similar to: Subset by Factor by date

Displaying 20 results from an estimated 10000 matches similar to: "Subset by Factor by date"

2009 Apr 16
3
"reverse truncate" to extract only decimal values
hello there, Is there a way of truncating in the opposite direction so as to retain only the values to the right of the decimal?? i.e. rather than: > trunc(39.5) [1] 39 i would get something like: > revtrunc(39.5) [1] 0.5 I've been searching to no avail but I imagine there is a very simple solution! Tyler -- View this message in context:
2008 May 05
3
merge numerous columns of unequal length
I have numerous objects, each containing continuous data representing the same variable, movement rate, yet each having a different number of rows. e.g. d1<-as.matrix(rnorm(5)) d2<-as.matrix(rnorm(3)) d3<-as.matrix(rnorm(6)) How can I merge these three columns side-by-side in order to create a table regardless of the difference in length? I wish to analyze the output in a spreadsheet
2008 Jun 02
4
NOT-SO-SIMPLE function!
I am trying to set up a function which processes my data according to the following rules: 1. if (x[i]==0) NA 2. if (x[i]>0) log(x[i]/(number of consecutive zeros immediately preceding it +1)) The data this will apply to include a variety of whole numbers not limited to 1 & 0, a number of which may appear consecutively and not separated by zeros. Below is an example with a detailed
2008 Sep 16
1
analyze subsample of dataframe
Hi there, I'm dealing with a pretty big dataset (~22,000 entries) with numerous entries for every day over a period of several years. I have a column "judy" (for Julian Day) with 0 beginning on Jan. 1st of every new year (I want to compare tendencies between years). However, in order to control for a leap year (2004), I simply need to subtract 1 from every judy value for the year
2009 Mar 28
1
Find inflection points using smooth.spline
Is there any way to identify or infer the inflection points in a smooth spline object? I am doing a comparison of various methods of time-series analysis (polynomial regression, spline smoothing, recursive partitioning) and I am specifically interested in obtaining the julian dates associated with the inflection points inferred by the various models. Tyler e.g.
2008 Jun 19
2
Advanced Filtering problem
http://www.nabble.com/file/p18018170/subdata.csv subdata.csv I've attached 100 rows of a data frame I am working with. I have one factor, id, with 27 levels. There are two columns of reference data, x and y (UTM coordinates), one column "date" in POSIXct format, and one column "diff" in times format (chron package). What I am trying to do is as follows: For each day
2008 Oct 13
2
split data, but ensure each level of the factor is represented
Hello, I'll use part of the iris dataset for an example of what I want to do. > data(iris) > iris<-iris[1:10,1:4] > iris Sepal.Length Sepal.Width Petal.Length Petal.Width 1 5.1 3.5 1.4 0.2 2 4.9 3.0 1.4 0.2 3 4.7 3.2 1.3 0.2 4 4.6 3.1 1.5
2009 Sep 09
1
change character to factor in data frame
Dear all I have a simple problem which I thought is easy to solve but what I tried did not work. I want to change character variables to factor in data frame. It goes easily from factor to character, but I am stuck in how to do backwards conversion. Here is an example irisf<-iris irisf[,2]<-factor(irisf[,2]) # create second factor str(irisf) 'data.frame': 150 obs. of 5
2010 Feb 19
3
plot circular histogram
In conducting studies of animal orientation and displacement, I need to produce circular histograms of angles (bearings in radians 0-2pi) where the centre of the circle indicates very few observations for a given bin of angles and outwardly concentric circles indicate greater frequencies of observations for a given bin of angles. I'd like not to have to write the function myself but I
2012 Jul 19
2
Subsetting problem data, 2
Hello, I didn't give enough information when I sent an query before, so I'm trying again with a more detailed explanation: In this data set, each patient has a different number of measured variables (they represent tumors, so some people had 2 tumors, some had 5, etc). The problem I have is that often in later cycles for a patient, tumors that were originally measured are now missing (or
2015 Nov 19
7
[Bug 93004] New: Guild Wars 2 crash on nouveau DX11 cards
https://bugs.freedesktop.org/show_bug.cgi?id=93004 Bug ID: 93004 Summary: Guild Wars 2 crash on nouveau DX11 cards Product: Mesa Version: git Hardware: Other OS: All Status: NEW Severity: normal Priority: medium Component: Drivers/DRI/nouveau Assignee: nouveau at
2008 Feb 26
2
Subsetting within xyplot()
All, I'm having problems w/ a simple attempt to subset an xyplot. The first plot below is a plot of y versus x for certain values of a third categorical variable z. Now I'd like to further restrict this to certain values of variable y. Neither of the two attempts below work. Any suggestions much appreciated. (note: I don't want to merely use ylim since I have a loess plot and I
2019 Mar 23
4
topenv of emptyenv
I was surprised just now to find out that `topenv(emptyenv())` equals ? `.GlobalEnv`, not `emptyenv()`. From my understanding of the description of `topenv`, it should walk up the chain of enclosing environments (as if by calling `e = parent.env(e)` repeatedly; in fact, that is almost exactly its implementation in envir.c) until it hits a top level. However, `emptyenv()` has no enclosing
2015 Dec 10
6
How do I reliably and efficiently hash a function?
I?ve got the following scenario: I need to store information about an R function, and retrieve it at a later point. In other programming languages I?d implement this using a dictionary with the functions as keys. In R, I?d usually use `attr(f, 'some-name')`. However, for my purposes I do not want to use `attr` because the information that I want to store is an implementation detail that
2010 Jul 18
2
simple loop(?) analysing subsets
Hi All, I have a large data set with many columns of data. One of these columns is a species identifier and the remainder are variables such as temperature or mass. Currently I am carrying out a single regression on subsets of the data set, e.g. separated data sets with only the data from one species at a time. I have been searching for a thread that will help me to understand how best to repeat
2012 Apr 01
1
trouble with small multiples on a date variable
Hello, I am loading a DBF file into R via JGR and am having trouble creating small multiple histograms on a date variable. Hist() handles the variable correctly. But I've been unable to work with lattice or ggplot2 despite trying format() and as.POSIXct(). Dates are in the format "2010-05-15" and the grouping variable is categorical. I'd appreciate it if someone would provide an
2003 Sep 12
2
Sorting a vector by date
Hello out there.... Again I have a problem and I stuck... How can I sort a vector of dates? For example I have the vector a<-ISOdate(2001, 1, 1) + 70*86400*runif(10) How can this vector be sorted chronological? And what's the function I should work with to handle these entries? (in sense of: which(a>2001-01-04) or somehting like that) Thank you for helping M.Kirschbaum
2006 Jun 22
5
(Still) no printing possible in wine 0.9.15
Hello List, since my first posting with the same subject was somehow incomplete, i decided to repost my question. I just installed wine-0.9.15, because I wasn't able to print with wine-0.9.8, but unfortunately the problem persists. My systems: Workstation: Gentoo 2006.0 Cups-1.1.23 no /etc/printcap no local printer connected Print server: Gentoo 2006.0 Cups-1.1.23 Printer: Canon i560
2011 Feb 14
1
Selecting particular rows in a table
Hi, I have a huge table with 134,000 entries. I want to choose only rows 60,000 to 90,000. Please help me on how to do this. V1 V2 V3 V4 1 31.10267 168.3204 41 0.4 2 31.19941 168.1488 41 0.4 3 31.29580 167.9764 41 0.4 4 31.39183 167.8034 41 0.4 5 31.48750 167.6297 41 0.4 6 31.58280 167.4553 41 0.4 7 31.67774 167.2803 41 0.4 8 31.77229 167.1045 41 0.4 9 31.86648 166.9281
2005 Jun 03
1
factor vector manipulation
Hi, I have one question on factor vector. I have 3 factor vectors: a<-factor(c("1", "2", "3")) b<-factor(c("a", "b", "c")) c<-factor(c("b", "a", "c")) what I want is like: c x 1 b 2 2 a 1 3 c 3 which means, I use b as keys and vector a as values and I find values for c. I used the following