similar to: How to assign multiple return values

Displaying 20 results from an estimated 2000 matches similar to: "How to assign multiple return values"

2008 Apr 07
5
How to pack my stuff into a package (library, collection)?
Hello, I am new useR, I have written some functions, which I currently use by "source"-ing them from the files. That's OK, but when I my functions start counting in the tens and hundreds I'd be glad to be able to type "help.search("my_obscure_fun")" and get a sensible reply. I also want to be able to load them as a package at startup and not have to
2008 Mar 22
2
More elegant multiplication or division of a data frame with a vector
Hello, I am importing some raw voltage multichannel measurements into an R data frame. I need to scale each column with the respective sensitivity for that channel. I figured how to do it, but I am curious if there isn't a more elegant way. Now I start with something like this: rawdata <- data.frame(rbind(c(1,2,3), c(4,5,6))) sens <- c(2,4,6) and I do this: data <-
2008 Mar 25
1
Combining several mappings in ggplot2
Hello, I want to be able to make a plot that has several series with different color and linetype. Online documentation suggest that this is possible, but I haven't found how: "We can also create redundant mappings, mapping the same variable to multiple aesthetics. This is most useful when producing a graphic for both colour and black and white display." Here's what I have to
2008 Feb 07
1
How to split a factor (unique identifier) into several others?
Hello, I have a data frame with a factor column, which uniquely identifies the observations in the data frame and it looks like this: sample1_condition1_place1 sample2_condition1_place1 sample3_condition1_place1 . . . sample3_condition3_place3 I want to turn it into three separate factor columns "sample", "condition" and "place". This is what I did so far: #
2008 Feb 25
1
Plotting series marked with a symbol on every nth data point, preferably in ggplot...
Hello! I am working with signals and a plot of several signals on the same axes can get quite messy. With lines that are very fractured, distinction by only the linestyle is not very clear. If I add symbols to the plot however, there are so many symbols, that they overplot and the whole plot is unreadable once again. I am looking for advice on how to make a plot with continuous lines and symbols
2008 Feb 07
1
Bode plots in ggplot2
Hello, I am trying to figure out how to make a bode plot (a.k.a. bode diagram) in ggplot2. An example of such a diagram can be found here: http://meweb.ecn.purdue.edu/~me475/ctm/freq/bode2.GIF The example above shows the gain and phase characteristic of a linear system. In my case, I would like to compare visually several systems on the same diagram. The data in the data frame is arranged
2008 Mar 26
2
Moving data between R and Matlab back and forth?
Hi to the list, I am trying to find a way to painlessly move structured data back and forth between R and Matlab (also Octave). For this purpose I found the R.matlab package great help. I wish to use a Matlab -v6 MAT file as an intermediary format, because it is well read by both Matlab and Octave. It is also well read by 'readMat' function in R.matlab package, but that is where I run
2008 Mar 13
3
Splitting a set of vectors in a list
I have a set of character vectors of uneven length that I have stored in a list. I can easily enough get any column of them using lapply but what I want is to be able to create a matrix of them. Other than some kind of brute force looping approach I have drawn a blank. Would somebody please suggest something? Thanks Example. mylist <- list(aa=c("cat","peach" ),
2004 Feb 11
6
lapply and dynamically linked functions
Hi all, I'm trying to use lapply on a list with the following command: out<-lapply(mylist,myfun,par1=p,par2=d) (1) where myfun<-function(x,par1,par1) {.....} (2) now this function is in fact a wrapper for some Fortran code I have written so I think this might be the problem. When I call lapply() as in (1) I get the following message: Error in get(x,
2012 Jul 02
2
Constructing a list using a function...
Hi All I have a dataframe: myframe<-data.frame(ID=c("first","second"),x=c(1,2),y=c(3,4)) And I have a function myfun: myfun<-function(x,y) x+y I would like to write a function myfun2 that takes myframe and myfun as parameters and returns a list as below: mylist $first [1] 4 $second [2] 6 Could you please help me with this? Doesn't seem like the
2008 Mar 27
2
Rule for accessing attributes?
Hi ! I am a new user and quite confused by R-indexing. Make a list and get the attributes lst <- list(x = 1:3, y = 4:6, z = 7:9) attributes(lst) This returns: $names [1] "x" "y" "z" I can easily do: nm <-names(lst) or nm <-attr(lst,"names") which both return the assigned names of the named list 'lst', but why then this doesn't
2006 Mar 30
3
access list component names with lapply
I have a question regarding accessing the names of list components when applying a function with lapply. Here is an example that demonstrates what I'd like to do. I have a list like this one: mylist <- list(a=letters[1:10], b=letters[10:1], c=letters[1:3]) Now I would like to append the names of the list components to their corresponding vectors with the c() function. I thought this
2009 Jan 12
2
assign a list using expression?
Dear R-users, I would like to assign elements to a list in the following manner: mylist <- list(a = a, b = b, c = c) To do this I tried myexpr <- expression(a = a, b = b, c = c) mylist <- list( eval(myexpr) ) It ends up by overwriting a when b is assigned and b when c is assigned. Additionally the element of the list does not have a name. Could you tell me why this is the case? Thank
2015 May 04
2
Define replacement functions
Hello I tried to define replacement functions for the class "mylist". When I test them in an active R session, they work -- however, when I put them into a package, they don't. Why and how to fix? make_my_list <- function( x, y ) { return(structure(list(x, y, class="mylist"))) } mylist <- make_my_list(1:4, letters[3:7]) mylist mylist[['x']] <- 4:6
2019 Mar 26
0
Discrepancy between is.list() and is(x, "list")
Hi Abs, Lets try to remain civil even when disagreeing about major design philosophies, ok? On Tue, Mar 26, 2019 at 2:08 PM Abs Spurdle <spurdle.a at gmail.com> wrote: > If I can merge this thread with the one I started yesterday... > > > "If the object does not have a class attribute, it has an implicit > class..." > > which I take to mean that if an object
2007 Oct 20
1
Getting at what a named object represents in a function...
Hi, I'm pretty new to R. I have an object (say a list) and I I have a function that I call on various columns in that list (excuse terminology if it's wrong/ambiguous). Imagine its like this (actual values are unimportant) and called mylist: >mylist A B 1 5 2 5 3 6 4 8 5 0 I have a function: foo = function(param){ #modify list A or B values depending on
2011 Apr 05
1
Help in splitting a list
Dear R users, Let's say I have a list with components being 'm' matrices (as exemplified in the "mylist" object below). Now, I'd like to subset this list based on an index vector, which will partition each matrix 'm' in 2 sub-matrices. My questions are: 1. Is there an elegant way to have the results shown in mylist2 for an arbitrary number of matrices in mylist?
2009 Oct 25
3
NULL elements in lists ... a nightmare
I can define a list containing NULL elements: > myList <- list("aaa",NULL,TRUE) > names(myList) <- c("first","second","third") > myList $first [1] "aaa" $second NULL $third [1] TRUE > length(myList) [1] 3 However, if I assign NULL to any of the list element then such element is deleted from the list: > myList$second <-
1999 May 09
1
subscripting in list() (PR#187)
Sorry My previous report is not detailed. In R, you will get this: > mylist <- list() > mylist[[1]] Error in mylist[[1]] : subscript out of bounds > mylist[[1]] <- c(1) Error: (list) object cannot be coerced to vector type 14 > mylist[[1]] <- c(1,2) > mylist[[1]] <- c(1) > mylist [[1]] [1] 1 I was trying to assigning c(1) to (mylist[[1]] <- c(1)) -- it seems
2004 May 10
2
Lists and outer() like functionality?
Hi, I'm have a list of integer vectors and I want to perform an outer() like operation on the list. As an example, take the following list: mylist <- list(1:5,3:9,8:12) A simple example of the kind of thing I want to do is to find the sum of the shared numbers between each vector to give a result like: result <- array(c(15,12,0,12,42,17,0,17,50), dim=c(3,3)) Two for() loops is the