Displaying 20 results from an estimated 3000 matches similar to: "extracting elements from a list in vectorized form"
2011 Oct 14
3
Split a list
I have a list of dataframes i.e. each list element is a dataframe with three columns and differing number of rows. The third column takes on only two values. I wish to split the list into two sublists based on the value of the third column of the list element.
Second issue with lists as well. I would like to reduce each of the sublist based on the range of the second column, i.e. if the range of
2010 Sep 22
2
efficient list indexing
Hello everyone,
I need some help with lists inside lists (a good way to emulate a struct)\
Assume that there is a small list called fred:
fred <- list(happy = 1:10, name = "squash")
and a big list called bigfred that includes fred list 5 times
bigfred <- rep(fred,5)
Is it possible somehow to index all these sublists(fred) inside bigfred with a
more direct way like this:
2007 Feb 22
3
List filtration
Hello R-ologists,
Imagine you have a list "list" like so:
>list
[[1]]
[1] "IPI00776145.1" "IPI00776187.1"
[[2]]
[1] "Something" "IPI00807764.1" "IPI00807887.1"
[[3]]
[1] "IPI00807764.1"
[[4]]
[1] "Somethingelse"
What I need to achieve is a filtered list "list2" like so:
>list2
[[1]]
[1]
2008 Nov 04
2
strange list structure question
my problem is more complex than below but I think below can suffice. i
have a list and the name of it at the top level is GGG. so, if i do an
lapply and operate on lower components in the sublist, then I can do as
shown in EXAMPLE 1 and what will come back will be named GGG at the top
level.
but, suppose that , the function inside the lapply function was more
complex and i wanted to
2011 Aug 04
2
How to extract sublist from a list?
Hi everyone,
Suppose I have a list named "lst", see below:
> lst
$sub1
...
$sub1$x
...
$sub1$y
....
$sub2
...
$sub2$x
...
$sub2$y
?
$sub3
...
...
...
Now, I want to extract the sub-sublist $y from every sublist(sub1, sub2...)
and then storage them to a new list.
I know how to extract them by subscript or list name one by one, but I
wonder if there exist some tricks to finish this
2012 Dec 22
1
plotting and saving diagrams automatically
[if the format of my email is changed or is difficult to understand, a text file is attached for easy understanding]Dear useRs,
i was wondering that if its possible in R to automatically generate plots and get it saved at the desired location? i have
data of cancer patients, from about 1000 cities around the world. i have converted that data into a list (called tcp) and
that list has 1000
2005 Aug 24
1
SV: Fax to email using mime-contruct
I also want to try that asterisk guide. But i'm not sure if i understood it correctly.
What exactly do i need to do? Do i need to compile Asterisk with the spanDSP plugin or just configure extensions.conf? The URL to spanDSP in the guide wasn't working.
I also use a traditional internet line to recieve calls and hopefully i will get Fax working soon.
This is so confusing.
Thanks,
Arne
2006 Jul 02
4
:order in partial
Hi,
i was looking through the docs and couldn''t find a good clean solution
for ordering a partial with an :order clause.
say i was iterating over categories and thier corresponding
sub-categories (regular belongs to) and wanted to order the
subcategories according to a certain column;
<% for category in @categories %>
<% render: partial => ''sublist'',
2006 Oct 30
2
which duplicated rows to delete
Hi
Say I've this vector with several duplicates
>x<-c(1,2,3,4,2,6,2,8,2,3)
>which(duplicated(x))
[1] 5 7 9 10 11
But what I realy want is somthing like:
List({2,5,7}, {3,10}, ...)
Then from each sublist I can specify which of the duplicate items to drop
res<-NULL
for(vec in myDuplicateList)
res<-rbind(res, subset(data[vec,], myCrit))
I'll get some of the way by
2008 May 14
4
Accessing items in a list of lists
Using R 2.6.2, say I have the following list of lists, "comb":
data1 <- list(a = 1, b = 2, c = 3)
data2 <- list(a = 4, b = 5, c = 6)
data3 <- list(a = 3, b = 6, c = 9)
comb <- list(data1 = data1, data2 = data2, data3 = data3)
So that all names for the lowest level list are common. How can I most
efficiently access all of the sublist items "a" indexed by the outer
2018 May 03
2
samba 4 joining samba 3 pdc - group mismatch
On Thu, 3 May 2018 15:07:30 +0100
Rowland Penny via samba <samba at lists.samba.org> wrote:
> On Thu, 3 May 2018 10:17:48 -0300
> "Ethy H. Brito via samba" <samba at lists.samba.org> wrote:
>
>
> > > You will never get the same IDs on the PDC and Unix domain member
> > > (this isn't really a problem)
> >
> > I know that. But
2018 May 03
2
samba 4 joining samba 3 pdc - group mismatch
On Thu, 3 May 2018 08:40:37 +0100
Rowland Penny via samba <samba at lists.samba.org> wrote:
> On Wed, 2 May 2018 19:21:46 -0300
> "Ethy H. Brito" <ethy.brito at inexo.com.br> wrote:
>
> This is where it is all going wrong, Your PDC isn't using LDAP, so
> you will have to rely on the winbind 'rid' backend. The lines below are
> wrong in several
2016 Aug 17
5
code to sort otherwise-unsortable "ilist"s, e.g. symbol tables
Dear all,
The below has been tested quite thoroughly by now, including performance-testing by the way of
using a modified compiler that triggers the below while compiling at least an old part of LLVM
["Function.cpp"] and sorting a symbol table with >7000 global variables.
Unfortunately, the optimization I have been working on for which I _thought_ I needed the
ability to sort a
2006 May 08
1
file_column - url_for_file_column issue.
Hi,
url_for_file_column @variable, ''name'', takes an instance variable. My
question is, what if I don''t want to have to retrieve the instance variable
every single time but I have the image id, along with its name with me.
Could I contruct that object in a view and pass it to url_for_file_column:
<% @picture = Picture.new %>
@picture.id = ...
2006 Apr 28
1
Beginner Question - <% ... %>
Regarding: <% (some code) %>
I have some suspicions/general ideas about what this contruct is
supposed to do, but can someone
a) tell me what it''s proper name is and
b) explain or point me to a resource which defines it in a formal way?
Thanks in advance,
Bihal
--
Posted via http://www.ruby-forum.com/.
2009 Aug 24
1
[LLVMdev] question about LLVMContext
Hi devs:
I'm trying to do something quite simple, but it seems I need to provide an
LLVMContext& to do it. I'm not sure what the 'proper' LLVMContext would be
in my situation.
I'm writing an analysis that is a FunctionPass. At some point in the pass,
I am given a Value * representing an N-bit integer. My goal is to contruct
two ConstantInt instances, for comparison
2006 Apr 20
1
Mutually Orthogonal Latin Squares
Hi all,
The package crossdes could contruct a complete sets of mutually orthogonal latin squares.
The construction works for prime powers only.
I hope to know whether there is a way to construct a mutually orthogonal Lation square for
10 or other numbers that could not be prime powers.
Thanks for any suggestions.
Best wishes,
Jinsong Zhao
2009 Jul 18
1
Building a big.matrix using foreach
Hi there!
I have become a big fan of the 'foreach' package allowing me to do a
lot of stuff in parallel. For example, evaluating the function f on
all elements in a vector x is easily accomplished:
foreach(i=1:length(x),.combine=c) %dopar% f(x[i])
Here the .combine=c option tells foreach to combine output using the
c()-function. That is, to return it as a vector.
Today I discovered the
2004 Jan 22
1
Bug in termplot?
Hi,
Is this a bug in termplot, or (once again) do I just not understand what R
is really doing?
I am using termplot to contruct partial residual plots,
1. For all terms at once
2. One term at a time
but I get different results from these two methods. To give a concrete
example, I would have thought the top and bottom rows of the plot
constructed with the following code would be identical.
2018 May 02
2
samba 4 joining samba 3 pdc - group mismatch
Hi all
Background: I am not a samba expert, not even close!
I have a ancient samba 3 (Server role: ROLE_DOMAIN_PDC) and I intend to
migrate all files to a samba 4 (Server role: ROLE_DOMAIN_MEMBER)
Users will stay in S3 for now.
Samba 4 joined samba 3 with no problems.
I rsync'ed all files and its permissions (rsync -a ...).
But...
I cannot find a way that makes S4 sees S3 users and groups