similar to: write.table() error

Hi, ?In the example you provided, it looks like the dates in Date2 happens first.? So, I changed it a bit.? DataA<- read.table(text=" ID,Status,Date1,Date2 ??? ??? ?????? 1,A,3-Feb-01,15-May-01 ??? ??? 1,B,15-May-01,16-May-01 ??? ??? 1,A,16-May-01,3-Sep-01 ??? ??? ??? ??? ??? 1,B,3-Sep-01,13-Sep-01 ??? ??? ??? ??? ??? 1,C,13-Sep-01,26-Feb-04 ??? ??? ??? ??? ???

Greetings everyone, I'm trying to add a specific table or a specific number of rows (e.g.44) to a table with no success. This is my basic table > head(dataA) year plot spp prop.B DCA1 DCA2 DCA3 DCA4 1 2000 1 a1 0.031079 -0.0776 -0.0009 0.0259 -0.0457 2 2000 1 a2 0.968921 -0.0448 0.1479 -0.1343 0.1670 3 2000 2 a1 0.029218

i am working with two sets of likert scale type (4 distinct values) data: dataA <- rep(1:4, c(3,2,2,4)) dataB <- rep(1:4, c(5,4,3,2)) i can now (bar)plot both of these separately and compare the distributions. plot(table(dataA), type='h') plot(table(dataB), type='h') is there a way to plot both of them in one plot, so that the bars for value "1" (dataA: 3,

NOTE: posted this to gluster-devel when I meant to post it to gluster-users 01 | 02 mirrored --| 03 | 04 mirrored --| distributed 05 | 06 mirrored --| 1) Would this command work for that? glusterfs-volgen --name repstore1 --raid 1 clustr-01:/mnt/data01 clustr-02:/mnt/data01 --raid 1 clustr-03:/mnt/data01 clustr-04:/mnt/data01 --raid 1 clustr-05:/mnt/data01 clustr-06:/mnt/data01 So the

Hello all, I have a data frame dataa: newdate newstate newid newbalance newaccounts 1 31DEC2001 AR 1 1170 61 2 31DEC2001 VA 2 4565 54 3 31DEC2001 WA 3 2726 35 4 31DEC2001 AR 3 2700 35 The following gives me the balance of state AR:

I would like to merge two dataframes, but i have a condition that needs to used for the merge as well. the rows (observations) in each dataframe are identified by each person's ID and by the date of the observation. Basically I would like it to be merged based on both ID (exact match) and date (a condition where one dataframe's date must be after the other dataframe's date).

Hi, I am trying to use glm to fit my data, wondering if there is a easy way to fit a glm without typing all the explanatory variable names. For example, if I have 100 explanatory variables x1, x2, ..., x100 and response variable is y, I don't want to do something like glm1 <- glm(y ~ x1 + x2 + ... + x100, family = gaussian, data = dataA) since it would be a lot of typing. Many thanks,

Hi R-Help! I am trying to use R2WinBUGS but I get the following error message in WinBUGS (and there must be something wrong with my R statement as I tried it directly in WinBUGS and it worked): display(log) check(C:/Documents and Settings/Daikon/Roche/pop_model.txt) model is syntactically correct data(C:/Documents and Settings/Daikon/Roche/data.txt) expected key word structure compile(7) ...(and

Hi, I want to plot this matrix (I attach the data), it is suposed that each column is a different time series. If I do g<-read.table("dataADF.txt", header=F) and plot(g[,1],type="l") it plots the first column plot if I want in a unique graph each colums of dataA, all in one. How should I proceed?There is a direct pre-defined code? And If I wanted a plot by each

Hello, I would like to read sets of files within a folder, perhaps using recursive methods. Right now, I rename the files before import. It would be even better to do this without renaming files, without providing explicit filenames, perhaps by importing files based on chronology, and translating each filename into a header? Please excuse my ignorance, and help cure my clunky programming

Thanks for your answers Stephen and Ben, I hope I am posting on the correct list now. I managed so far to run the multinomial model with random effect with the following command: MCMCglmm(fixed=cbind(Apsy,Mygl,Crle,Crru,Miag,empty) ~ habitat:trait,random=~idh(trait):mesh,family="multinomial12", data=dataA,rcov=~trait:units) (where multiple responses are different species, Habitat

I have two dataframes, the first column of each dataframe is a unique id number (the rest of the columns are data variables). I would like to figure out how many times each id number appears in each dataframe. So far I can use: length( match (dataframeA$unique.id[1], dataframeB$unique.id) ) but this only works on each row of dataframe A one-at-a-time. I would like to do this for all of

Hi, I used Dr. Harrell's rms package to make a nomogram. Below is my code for nomogram and calculate total points and probability *in original data set* used for building the nomogram. *My question is how I get the formula for calculating the survival probability for this nomogram. Then I can use this formula to do validation by using other data set. * f1 <- cph(Surv(retime,dfs) ~

I have a distributed/replicated setup with Glusterfs 3.0.2, that I'm testing on 4 servers, each with access to /mnt/gluster (which consists of all directories /mnt/data01 - data24) on each server. I'm using configs I built from volgen, but every time I access a file (via an 'ls -l') for the first time, I get all of these messages in my logs on each server: [2010-05-04 10:50:30] W

Jim, Both the branch and the branch target are in the same function. This is known delta and should not matter where it is relocated because the delta will remain the same once it is a .o or later. I just want to know how to tell the compiler that this expression is target offset - branch offset. More generally, I want to know the rules for setting up expressions in general. I have no idea if

Hello! If I have a matrix as 1 2 2 3 and I want to change the value 2 in 0, what can I do? Thank you -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

Hello, I'm hoping someone with a wide experience with R may be able to see what the program is trying to tell me. I've got an array: y1=rnorm(41,0.2) y2=rnorm(41,0.2) y3=rbind(y1,y2) data11<-array(0,c(41,2,2)) data11[,1,]=y3 data11[,2,]=y3 rownames(data11)<-rownames(data11, do.NULL = FALSE, prefix = "Obs.") colnames=c("V","R")

Hello, I'm working with an array; I'm trying to make it so that an array of dim(42,2,2) has names whose length corresponds to that of the array, and am hoping someone with experience with this can see what I'm not doing correctly: data11 = array(0,c(41,2,2)) y = lsoda(x0,times,fhn$fn.ode,pars)#This is make.fhn() from colloc infer package# y = y[,2:3]

Suppose I have following dataset : > head(data1) Date Return 1 03/31/00 0.14230650 2 04/28/00 -0.03276228 3 05/31/00 -0.06527890 4 06/30/00 -0.04999873 5 07/31/00 -0.01447902 6 08/31/00 0.22265729 Now I convert it to zoo object : > data11 = zoo(data1[,2], as.Date(data1[,1], format="%m/%d/%y")) > head(data11) 2000-03-31 2000-04-28 2000-05-31

Hello, I am using Dr. Harrell's rms package to make a nomogram. I was able to make a beautiful one. However, I want to change 5-year survival probability to 5-year failure probability. I couldn?t get hazard rate from Hazard(f1) because I used cph for the model. Here is my code: library(rms) f1 <- cph(Surv(retime,dfs) ~ age+her2+t_stage+n_stage+er+grade+cytcyt+Cyt_PCDK2 , data=data11,