similar to: strsplit, keeping delimiters

On Wed, 12 Apr 2023 08:29:50 +0000 Emily Bakker <emilybakker at outlook.com> wrote: > Some example data: > ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? > ?leucocyten ? grampositieve coccen +? > ? > I want to split the strings such that I get the following result: > c(?leucocyten +?, ??gramnegatieve staven +++?, > ??grampositieve staven ++?) >

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

Hi all, Is there a tool in base R to extract matched expressions from a regular expression? i.e. given the regular expression "(.*?) (.*?) ([ehtr]{5})" is there a way to extract the character vector c("one", "two", "three") from the string "one two three" ? Thanks, Hadley -- http://had.co.nz/

Hi, if I have this string: "a.b.c.d" and I use this function: unlist(strsplit("a.b.c.d", "\\.")), I get this as my output: "a", "b", "c", and "d". Is there a way to just split on the first period so I obtain only two pieces like: "a" and "b.c.d"? Anyways, thanks in advance! -- View this message in context:

#how do I break these up into first two letters (RM), number, and then the last part #is there an easily accessible regex tutorial on the internet? v = (structure(1:122, .Label = c("RM215Temp", "RM215SpCond", "RM215DO.Conc", "RM215Depth", "RM215pH", "RM215ORP", "RM215Turbidity.", "RM215Battery", "RM215DO.",

Dear fellow R-help members, I hope to seek your advice on how to parse/manage a dataset with hundreds of columns. Two examples of these columns, 'cancer.problems', and 'neuro.problems' are depicted below. Essentially, I need to parse this into a useful dataset, and unfortunately, I am not familiar with perl or any such language. data <- data.frame(id=c(1:10))

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

Greetings, I have a vector of values that are a word followed by a number, e.g., x = c("Apple12","HP42","Dell91"). The goal is to split this vector into two vectors such that the first vector contains just the words and the second contains just the numbers. I cannot use strsplit (or at least I do not know how) as there is no obvious separator. I can use sub to

Hi all, is there any function to find some words in a character-string? For example suppose the string is : "gdfsa-sdhchc-88", now I want to find whether this string contains "sdhch". Is there any R function to do that? Regards, -- View this message in context: http://www.nabble.com/Searching-within-a-ch.-string-tp23484010p23484010.html Sent from the R help mailing list

Hi, Is there a way in R to get the string which matches the expression, where the expression is a substring of the parent string. Lets say, I have $i <- "transcript:ENST0000112334 pid:ENSP000012345" What I need is the string "pid:ENSP000012345" from $i using the query "ENSP". Appreciate your comments. Praveen Surendran School of Medicine and

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Dear List, I have an ascii text file with data I'd like to extract. Example: Year Built: 1873 Gross Building Area: 578 sq ft Total Rooms: 6 Living Area: 578 sq ft There is a lot of data I'd like to ignore in each record, so I'm hoping there is a way to use strings as delimiters to get the data I want (e.g. tell R to take data between "Built:" and "Gross" -

Hi again, how to elegantly split s <- "ABCDEFGT(P)HIJK" into "A" "B" "C" "D" "E" "F" "G" "T(P)" "H" "I" "J" "K" (independently of which letters 'T' or 'P' actually represent ...). Please jumstart my regexing, Joh

I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Hi Everyone, I'm new to programming R and have accomplished my goal, but feel that there is probably a more efficient way of coding this. I'd appreciate any guidance that a more advanced programmer can provide. My goal -- I would like to find the length of the longest word in a string containing many words separated by spaces. How I did it -- I was able to find the length of the

Is there a way of reading in a file in a way that each line becomes a vector: for example: meals.txt breakfast bacon eggs sausage lunch sandwich apple marsbar crisps dinner chicken rice custard pie I want to read in this file and end up with 3 different vectors, one called breakfast which contains "bacon", "eggs", sausage" One called

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

Are there packages that allow improved String and URL processing? E.g. extract parts of a URLs such as sub-domains, top-level domain, protocols (e.g. https, http, ftp), file type based on endings, check if a URL is valid or not, etc... I am currently only using split and paste. Are there better and more efficient ways to handle strings e.g. finding sub-strings or to do pattern matching? What