similar to: print and read.table commands

Hello everyone, I have a data frame in which I am wanting to eliminate the row labels and then relabel the rows with g1-g2000.I have used the following code: dat<-read.table(file="C:\\Documents and Settings\\Owner\\My Documents\\colon cancer1.txt",header=T,row.names=1) file.show(file="C:\\Documents and Settings\\Owner\\My Documents\\colon cancer1.txt") I thought that this

Hello everyone, I have two problems which I am unable to solve : 1.I am trying to add the  row labels (g1-g2000) to the very left of a data table. The data table is 2000 rows  by 62 columns.I have used the following code. read.table(file="C:\\Documents and Settings\\Owner\\My Documents\\colon cancer1.txt",header=T,row.names=1) rowname(dat) <- paste("g", c(1:nrow(dat)),

Dear fellow R-help members, I hope to seek your advice on how to parse/manage a dataset with hundreds of columns. Two examples of these columns, 'cancer.problems', and 'neuro.problems' are depicted below. Essentially, I need to parse this into a useful dataset, and unfortunately, I am not familiar with perl or any such language. data <- data.frame(id=c(1:10))

dear all, I am a student in cs college. I would like to know how to plot infinte number of genes after using the svm. the data set i have consists of x which is a matrix of 39 cancer patients [rows] and 2000 gene names [colmns]. each cell is the value of the gene for a particular patient. there are two types of cancer people representedas factor y. here is the code: library(e1071) #load

Hello to everyone, I have gotten my file to print to screen but when I use read.table I am getting an error message that says there are" more columns than column names."This is a file that was not created by me so I am not sure how to investigate and solve this problem.I looked in the help file and it suggested an auxilliary function called count.fieldsThe code that was used was:

> On Apr 16, 2018, at 3:20 PM, David Winsemius <dwinsemius at comcast.net> wrote: > >> >> On Apr 16, 2018, at 2:58 PM, Therneau, Terry M., Ph.D. via R-devel <r-devel at r-project.org> wrote: >> >> A user asked me about this and I can't figure it out. >> >> tmt% R >> R Under development (unstable) (2018-04-09 r74565) --

Dear R team, dear Prof. Therneau, library(survival) data(colon) ?colon gives me only a very rudimentary source (only a name). Is there a possibility to get a reference to the clinical trial these data are taken from? Many thanks in advance. With best wishes, Matthias Gondan --

I am using pyramid.plot() from the plotrix package. I have something like this ############################################ xy.pop<-dados$masfr xx.pop<-dados$femfr #agelabels<-dados$femlab xycol<-color.gradient(c(0,0,0.5,1),c(0,0,0.5,1),c(1,1,0.5,1),11) xxcol<-color.gradient(c(1,1,0.5,1),c(0.5,0.5,0.5,1),c(0.5,0.5,0.5,1),11) xylab<-dados$maslab xxlab<-dados$femlab

Hi Robert, Thank you for your reply. An attempt to solve this via a regular expression query is particularly helpful. Unfortunately, I don't have much time to play around with this just now. Ultimately though, I think I would like to implement a solution something along the lines of what you have done. I have a book on regular expressions that I am now starting to read. In the meantime, the

Dear R-help list, Apologies. I am trying to convert one table to another. It feels that it should be a very straightforward answer with a single (or two) commands with the right extensions, but I really can't figure this out right now. I have several hundred pheno factors actually, so manually doing this line by line is not an option. My original table is approximately like this : ID

Hello everyone, I have a question as to what code should be used if one wanted to subset from a dataframe of 7000rows by 38 columns.For example if you wanted to generate a array of 100 by 38 would you not use the following: Z<-(dat,dim=c(100,38)) where dat is the dataframe of 7000by 38 Whenever I do this and type show(Z) I get a output of 100 by 38 they all say "integer,7000" as

Hi Paul, Sounds like you have your answer, but for fun I thought I'd try solving your problem using only a regular expression query and base R. I believe this works: > txt <- "Patient had stage IV breast cancer. Nothing matches this sentence. Metastatic and breast match this sentence. French bike champion takes stage IV victory in Tour de France." > pattern <-

Hello List, While translating documents in markdown, I've noticed that it is often necessary to continue table cell text on the following line, especially when limited to a narrow column, and especially in table headers. Unfortunately, this is impossible with the existing table syntax, which interprets each new line as a new table row. I see that David Wheeler proposed a syntax for a text

> Hi, > I recently downloaded R on window and running Rgui on NT. I have never use > R before and trying to learn R by following An introduction to R. > I generated a table of 900x5 in excel and saved as tab delimited txt file. > I then do read.table but I keeping getting the following message > > data <- read.table("ML4mm25.txt", header=T, sep=" ")

Hello everyone, I have a plot and I am wanting to label points as 1 through 20 I have the following code for the plot: dat<-read.table(file="C:\\Documents and Settings\\Owner\\My Documents\\colon cancer1.txt",header=T,row.names=1) file.show(file="C:\\Documents and Settings\\Owner\\My Documents\\colon cancer1.txt")

Dear Rgurus, Interaction terms in the linear models function lm are specified by the colon : eg: x ~ a + b + a:b a shortcut for the above is: x ~ a*b the output if calling anova on the lm object will be the same in both cases a .... b .... a:b ... Resdiuals ... What I am wondering is how the interaction term (a:b) given above should be written in a table in an manuscript? a ) a*b b )

A user asked me about this and I can't figure it out. tmt% R R Under development (unstable) (2018-04-09 r74565) -- "Unsuffered Consequences" Copyright (C) 2018 The R Foundation for Statistical Computing Platform: x86_64-pc-linux-gnu (64-bit) > library(survival) > data(cgd0) Warning message: In data(cgd0) : data set ?cgd0? not found ---- The data set is present and can be

Hi, I am new to R. I have a matrix that I have assigned to the object ?colon?. > colon<-read.table("c:\\alon.txt",header=T,row.names=1) attach(colon) names(colon) The dimenstions are 2000 62. Each of the 62 columns (titled norm1, norm2, norm3, etc) has 2000 different numbers (?continuous? values) within it. I have also assigned a name for each of the 2000 rows of the

Dear R users, I tried to fit a cox proportional hazard model to get estimation of stratified survival probability. my R code is as follows: cph(Surv(time.sur, status.sur)~ strat(colon[,13])+colon[,18] +colon[,20]+colon[,9], surv=TRUE) Error in if (!length(fname) || !any(fname == zname)) { : missing value where TRUE/FALSE needed Here colon[,13] is the one that I want to stratify and the

I am given a text file of records to be converted into a table format. I have searched related topics or packages, but can't find any similar cases. Please help. Sample record is given below. Take note the last element doesn't have a semi colon. ###---------Start of record---------------------- Name : John Height: 170cm Weight : 70kg Age: 30 Status: Married Children: 2 Employment