Displaying 20 results from an estimated 20000 matches similar to: "list()"
2002 Jul 09
3
Assignment converts variable to factor
Hello,
I would like to know if this behaviour in R is as expected.
I have a data frame 'dat' with column var1 being character (and not
factor). Then I create a new column 'var2' by:
> dat[,"var2"] <- dat$var1;
Column var2 is now a factor.
But if I do:
> dat$var2 <- dat$var1;
Then column var2 is character (and not factor).
I don't want to have
2005 Aug 14
1
complex expression with plotmath
Hello everyone,
I want to define a function that receives the name of two variables
(may include Greek letters and subscripts) and uses them into the
title of a plot.
My best attempt is the following:
myplot <- function(var1, var2) {
v=paste(var1,"==1 & ",var2,"==2");
plot(1:10, main=parse(,,v))
}
But when I call it with something like myplot("Q[i]",
2004 Aug 17
5
Bug in colnames of data.frames?
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
> myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
> myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ]
everything is fine, but if I omit the commas:
> myData$var4 <- myData[ "var1" ] + myData[ "var2" ]
the name
2013 May 03
3
color by group in ggplot
Hey,
I have a dataset like this:
ID Var1 Var2 Group
A1 1 1 BB
A2 1 2 AA
B1 2 1 CC
B2 1 3 DD
C1 1 2 EE
I would like to plot the points of Var1 and Var2, use "ID" as X-axis, but
color the points by "Group". I can
2008 Jul 16
2
Group level frequencies
Dear List,
I have Multi-level Data
i= Indivitual Level
g= Group Level
var1= First Variable of interest
var2= Second Variable of interest
and I want to count the frequency of "var1" and "var2" on the group
level.
I found a way, but there must be a much simpler way.
data.ml <-
data.frame(i=c(1:8),g=as.factor(c(1,1,1,2,2,3,3,3)),var1=c(3,3,3,4,4,4,4
,4),
2011 Jul 05
4
Create a data frame of all possible unique combinations of factors
Hello,
I'm trying to create a data frame where each row has a unique combination of
factors.
I start with a vector of species like so:
> 1> test <- c("A","B","C","D")
>
> 1> test
>
> [1] "A" "B" "C" "D"
>
To get all species combinations I have used expand.grid like this:
2009 Sep 22
3
converting a character vector to a function's input
Hi all, I have been trying to solve this problem and have had no luck so far.
I have numeric vectors VAR1, VAR2, and VAR3 which I am trying to cbind. I also have a character vector "VAR1,VAR2,VAR3". How do I manipulate this character vector such that I can input a transformed version of the character vector into cbind and have it recognize that I'm trying to refer to my numeric
2012 Sep 11
3
Combine two variables
Hi:
I have two variables in a data frame that are the results of a wording experiment in a survey. I'd like to create a third variable that combines the two variables. Recode doesn't seem to work, because it just recodes the first variable into the third, then recodes the second variable into the third, overwriting the first recode. I can do this with a rather elaborate indexing process,
2012 Jun 03
2
merging single column from different dataframe
Hi all,
probably really simple to solve, but having no background in programming I
haven't been able to figure this out: I have two dataframes like
df1 <- data.frame(names1=c('aa','ab', 'ac', 'ad'), var1=c(1,5,7,12))
df2 <- data.frame(names2=c('aa', 'ab', 'ac', 'ad', 'ae'),
var2=c(3,6,9,12,15))
Now I want merge
2014 Aug 21
2
pregunta
Buenas noches Javier y José,
Estoy en contra de usar attach(), asi que propongo la siguiente alternativa
con with():
# paquete
require(epicalc)
# los argumentos en ... pasan de epicalc:::cc
# ver ?cc para mas informacion
foo <- function(var1, var2, var3, ...){
or1 <- cc(var1, var2, ...)
or2 <- cc(var1, var3, ...)
list(or1 = or1, or2 = or2)
}
# datos
x <-
2010 Dec 20
2
Turning a Variable into String
I would like to know how to turn a variable into a string. I have tried
as.symbol and as.name but it doesnt work for what I'd like to do
Essentially, I'd like to feed the function below with two variables. This
works fine in the bit working out number of elements in each variable.
In the print(sprintf("OK with %s and %s\n", var1, var2)) line I would like
var1 and var2 to be
2006 Mar 02
1
CCF and Lag questions
I am new to R and new to time series modeling.
I have a set of variables (var1, var2, var3, var4, var5) for which I have
historical yearly data.
I am trying to use this data to produce a prediction of var1, 3 years into
the future.
I have a few basic questions:
1) I am able to read in my data, and convert it to a time series format
using 'ts.'
data_ts <- ts(data, start = 1988, end =
2012 Jul 01
2
list to dataframe conversion-testing for identical
HI R help,
I was trying to get identical data frame from a list using two methods.
#Suppose my list is:
listdat1<-list(rnorm(10,20),rep(LETTERS[1:2],5),rep(1:5,2))
#Creating dataframe using cbind
dat1<-data.frame(do.call("cbind",listdat1))
colnames(dat1)<-c("Var1","Var2","Var3")
#Second dataframe conversion
2006 Jan 13
2
find mean of a list of timeseries
Can someone please give me a clue how to 're'write this so I dont need
to use loops.
a<-ts(matrix(c(1,1,1,10,10,10,20,20,20),nrow=3),names=c('var1','var2','var3'))
b<-ts(matrix(c(2,2,2,11,11,11,21,21,21),nrow=3),names=c('var1','var2','var3'))
2014 Aug 21
2
pregunta
Estimados
Estoy entrenando hacer funciones que respondan a comandos,
en esta caso en la salida gráfica se observa que dice : Exposure=var3 y
outcome=var 1
quisiéramos que se reflejan los nombres de la base de datos : var1=estado,
var2=cake, var3=chocolate
Espero haberme explicado adecuadamente
Adjunto tabla con datos
####################################
#Comando que llama
2008 May 02
2
Coercing by/tapply to data.frame for more than two indices?
Dear Colleagues,
Apologies for a long email to ask what I feel may be a very simple
question; I figure it's better to overspecify my situation.
I was asked a question, recently, by a colleague in my department
about pre-aggregating variables, i.e., computing the mean of defined subsets
of a data frame. Naturally, I thought of the 'by' and 'tapply' functions, as
2009 Jan 13
3
Comparing elements for equality
Suppose I have a dataframe as follows:
dat <- data.frame(id = c(1,1,2,2,2), var1 = c(10,10,20,20,25), var2 =
c('foo', 'foo', 'foo', 'foobar', 'foo'))
Now, if I were to subset by id, such as:
> subset(dat, id==1)
id var1 var2
1 1 10 foo
2 1 10 foo
I can see that the elements in var1 are exactly the same and the
elements in var2 are exactly
2014 Apr 11
6
crear variable en base a nombre de columnas que tienen un 1
Buenos días.
Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa
que seguro que es muy simple..
Pongo un ejemplo.
var1 <- c(rep(0,3),rep(1,2))
var2 <- c(rep(1,2),0,0,1)
var3 <- c(rep(1,2),rep(0,3))
var4 <- c(rep(1,2),rep(0,3))
datos <- data.frame(fila=1:5,var1, var2, var3, var4)
datos
datos
fila var1 var2 var3 var4
1 1 0 1 1 1
2 2 0
2009 May 20
1
Comparing spatial distributions - permutation test implementation
Hello everyone,
I am looking at the joint spatial distribution of 2 kinds of organisms
(estimated on a grid of points) and want to test for significant
association or dissociation.
My first question is: do you know a nice technique to do that,
considering that I have a limited number of points (36) but that they
are repeated (4 times)? I did GLMs to test for correlations between
the
2014 Apr 11
2
crear variable en base a nombre de columnas que tienen un 1
Carlos, en principio si sería algo así, sólo que en vez de quedarme con
todas las columnas var1 a var4 tuviera sólo 3, ya que en mis datos no
hay ningún caso que tenga el valor 1 en más de 3 variables..
Había llegado a una solución (mucho menos elegante que usando reshape),
que implicaba un for sobre las filas.
Jorge, creo que tu solución me vale.
Muchas gracias a los dos..
Saludos
El