , R stays in a loop? Can't it take more then 2 loops in one program? powerb<-function(x,sp2,a,b,b1,m) {

Dear R-experts, I have got a dataframe: data ID disease V1 V2 1 p1 1 2 p1 3 3 p3 3 4 p3 5 5 p5 1 From which I extract a usefull table: affect affect 1 3 5 p1 1 1 0 p3 0 1 1 p5 1 0 0 I want to merge this with anotherdataframe: age p1 23 p2 24 p3 23 p4 11 p5 45 If have tried as.data.frame(affect) and other solutions to get the following comment going:

Dear R users, This command works (calling a programm -called whap- with file specifiers etc.): >system('cmd /c "c:\\pheno\\whap --file c:\\pheno\\smri --alt 1 --perm 500"', intern=TRUE) Now I need to call it from a loop to replace the "1" by different number, however I get lost using the quotes: I tried numerous versions of: >i<-1

Dear R-experts, My problem is how to handle a 10GB data file containing genotype data. The file is in a particular format (Illumina final report) and needs to be altered and merged with phenotype data for further analysis. PERL seems to be an frequently used solution for this type of work, however I am inclined to think it should be doable with R. How do I open a text-file, line by line,

I was reading about the project drawer feature in Textmate, which is Mac only. Is there a similar feature in a Windows based text editor that works with R. This feature sounds really useful. Thanks, Graham [[alternative HTML version deleted]]

I am tying myself in knots over subscripts when applied to lists I have a list along the lines of: lis<-list(c("a","b","next","want1","c"),c("d", "next", "want2", "a")) >From which I want to extract the values following "next" in each member of the list, i.e. something along the lines of

Hi, I'm trying to get data from web page and modify it in R. I have a problem with encoding. I'm not able to get encoding right in htmlTreeParse command. See below > library(RCurl) > library(XML) > > site <- getURL("http://www.aarresaari.net/jobboard/jobs.html") > txt <- readLines(tc <- textConnection(site)); close(tc) > txt <- htmlTreeParse(txt,

Sorry. I forgotten the words volume or loudness. But it is know as microphone stroke too, i think. If something can tell me something about that procedure it would complete my pleasure. To bring back memories, i only wanted to know wheather i can change a variable that holds the sound intensity (loudness) needet to start "encoding >> sending" if the speex codec is in voice

Hi, I am using this subset statement and it works outside a function. LIS[[i]]<- lapply(LI, subset, select=cov[[i]]) However, wrapped inside a function this statement produces the same values for every LIS[[1]] which is only the first subset of LI. Does anyone know why is not working correctly inside a function? ff = factor(covariate) nLev <- nlevels(ff) cov <-

On Tue, 2012-05-01 at 19:58 -0500, Peter Bergner wrote: > On Tue, 2012-05-01 at 17:47 -0500, Hal Finkel wrote: > > By default it should build for > > whatever the current host is (no special flags required). To > > specifically build for something else, use: > > -ccc-host-triple powerpc64-unknown-linux-gnu > > or > > -ccc-host-triple

Hi I have a list that has attributes: attributes(lis[2]) $names [1] "150096_at" I want to use those attributes in a function and then use lapply to apply that function to every element of the list, eg for simplicity's sake: my.fun <- function(x) { attributes(x) } Then l2 <- lapply(lis, my.fun) It seems that "attributes(x)" within the function is not the

I am having a problem with rsync hanging after completion. The command I am using is: rsync -vaz --delete /banproc/ backenp650:/banproc (thanks jw for the syntax correction) There were 56 deletions on the destination and ~ 1380 files copied total (I gathered these stats by using grep and wc -l on a saved file of my ssh session to the source host). Below is the last couple of lines on my ssh

On Jan 3, 2014, at 11:01 AM, Andrew Trick <atrick at apple.com> wrote: > > On Jan 3, 2014, at 4:58 AM, Haishan <hndxvon at 163.com> wrote: > >> >> At 2014-01-01 04:36:21,"Andrew Trick" <atrick at apple.com> wrote: >> >> On Dec 31, 2013, at 3:52 AM, Haishan <hndxvon at 163.com> wrote: >> My update steps are shown

So what is the status about LiveVariables. Is there a plan to remove it? After searching in old lvm-dev-mails it is mentioned that LiveVariable still exists due to one pass needing it. And a comment in TargetPassConfig.cpp indicates that the pass in question is TwoAddressInstruction: // FIXME: Once TwoAddressInstruction pass no longer uses kill flags, // LiveVariables can be removed

On Feb 4, 2013, at 3:44 PM, "Sergei Larin" <slarin at codeaurora.org> wrote: > Seems like an easy solution for this case... But let me ask you a more > general question. > The reason I kept on hanging on to the MBB->splice was (probably outdated) > assumption that it will one day properly update liveness for instructions it > moves... That is a serious matter

Is there a way I can get R to automatically enter the browser inside a user-defined function on the generation of an error? Specifically, I'm trying to debug this: Error in as.double.default(sapply(lis, FUN)) : (list) object cannot be coerced to double In addition: There were 38 warnings (use warnings() to see them) > traceback() 8: as.double.default(sapply(lis, FUN)) 7:

At 2014-01-01 04:36:21,"Andrew Trick" <atrick at apple.com> wrote: On Dec 31, 2013, at 3:52 AM, Haishan <hndxvon at 163.com> wrote: Hi, I insert a new machine basic block(MBB) before Greedy Register Allocation, after Simple Register Coalescing. But I encounter a fatal error "regalloc = ... not currently supported with -O0". I use command line with opt level

Dear list members, I am trying, within a lapply command, to print the name of the objects in list or data frame. This is so that I can use odfWeave to print out a report with a section for each object, including the object names. I tried e.g. a=b=c=1:5 lis=data.frame(a,b,c) lapply( lis, function (z) { obj.nam <- deparse(substitute(z)) cat("some other text",obj.nam,"and so

On Jan 3, 2014, at 1:06 PM, Andrew Trick <atrick at apple.com> wrote: > > On Jan 3, 2014, at 12:10 PM, Jakob Stoklund Olesen <stoklund at 2pi.dk> wrote: > >> >> On Jan 3, 2014, at 11:01 AM, Andrew Trick <atrick at apple.com> wrote: >> >>> >>> On Jan 3, 2014, at 4:58 AM, Haishan <hndxvon at 163.com> wrote: >>>

Dea-R community. I'd like to draw your attention to an issue I have recently encountered while doing my current data analysis. I've got an unexpected (to me) result from the command: > augPred(lmList(my.object)), 'my.object' being a grouped data frame of class: > class(my.object) [1] "nfnGroupedData" "nfGroupedData" "groupedData"