similar to: Barplot help

# I would like to outline the squares in the legend with a black line. Does anyone know how to do this? x.t <- structure(c(5987.387, 4354.516, 3685.789, 6478.592, 5924.315, NA, 8386, 5559.468, NA, 4651.273, 3967.5, NA, 4339.167, 5053.56, NA, 4631.978, 4808.694, NA, 5217.306, 4017.632, NA, 5846.903, 3969.883, NA, 3867.825, 3910.236, NA, 3886.434, 3782.094, NA, 3959.668, 3961.286, NA, 3848.853,

I have a file, each column of which is a separate year, and each row of each column is mean precipitation for that month. Looks like this (except it goes back to 1964). month X2000 X2001 X2002 X2003 X2004 X2005 X2006 X2007 X2008 X2009 1 1.600 1.010 4.320 2.110 0.925 3.275 3.460 0.675 1.315 2.920 2 2.960 3.905 3.230 2.380 2.720 1.880 2.430 1.380

I can't understand what is happening. This is the code and results: > agoa <- read.table(file = "C:/Users/HTPC/Documents/_Documents/Research/WithDidia/AGOAUSImports.txt", header = T, sep = "\t", dec = ".", na.strings = "NA", stringsAsFactors = T)# > str(agoa); names(agoa) 'data.frame':109 obs. of  19 variables:  $ X    : Factor w/ 39

I am just beginning to use Sweave with Lyx on a Mac (R2.8.1). I have 12 chunks of Sweave code that work fine, but this piece: <<>>= library(car)

Hello All, I have the following dataset: Year 2006 2007 Jan Jan 0.0204 0.0065 Feb Feb 0.0145 0.0082 Mar Mar 0.0027 0.0122 > dput(d_tmp) structure(list(Year = c("Jan", "Feb", "Mar"), `2006` = c(0.0204, 0.0145, 0.0027), `2007` = c(0.0065, 0.0082, 0.0122)), .Names = c("Year", "2006", "2007"), row.names = c("Jan",

Folks, I have a data frame with columns 200401, 200402, ..., 201207, 201208. These represent years/months. What would be the best way to sum these columns by year? What about by quarter? Thanks for your time, KW -- [[alternative HTML version deleted]]

Hello I am running Windows Vista 32 with 4 GB (installed, though Windows of cours= e only recognizes 3326 MB, as reported by Windows "My Computer") I am running R 2.7.1 I was trying to read in a comma delimited single column CSV file, assign th= at file to a variable ("data") and then extract a sample (assigned to "part= ial"). I was getting memory allocation

Estimados ¿Cómo puede emitirse un comando para leer estos datos así como están? , yo solo lo sé hacer cuando unos están detrás de otros en una sola columna . Saludos José -- Este mensaje le ha llegado mediante el servicio de correo electronico que ofrece Infomed para respaldar el cumplimiento de las misiones del Sistema Nacional de Salud. La persona que envia este correo asume el

Hi all, how can I divide two tables of the same dimension so that all names are preserved, ie do not become NA? I have "tab1" and "tab2", each having names in the first column. I want "tab3" with the same names and values "tab1/tab2". Thanks, Serguei

I see no bug here. R is telling you that you have insufficient memory available: see also ?"Memory-limits". See also rw-FAQ Q2.9. Note that we don't have a reproducible example and in particular have no idea of how many columns this data frame has. The 'R Data Import/Export' manual gives you many hints on how to do this more efficiently, and it is referenced from the