similar to: peak finding

I have a big contingency table, approximately of size 60*2*500*500, and I need to count the number of cells containing a count of 1 for each of the factors values defining the first dimension. Here is my attempt: tab1<-with(pisa1,table(CNT,GENDER,ISCOF,ISCOM)) tab2<-apply(tab1,1:4,function(x)ifelse(sum(x)==1,1,0)) tab3<-apply(tab2,1,sum) Computing tab2 is very slow. Is there a faster

Hi R, I wanted to know how do we access the elements of a list. In particular, v=list(c(1,2,3,4,5),c(1,2,33,4,5),c(1,2,333,4,5),c(1,2,3333,4,5)) I want to access all the thirds items of the elements of the list. i.e., I want to access the elements, 3,33,333,3333. This can be done through sapply as: sapply(v,function(x) x[3]) But I need to access this without using

While termplot is under discussion, here's another proposal. I'd like to change the default for partial.resid to TRUE, and for smooth to panel.smooth. I'd be surprised if those changes were to break existing code. John Maindonald email: john.maindonald at anu.edu.au phone : +61 2 (6125)3473 fax : +61 2(6125)5549 Centre for Mathematics & Its Applications, Room

I am converting some matlab code into R that use inverse of the complementary error function, erfcinv and did not find an equivalent in R, is there such a function in some contributed modules? Thanks.

I have a set data={A,B,C,D,E,F,G} I want to choose 2 letter from 8 letters, i.e. generate the combination set for choose 2 letters from 8 letters. I want to get the liking: combination set={AB,AC,AD,....} Does anyone konw how to do in R. thanks, Aimin

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Does anyone have, or has anyone ever considered making, a version of 'termplot' that allows the user to specify that all plots should have the same y-limits? This seems a natural thing to ask for, as the plots share a y-scale. If you don't have the same y-axes you can easily misread the comparative contributions of the different components. Notes: the current version of termplot

Does anyone have, or has anyone ever considered making, a version of 'termplot' that allows the user to specify that all plots should have the same y-limits? This seems a natural thing to ask for, as the plots share a y-scale. If you don't have the same y-axes you can easily misread the comparative contributions of the different components. Notes: the current version of termplot

Hi, I can not comprehend the linear fitting results of polynoms. For example, given the following data (representing y = x^2): > x <- 1:3 > y <- c(1, 4, 9) performing a linear fit > f <- lm(y ~ poly(x, 2)) gives weird coefficients: > coefficients(f) (Intercept) poly(x, 2)1 poly(x, 2)2 4.6666667 5.6568542 0.8164966 However the fitted() result makes sense: >

Hi all, I used the function 'glm' to perform logistic regression, and then use 'summary' to display the fitting result. There are 'z value' and 'Pr(>|z|)' Do they simpily represent the result of 'z test' ? as I perform the 'z test' for a particular variable following the definition, it yields a different result. Stephen Lau

Hi there, Am try to find tree diameter increment in a hierarchical data with tree diameter measurements, date of measurements, in plots that are located in different region. How do I do it? am very new to R. Thanks for you help. Maina Kariuki Level 3, 8 Nicholson Street East Melbourne VIC 3002 Ph: (03) 9637 9809 Email: maina.kariuki@dse.vic.gov.au Notice: This email and any

Hi, For example, natural_nums <- 1:10 even_nums <- seq(2,10, by = 2) types <- c("natural_nums", "even_nums") What functions can be performed on types[1] to turn it into a variable name and not a string ? [[alternative HTML version deleted]]

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Hi, I need to compute an array from a matrix and an array: A <- array(1:20,c(2,2,5)) B <- matrix(1:10,5) And I would like the result to be an array consisting of the following: rbind(A[1,,1]*B[1,], A[2,,1]*B[1,]) rbind(A[1,,2]*B[2,], A[2,,2]*B[2,]) rbind(A[1,,3]*B[2,], A[2,,3]*B[2,]) etc. Hence the result should have the same dimension as A, ie a series of 2 by 2 matrices. Short of

Hi, My example is as the following, W<-matrix(c(2,4,2,8,1,3),ncol=3) which(W==min(W)) I would like to find the index for min of the matrix W, i.e. (1, 3) instead of 5 as the output. What command could I use? Thanks, Kate [[alternative HTML version deleted]]

Hi, I am trying to find a solution in R for the following C++ code that allows one to skip ahead in the loop: for (x = 0; x <= 13; x++){ x=12; cout << "Hello World"; } Note that "Hello World" was printed only twice using this C++ loop. I tried to do the same in R: for(i in 1:13){ i=12 print("Hello World") } It doesn't work as I expected, i.e.,

Dear R user group, I am working with boxplots and cannot solve the following problem: > data<-c(0,15,0,60,0,0,0,0,0,60,60,0,60,0,30,0) > data [1] 0 15 0 60 0 0 0 0 0 60 60 0 60 0 30 0 > boxplot(data) The boxplot has the first hinge and the mean-bar both at 0... Why is this the mean is clearly >0! Thanking you and wishing you an excellent day, Georg.

hi, is there a way to compile r script , so that it can be run without the R platform, both on unix and windows something to create exe file. thnx -- View this message in context: http://www.nabble.com/R-to-exe-tp17291121p17291121.html Sent from the R help mailing list archive at Nabble.com.

Hi, I have a matrix a = matrix (1:16, 4, 4) b = c (2,3) I want to find out which rows of a, where a[,1] equals any values of b? I know that if b is only one value, e.g, b=2, then what I want is a[a[,1] == 2,] But what about if it is not one value but a vector of values? Thanks much in advance. -- Waverley @ Palo Alto

Could someone help me on the following: SAS has DUD (Does not Use Derivatives) for nonlinear regression. Does "R" has a similar capability? I am not good at derivatives and may get my derivative wrong before feeding it to a nonlinear regression procedure. Any help would be much appreciated. Liu Hancock Forest Management NZ Tokoroa, New Zealand DDI: 07-8850387 Mobile: 021-1576178