similar to: Combine two columns

I would like to compare two data sets saved as text files (example below) to determine if both sets are identical(or if dat2 is missing information that is included in dat1) and if they are not identical list what information is different between the two sets(ie output "a1", "a3" as the differing information). The overall purpose would be to remove "a1" and

Thank you for the suggestion, Bill. The result is not quite what I would like. Here's sample code for you or anyone else who may be interested: Al1 = c('A','C','C','C') Al2 = c('G','G','G','T') Freq1 = c(0.0078,0.0567,0.9434,0.9908) MAF = c(0.0078,0.0567,0.0566,0.0092) m1 = data.frame(Al1=Al1,

Hello, All! How might one accomplish this using the by() function? m1 is a data frame. # populate column "m1$major_allele" for ( i in 1:length(m1$major_allele)) { if ( m1$Freq1[i] == m1$MAF[i]){ m1$major_allele[i] = m1$Al1[i] } else{ m1$major_allele[i] = m1$Al2[i] } } Jim [[alternative HTML version deleted]]

I am new in R and i am having trouble here. I?ve already searched in the list but hasn?t helped When i run this script above i get the message "Error in gen[j, i] : incorrect number of dimensions". However gen is 1000x200 (ind x loc) and so is g could anybody help me for (i in 1 : loc) { #loc=200 for (j in 1 : ind) { #ind=1000 g1 <= function ( gen ) matrix ( if (gen[j, i]

Hey, I have a dataset and I want to identify the records by groups for further use in ggplot. Here is a sample data: ID Value AL1 1 AL2 2 CA1 3 CA4 4 I want to identify all the records that in the same state (AL1 AND A2), group them as "AL", and do the same for CA1 and CA4. How can I have an output like: ID Value State AL1 1 AL AL2 2 AL CA1 3 CA CA4 4

Hello All, I have a toy dataframe like this. It has 8 columns separated by tab. Name SampleID Al1 Al2 X Y R Th rs191191 A1 A B 0.999 0.09 0.78 0.090 abc928291 A1 B J 0.3838 0.3839 0.028 0.888 abcnab A1 H K 0.3939 0.939 0.3939 0.77 rx82922 B1 J K 0.3838 0.393

I want to shade the area under the curve of the standard normal density. Specifically color to the left of -2 and on. How might i go about doing this? Thanks -- View this message in context: http://n4.nabble.com/Shade-area-under-curve-tp1586439p1586439.html Sent from the R help mailing list archive at Nabble.com.

Greetings: I would like comments on this example and after fixing it up, I need help from someone who has access to insert this in R's help page for plotmath. I uploaded a drawing http://pj.freefaculty.org/R/Normal-2009.pdf that is created by the following code http://pj.freefaculty.org/R/Normal1_2009_plotmathExample.R This will be a good addition to the plotmath help page/example.

Hi John, Thank-you very much for replying, - in answer to your questions: *"As I understand what you wrote, all factors but linelabel are crossed, with linelabel nested within all the other factors?" That's exactly it, *" What is in the highest order cells? Single observations, or multiple scores?" I would say "single observations" - but i have to

Hi R sages, Here is my latest problem. Consider the following toy example: x <- read.table(textConnection("y1 y2 y3 x1 x2 indv.1 bagels donuts bagels 4 6 indv.2 donuts donuts donuts 5 1 indv.3 donuts donuts donuts 1 10 indv.4 donuts donuts donuts 10 9 indv.5 bagels donuts bagels 0 2 indv.6 bagels donuts bagels 2 9 indv.7 bagels donuts bagels 8 5 indv.8 bagels donuts bagels 4 1 indv.9

Hello all, I am trying to write a program in R in which I call a function multiple times within a loop. The problem is that sometimes the function breaks down while calling another function, and produces an error message that breaks my loop and the program stops. I would like to keep the loop running when this function breaks down, and just move on to the next iteration in the loop. Is there

Hi, I was hoping someone could help me with the following problem. Consider this toy example. For the input dataset there are four individuals (rows "indv.1" through "indv.4"), measured for two different variables (columns "var.1" and "var.2") at two different levels of a factor (column "factor.level"). I want to calculate a matrix that has the

Hi I have the followed code for which I am writing a loop pass. int main() { int i = 0; for (i=0; i<20; i++) { printf ("hello world %d\n", i); } return 0; } In the function runOnLoop, I have the following instruction PHINode *indv = NULL; indv = L->getCanonicalInductionVariable(); However, when I check indv is always set to NULL. Since the code has a canonical

Hello again, How do I split a data frame into smaller, completely separate data frames (rather than separate data frames comprising a single "list")? Consider the following data, and my coding attempt: x <- read.table(textConnection("id type number indv.1 bagel 6 indv.2 bagel 1 indv.3 donuts 10 indv.4 donuts 9"), header = TRUE) closeAllConnections() x.split <-

Good Mourning, I have a function to generate a matrix as I show part of it; g[j,i]<-if (gen[j,i]==0) al1[i,1]+al1[i,1] else ... However i would like that this function occurred with a probability P and that another function (another formula to generate g matrix) with probability P-1 That?s it, if P is .7, i would like that in 70% of the times (for random i and j) the matrix g was generated

Hi all, I have a very simple problem that I cannot seem to find the answer to. Consider the following toy dataset: x <- read.table(textConnection("V1 apples bananas cherries indv.1 7 8 4 3 indv.2 7 7 4 9"), header = TRUE) How would I change the column name of ONLY the first column, not the others? Surely I should not have to re-specify the names of ALL the columns -- e.g.,

Hi, What does your LLVM IR look like. Are you sure the loop hasnt been optimized away? Arushi On Sat, May 21, 2011 at 5:52 PM, Malveeka Tewari <mtewari at eng.ucsd.edu>wrote: > Hi > > I have the followed code for which I am writing a loop pass. > > int main() { > int i = 0; > for (i=0; i<20; i++) { > printf ("hello world %d\n", i); > }

Hi, I turn to you, the R Sages, once again for help. You've never let me down! (1) Please make the following toy files: x <- read.table(textConnection("var.1 var.2 var.3 var.1000 indv.1 1 5 9 7 indv.210000 2 9 3 8"), header = TRUE) y <- read.table(textConnection("var.3 var.1000"), header = TRUE) write.csv(x, file = "x.csv") write.csv(y, file =

I just had a quick play with gzip compression on a filesystem and the result was the machine grinding to a halt while copying some large (.wav) files to it from another filesystem in the same pool. The system became very unresponsive, taking several seconds to echo keystrokes. The box is a maxed out AMD QuadFX, so it should have plenty of grunt for this. Comments? Ian

Hello R listserve, I would appreciate someone's help with this problem. Consider the following toy dataset: x <- read.table(textConnection("worldclim.1 worldclim.2 cru.1 cru.2 indv.1 7 8 32 658 indv.2 7 7 39 422"), header = TRUE) How could I create a subset of the data based on the column prefix? For instance, let's say I wanted to subset only the columns with the