similar to: optim error

Displaying 20 results from an estimated 3000 matches similar to: "optim error"

2008 Jun 01
2
optim error - repost
Here is a clean version. I did this with nls and it works (see below), but I need to do it with optim. Keun-Hyung # optim vol<-rep(c(0.03, 0.5, 2, 4, 8, 16, 32), 3) time<-rep(c(2,4,8),each=7) p.mated<-c(0.47, 0.48, 0.43, 0.43, 0.26, 0.23, NA, 0.68, 0.62, 0.64, 0.58, 0.53, 0.47, 0.24, 0.8, 0.79, 0.71, 0.56, 0.74, 0.8, 0.47) eury<-data.frame(vol=vol, time=time, p.mated=p.mated)
2012 Jul 30
2
distance matrix and hclustering
Dear R Users,i am very new to R. I want your help on an issue regarding distance matrix and cluster analysis i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values > dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21, 0.21, 0.21, 0.2, 0.19, 0.19, 0.19, 0.19, 0.18, 0.18, 0.18, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17, 0.17,
2013 May 15
1
x and y lengths differ
I have a problem with R. I try to compute the confidence interval for my df. When I want to create the plot I have this problem: Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ. I try this code: library(dplR) df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL) write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)
2010 Mar 31
1
Weird R behaviour?
Dear list, I have observed a weird behaviour from R --- apologies if I am missing something obvious! df3f826f28 df3f826f28 Say you type in R: >c.preec <- 10074 >c.gd <- 2200 >p1 <- .2 >c.neo <- p1*9451 + (1-p1)*3883 >n.preec <- 3710 >n.gd <- 2650 >n.neo <- 2120 >n.pcos <- 53000 >unit.met <- 94 >cost.met <- 94*n.pcos >effect <-
2008 Dec 06
1
Morlet wavelet not supportd by wavCWTPeaks
aa <- (structure(list(X.0.85 = c(-1.02, -1.17, -1.29, -1.39, -1.46, -1.5, -1.52, -1.5, -1.46, -1.39, -1.3, -1.19, -1.07, -0.93, -0.79, -0.65, -0.5, -0.36, -0.22, -0.08, 0.05, 0.18, 0.3, 0.41, 0.52, 0.62, 0.72, 0.81, 0.89, 0.98, 1.05, 1.13, 1.19, 1.25, 1.29, 1.31, 1.31, 1.29, 1.24, 1.16, 1.06, 0.93, 0.77, 0.58, 0.38, 0.16, -0.07, -0.31, -0.89, -1.05, -1.19, -1.31, -1.41, -1.47, -1.51, -1.51,
2013 May 23
1
sample(c(0, 1)...) vs. rbinom
Greetings.? My wife is teaching an introductory stat class at UC Davis.? The class emphasizes the use of simulations, rather than mathematics, to get insight into statistics, and R is the mandated tool.?? A student in the class recently inquired about different approaches to sampling from a binomial distribution.? I've appended some code that exhibits the idea, the gist of which is that using
2008 Apr 09
1
simple intro to cluster analysis using R
I am looking for simple introduction to cluster analysis using R, that would be understandable to a novice in statistics. Or, could someone perhaps help me understand how to proceed in my analysis? I am very new to both statistics and R, but am trying hard to avoid having to use SPSS as everyone around me... I have dataset on people presenting their opinions on different religious
2011 Jan 21
4
clustering fuzzy
hello, i'm pete ,how can i order rows of matrix by max to min value? I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K are clusters. I need first and second largest elements of the i-th row. for example 1 0.66 0.04 0.01 0.30 2 0.02 0.89 0.09 0.00 3 0.06 0.92 0.01 0.01 4 0.07 0.71 0.21 0.01 5 0.10 0.85 0.04 0.01 6 0.91 0.04 0.02 0.02 7 0.00 0.01 0.98 0.00 8 0.02
2012 Jul 02
1
How to get prediction for a variable in WinBUGS?
Dear all,I am a new user of WinBUGS and need your help. After running the following code, I got parameters of beta0 through beta4 (stats, density), but I don't know how to get the prediction of the last value of h, the variable I set to NA and want to model it using the following code.Does anyone can given me a hint? Any advice would be greatly appreciated.Best
2010 Feb 17
2
extract the data that match
Hi r-users,   I would like to extract the data that match.  Attached is my data: I'm interested in matchind the value in column 'intg' with value in column 'rand_no' > cbind(z=z,intg=dd,rand_no = rr)             z  intg rand_no    [1,]  0.00 0.000   0.001    [2,]  0.01 0.000   0.002    [3,]  0.02 0.000   0.002    [4,]  0.03 0.000   0.003    [5,]  0.04 0.000   0.003    [6,] 
2010 Aug 16
1
need of elegant data manipulation
Dear R users, I seek for a more elegant manner to manipulate my data that that I produced so far. Data is in a data frame THC515.DATA -sample at the end of this mail- of 5 variables, a string and 4 continuous numeric variables. I need to get the mean of two variables "Q" and "T" at the levels of a third one "dP", individually for each level of "n". I
2012 Mar 04
2
How do I create a scatterplot with two explanatory variables?
Hi there, I'm trying to make a scatterplot of removed versus duration for each type of bee. No matter what I try, I can't seem to get my code to work. Any help would be appreciated. Thanks! My r-code: dat$BEE <- with(dat, factor(BEE, c(1,2))) plot(REMOVED~DURATION,pch=BEE, col=BEE) REMOVED DURATION BEE 1 0.07 2 QUEEN 2 0.10 5 QUEEN 3 0.11 7 QUEEN 4 0.12 11 QUEEN 5 0.15 12 QUEEN 6 0.19
2008 Jun 05
1
choosing an appropriate linear model
I am trying to model the observed leaching of wood preservative chemicals from treated wood during an outdoor experiment where leaching is caused by rainfall events. For each rainfall event, the amount of rainfall was recorded as well as the amount of preservative chemical leached. A number of climatic variables were measured, but the most important is the amount of rainfall. I have tried a
2007 Mar 05
4
Identifying last record in individual growth data over different time intervalls
Hi I have a plist t which contains size measurements of individual plants, identified by the field "plate". It contains, among other, a field "year" indicating the year in which the individual was measured and the "height". The number of measurements range from 1 to 4 measurements in different years. My problem is that I would need the LAST measurement. I only
2006 Sep 28
1
help on plots
Dear friends, I met a problem on plotting. My dataset is : year MHBC LHBC MHRC LURC 1993 11.75 4.50 0.43 0.46 1994 7.25 1.25 0.35 0.51 1995 8.67 2.17 0.54 0.44 1996 2.67 1.33 0.78 0.47 1997 3.42 4.92 0.69 0.48 1998 1.92 3.08 0.72 0.54 1999 2.33 2.58 0.74 0.41 2000 5.75 4.50 0.45 0.50 2001 3.75 4.42 0.52 0.47 2002 2.33
2012 Sep 28
2
Converting array to matrix
Hi, I have a 3d array as below, I want to make this array to a matrix of p=50(rows) and n=20(columns) with the coverage values . The code before the array is: library(binom) Loading required package: lattice pi.seq<-seq(from = 0.01, to = 0.5, by = 0.01) no.seq<-seq(from = 5, to = 100, by = 5) cp.all = binom.coverage( p = pi.seq, n = no.seq , conf.level = 0.95, method = "exact")
2007 Nov 06
1
How to find the zero (only the real solution) with the package polynom ?
Hello, I have 3 columns : a, b and a*b I would like to find the pair (a,b) so that a*b is the minimum but not from the points I measured but from the fit of the curve (I have more points that the ones given below but I fit only on this part because I know that the minimum a*b is in this interval). I thought doing it this way : - to fit a*b=f(a) abfit<-lm(ab ~ poly(a,8,raw=T)) - to use the
2010 Jun 04
1
How do I 'merge' a altered subset of a data.frame back into the same data.frame
Hi Step 1: I create a data.frame called iolm. Step 2: I create a conditional subset i_wtr. Step 3: In this subset I add 0.3 to all values in the IOLM_AST column. Step 4: Now I am looking for the best way to Œmerge¹ the altered subset back into the original iolm data.frame ## STEP 1 >iolm ID IOLM_AST IOLM_AXIS 1 1 1.15 165.33 2 2 1.20 79.00 3 3 0.40
2009 Mar 08
2
plot confidence limits of a regression line - problem
hi, I don't know what I am doing wrong, but with that code; x1 <- c(1.60, 0.27, 0.17, 1.63, 1.37, 2.00, 0.90, 1.07, 0.89, 0.43, 0.37, 0.59, 0.47, 1.83, 1.79, 0.90, 0.72, 1.83, 0.23, 1.97, 2.03, 2.19, 2.03, 0.86) x2 <- c(1.30, 0.24, 0.20, 0.50, 1.33, 1.87, 1.30, 0.75, 1.07, 0.43, 0.37, 0.87, 1.40, 1.37, 1.63, 0.80, 0.57, 1.60, 0.39, 2.03, 1.90, 2.07, 1.93, 0.93) model <-
2007 Nov 07
3
Can I replace NA by 0 (if yes, how) ?
Hello, I'm trying to fit some points with a 8-degrees polynom (result of lm is stored in pfit). In most of the case, it is ok but for some others, some coefficients are "NA". I don't really understand the meaning of these "NA". And the problem is that I can't perform a derivation (pderiv<-as.function((deriv(polynomial(pfit$coefficients))))) on pfit due to the