similar to: Constructing dummy variables for months for a time series object

Dear R users I would like to do some spreadsheet style expansion of dates. For example, I would need to obtain a vector of months. I approached in an obviously wrong way: > paste(01:12) [1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" > as.Date(paste(01:12),

Hello everyone, I have a dataset with 3 colums (Year, Month, MeanTemp). Now I would like to calculate the average of the mean temperature for the summer months (Juli, August, September) for each of the 20 years. I'm sure it's somehow possible with a loop, but all I tried so far didn't worked and by the time I spent looking for a solution I would have even be faster doing this in

A user asked me about this and I can't figure it out. tmt% R R Under development (unstable) (2018-04-09 r74565) -- "Unsuffered Consequences" Copyright (C) 2018 The R Foundation for Statistical Computing Platform: x86_64-pc-linux-gnu (64-bit) > library(survival) > data(cgd0) Warning message: In data(cgd0) : data set ?cgd0? not found ---- The data set is present and can be

Hi all, I am just curious how to sort the groups in a categorical box plot chart bwplot here is the example: d<-data.frame(sample(rep(month.abb,20), 100), runif(100,1,10)); colnames(d) <- c("Month", "Value"); bwplot(d$Month ~ d$Value); as you can see Months are not sorted alphabetically. Does anybody know ho to sort those on the chart level? Thank you Jan

I am sorry, I'd like to split my column ("names") such that all the beginning of a string ("X..") is gone and only the rest of the text is left. x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd")) x$names<-as.character(x$names) (x) str(x) Can't figure out how to apply strsplit in this situation - without using a

I think I'm missing something tonight in the usage of 'legend': plot(0, type="n") legend(locator(1), month.abb[1:5], pch=15, col=1:5) gives me something similar to what I want. But legend(locator(1), month.abb[1:5], fill=T, col=1:5) gives me 5 black boxes. What am I doing wrong? Thank you, > version _ platform i686-pc-linux-gnu arch i686 os

Hello, Everyone. Does anyone know how to create a Nightingale’s Rose chart by using R? Hopefully, the graph could be displayed like this: http://mbostock.github.com/protovis/ex/crimea-rose.html Thanks a lot. Kind regards, Henry [[alternative HTML version deleted]]

Dear all, I am running R : Copyright 2005, The R Foundation for Statistical Computing Version 2.1.1 (2005-06-20), ISBN 3-900051-07-0 Under Mac os X, a french version! I am preparing a package and I got the following issue I am trying to read dates that are written in english and have them recognized by R using as.Date function. I realized strangely that when I type > month.abb [1]

Hello! I'm using a CompactFlash as storage device. Since those CF cards only have limited write cycles (CF does wear-levelling by itself, but you don't want to write too many timet so the card) i was wondering by what a factor the journaling of ext3 increases the write accesses to the CompactFlash compared to ext2. Thanks a lot already for your help! Sincerely Chris Braun

Hello: I have a dataframe, where the first column in a month: Month CATCHMENT_ med min max 1 Apr Alknda01 71.68080 11.9406600 196.2753 2 Apr Alknda02 69.44580 12.1065600 196.2753 3 Apr ArialKhan 39.89310 5.8598700 175.4433 4 Apr Arjun01 4.79652 0.0093336 55.7136 5 Apr Arjun02 4.79652 0.0093336 55.7136 6 Apr Arun01 52.42320 0.1571928

Hi Simon, thank you for the concise reply. Do you mean the reported behavior of drop() is not a bug? It looks like a borderline bug to me (see below), but I'm not the judge of that. If this is the intended behavior and serves an actual purpose, then that could be explicitly documented in a \note{} on the help page. Such a note would slightly reduce the surprise of users running into this

I have noticed a significant performance degradation using merge in 2.9.1 relative to 2.8.1. Here is what I observed: N <- 100000 X <- data.frame(group=rep(12:1, each=N), mon=rep(rev(month.abb), each=N)) X$mon <- as.character(X$mon) Y <- data.frame(mon=month.abb, letter=letters[1:12]) Y$mon <- as.character(Y$mon) Z <- cbind(Y, group=1:12) system.time(Out

Hello John, Thank you very much for your fast response and the patch. Is it possible to add Fabian Scheler and Florian Franzmann to the people section as proposed in the attached patch? I hope to manage to write a description for the 'ProjectsWithLLVM' page this week and send it to the list. Thanks again, Tobias Am 26.09.2013 21:26, schrieb John Criswell: > Dear Tobias, > >

Dear all, I am running R : Copyright 2005, The R Foundation for Statistical Computing Version 2.1.1 (2005-06-20), ISBN 3-900051-07-0 Under Mac os X, a french version! I am preparing a package and I got the following issue I am trying to read dates that are written in english and have them recognized by R using as.Date function. I realized strangely that when I type > month.abb [1]

Dear R users, As per my attached script I am ploting monthly mean data which has missing months. But in the plot missing months are not shown (plot attached). Kindly help how to show complete plot (Jan-Dec) with missing months. Regards, Yogesh -------------- next part -------------- An embedded and charset-unspecified text was scrubbed... Name: script.txt URL:

Dear R-help, I am looking for ideas and presentations of new and advanced data visualization methods. As an example of what I am searching for, the 'Many Eyes' pages at http://manyeyes.alphaworks.ibm.com/manyeyes/ may provide a good paradigm. I would be interested even if it will not be easy to implement such examples in R, e.g. because of the interactive nature of these graphical

Given a data frame with a continuous variable and a factor. I would like to generate a histogram of the continuous variable, where each bar is filled with different colors according to the percentage of factor values falling into this region of the continuous variable. I looked into packages like 'lattice' and 'ggplot2'. Searching R-help revealed that 'histogram' is

Hey, As announced earlier, here comes our project description. It would be great if you could add it to llvm.org! Tobias -- The Real-Time Systems Compiler (RTSC) The Real-Time Systems Compiler (RTSC) is an operating-system–aware compiler that allows for a generic manipulation of the real-time system architecture of a given real-time application. Currently its most interesting application is

Hi, I have a data matrix with 13 columns and 55 rows. First coulmn is year and other are monthly values for 55 years. Now i want to create a single column of all the values ( i e a single time series column from column 2 to 13 ). Is it the for loop that works here ...how ? or how i can rearrange the data so that it becomes a times series column. hope i made the question clear . thank you,

I'm a relative R novice, and sometimes the simple things trip me up. Suppose I have a <- c("apple", "pear") and I want a logical vector of whether each of these strings contains "ear" (in this case, F T). What is the idiom? Quizzically, Mark Lindeman