similar to: TR : Probs with paste

Hello all, After some months doing ok with R, I am embarrassed that I have to make this my first posting to the help list. I am trying to run the following (actually in a loop but shortened for the post): risk.factors <- c("file$A", "file$B", "file$C", "file$D", "file$E") table(paste(risk.factors[1])) but run into problems

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at

Since you only have 3 predictors, each categorical with a small number of categories, you can use expand.grid to make a data.frame containing all possible combinations and give that the predict method for your model to get all possible predictions. Something like the following untested code. newdata <- expand.grid( Humidity = levels(Humidity), #(High, Medium,Low)

? data=read.table("http://statcourse.com/research/boston.csv", , sep=",", header = TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) Please: Show me the tree. Mark -------- Original Message -------- Subject: Re: [R] help with rpart From: "Stephen Milborrow" <[1]milbo at sonic.net>

Hi Manuel, I've taken the liberty of adding the r-help list back to this email, even though you sent your reply just to me, so that others may contribute. On Fri, Mar 9, 2012 at 6:27 PM, Manuel Sp?nola <mspinola10 at gmail.com> wrote: > Thank you Sarah, > > I am thinking more on?habitat mapping and landscape metrics. Then you've probably seen the adehabitat* and SDMTools

On Tue, Jun 19, 2012 at 1:11 PM, Saima Bashir <saimabashir11 at yahoo.com> wrote: > Hi Sarah, > > I have installed and loaded them into R but get same error. > > I am using four equations, cross-section data, version R i386 2.15.0. That is by no means all the information I requested in my original reply, or all that is requested in the posting guide. Nobody can help you

Hello everyone, I've come up with a problem with using paste() inside apply() that I can't seem to solve. Briefly, if I'm using paste to collapse the rows of a data frame, AND the data frame contains strings with spaces, AND there are NA values in subsequent columns, then paste() introduces spaces. This only happens with that particular combination of data values and commands. I have

? data=read.table("http://statcourse.com/research/boston.csv", , sep=",", header = TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) predict(fit,data[4,]) plot only reveals part of the tree in contrast to the results on obtains with CART or C5 -------- Original Message -------- Subject: Re: [R] help with rpart From: Sarah

I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,

The real weird thing is I wrote "weird" and it comes out "wired"... The background is that I did a lot of sparse matrices calculations. Therefore need some indices tweaks, e.g subtract a block from a big matrix. Then I just create an indicies matrix and use it directly as a vector since a matrix is just a vector with dimensions attributed in R. I know I can convert them to a

I still need the output to match my requiremnt in my original post. With decision rules "clusters" and probability attached to them. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message

Folks: I consider my reply below rather clumsy: One has to keep track of index numbers other than that which is inserted and must separately change column names. Is there as "essentially better" way to do this, either via base R or via an R package. I leave it to you to define "essentially better." Thanks. Cheers, Bert On Mon, Aug 1, 2011 at 10:17 AM, Bert Gunter

Thank you Sarah.I'm glad it was a quick fix: On Fri, Feb 5, 2010 at 8:50 AM, Sarah Goslee <> wrote: > You're not only removing a row of data, you are invoking the default > behavior of subset, which is to collapse the subsetted result to the > smallest possible type, which in this case is a vector. Vectors have > no rows, and thus no row names. > > You need the

Hello to all, I still have this doubt. I'd like to colour the different labels of my dendrogram each one with a different colour. How can I do? I guess I could do using *edgetext* and then *t.col* or* lab.col* but I don't know how to add edgetext to my dendrogram. Can you help me please? Example: require(graphics); require(utils) hc <- hclust(dist(USArrests), "ave") (dend1

I thought Sarah's reply was great and, alas, should probably be templated for this list. Not sure it fits as a fortunes package entry, but I thought it at least worthy of consideration. Cheers, Bert >> ... >> I appreciate any suggestions for this problem. Sarah Goslee replied: > Suggestions? Yes. Read the posting guide and follow it. It isn't clear that > this is even

Thank you Sarah and Mike for your explanations. My final objective is to produce maps (png image or any kind of extension I can import in LaTeX) where rainfall data are interpolated, using the Inverse Distance method or Kriging. My input file (pointfile.csv in the reported example) reports the station code, lat and long of the meteorological station and the rainfall value (which might be the

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

Sarah's solutions are good, and here's another, even more basic: tmp1 <- unique(dat1$B) tmp2 <- seq_along(tmp1) dat1$C <- tmp2[ match( dat1$B, tmp1) ] > dat1 N B C 1 1 29_log 1 2 2 29_log 1 3 3 29_log 1 4 4 27_cat 2 5 5 27_cat 2 6 6 1_log 3 7 7 1_log 3 8 8 1_log 3 9 9 1_log 3 10 10 1_log 3 11 11 3_cat 4 12 12 3_cat 4 As a single line

Hi Scott, Where did you get this function originally? I can't find anything about it. What OS are you using? What says, "not available for the version"? Where are you getting that error? What are you trying to accomplish? What does that function actually do? It's impossible to suggest a work-around for a function of unknown purpose and origin. (The posting guide for this

Hello, I imagine that I'm missing something straightforward, but a run thru the help files didn't turn up an answer. I noticed while formatting some figures for publication that text enclosed in expression() and used for a title displays differently than a string, regardless of the par options. On both postscript() and x11() devices, the regular text is heavier than the expression text.