similar to: applying a function recursively

Dear R gurus, first let me apologize for a question that might hve been answered before. I was not able to find the solution yet. I want to concatenate two lists of lists at their lowest level. Suppose I have two lists of lists: list.1 <- list("I"=list("A"=c("a", "b", "c"), "B"=c("d", "e", "f")),

To whom it may concern I made some analysis with R using the command Anova. However, I found some problmes with the output obtained by selecting type II o type III sum of squares. Briefly, I have to do a 2x3 mixed model anova, wherein the first factor is a between factor and the second factor is a within factor. I use the command Anova in the list below, because I want to obtain also the sum

the study design of the data I have to analyse is simple. There is 1 control group (CTRL) and 2 different treatment groups (TREAT_1 and TREAT_2). The data also includes 2 covariates COV1 and COV2. I have been asked to check if there is a linear or quadratic treatment effect in the data. I created a dummy data set to explain my situation: df1 <- data.frame( Observation =

Hi, I have a three dimensional array, e.g., my.array = array(0, dim=c(2,3,4), dimnames=list( d1=c("A1","A2"), d2=c("B1","B2","B3"), d3=c("C1","C2","C3","C4")) ) what I would like to get is then a dataframe: d1 d2 d3 value A1 B1 C1 0 A2 B1 C1 0 . . . A2 B3 C4 0 I'm sure there is one function to do

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Colleagues, I want to create the following array: "A1", "A2", "A3", "B1", "B2", "B3", "C1", "C2", "C3" I recall that there is a trick using "c" or "paste" permitting me to form all combinations of c("A", "B", "C") and 1:3. But, I can't recall the

Hi, Suppose, if I create 15 files in my working directory. set.seed(48) lapply(1:15,function(i) {m1 <- matrix(sample(1:20,1686*2,replace=TRUE),nrow=1686,ncol=2); write.table(m1,paste0("file_",i,".txt"),row.names=FALSE,quote=FALSE)}) ?D <-dir() D1 <- D[order(as.numeric(gsub("\\D+","",D)))] D1 ?res <- t(sapply(D1,function(x) {x1<-

Dear all: I have this: A1 B1 C1 D1 E1 A2 B2 C2 D2 E2 A3 B3 C3 D3 E3 And I want this A1 E1 B1 E1 C1 E1 D1 E1 A2 E2 B2 E2 C2 E2 D2 E2 A3 E3 B3 E3 C3 E3 D3 E3 Example: m<- matrix(1:15,nrow=3,byrow=T) m v<- unlist(list(t(m[,1:4]))) u<- rep(c(5,10,15),c(4,4,4)) data.frame(v,u) This is the result I want but I would like to learn a simpler way to do it. Any clue?

Dear R Users Hi, I have very emergency problems in my programming about finding MLE with optim command. I reproduced it with real data. I guess that my function object in optim is very sensitive because it has power function . Then optim give me lower or initial values for estimates with these warnings for Hessian matrix computation: 1: In log(B2 * (C2^(y + v))) : NaNs produced 2: In log(B3

Hi, I have an R programming problem and I havent found anything in the documentation yet: I have a data matrix, in which two neighbouring columns represent replicates of the same experiment, e.g. something like this: A A B B C C row1 1 1 1 2 2 2 row2 1 1 1 1 1 2 I would like to test, if the values for the two replicates in a row are the same or if they differ and generate a new

Hello all, Maybe I'm being thick, but I was trying to figure out a simple way to create a list with the same dimension of another list, but populated with NA values. masterlist = list( aa=list( a=matrix(rnorm(100),10,10), b=matrix(rnorm(130),13,10), c=matrix(rnorm(140),14,10)), bb=list(

I have a dataset that is basically structureless. Its dimension varies from row to row and sep(s) are a mixture of tab and semi colon (;) and example is HEADER1 HEADER2 HEADER3 HEADER3 A1 B1 C1 X11;X12;X13 A2 B2 C2 X21;X22;X23;X24;X25 A3 B3 C3 A4 B4 C4 X41;X42;X43 A5 B5 C5 X51 etc., say. Note that a blank

Hi all, I frequently encounter datasets that require me to repeat the same calculation across many variables. For example, given a dataset with total employment variables and manufacturing employment variables for the years 1990-2010, I might have to calculate manufacturing's share of total employment in each year. I find it cumbersome to have to manually define a share for each year and

Hi I'm trying two combine two vectors that have different lengths. This without recursive the shorter one. E.g., a <- seq(1:3) b <- seq(1:6) Thanks in advance Serdar [[alternative HTML version deleted]]

Hi, I am trying to generate a figure of 9 plots that are contained in one device by using par(mfrow = c(3,3,)) I would like to have 1 common legend for all 9 plots somewhere outside of the plotting area (as opposed to one legend inside each of the 9 plots, which the function legend() seems to generate by default). Any hint how to do this? Best, Georg

There are function which does have optimization opportunities but because of may-alias memory dependencies sometimes optimization is not effective. May be runtime checks kills the gains of optimization. For such cases aiming to do interprocedural function specialization optimization where in the clone function version no-alias assumption can be assumed and the original function version will hold

See if the following helps: > m <- outer(letters[1:5], 1:4, paste, sep="") > m [,1] [,2] [,3] [,4] [1,] "a1" "a2" "a3" "a4" [2,] "b1" "b2" "b3" "b4" [3,] "c1" "c2" "c3" "c4" [4,] "d1" "d2" "d3" "d4" [5,]

Hello, R experts, Sorry for asking this question again again since I really want a help! I have a two-factor experiment data and like to calculate estimates of interation contrasts say factor A has levels of a1, a2, and B has levels of b1, b2, b3, b4, and b5 with 3 replicates. I am not sure the constrast estimate I got is right using the script below:

A common process when data is obtained in an Excel spreadsheet is to save the spreadsheet as a .csv file then read it into R. Experienced users might have learned to be wary of dates (as I have) but possibly have not experienced what just happened to me. I thought I might just share it with r-help as a cautionary tale. I received an Excel file giving patient details. Each patient had an ID

Dear R community, I am a beginner to R and have a question concerning mget, about I could not find anything in the various documentation. I have a column in a dataframe x for which I want to get values in y: mget(x[,1], env=y, ifnotfound=NA) I receive an error mesage: Error in mget(x[, 1], env = y, ifnotfound = NA) : attempt to use zero-length variable name this is probably due to